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Quantity Survey, Contracts & Tenders (October 2010)

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Total No. of Questions : 12] P1138 [Total No. of Pages :4 [3864] - 103 B.E. (Civil) QUANTITY SURVEY, CONTRACTS & TENDERS (2003 Course) Time : 4 Hours] [Max. Marks : 100 Instructions to the candidates: 1) Answer Q1 or Q2,Q3 or Q4,Q5 or Q6 from Section - I and Q7 or Q8,Q9 or Q10,Q11, or Q12 from Section - II. 2) Answers to the two Sections should be written in separate books. 3) Neat diagrams must be drawn wherever necessary. 4) Figures to the right indicate full marks. 5) Use of logarithmic tables slide rule, Mollier charts, electronic pocket calculator and steam tables is allowed. 6) Assume suitable data, if necessary. SECTION - I Q1) A square room of internal dimensions 3m 3m 3m has the following openings in it. a) b) c) d) e) Door D1 1.8 m 2.1 m, thickness of door frame 300 mm. Door D2 1.2m 2.1 m, thickness of door frame 100 mm. Exhaust fan opening 150 mm 150 mm. Window W1 2.3 m 1.5 m, thickness of window frame 50 mm. Window W2 1.5 m 1.5 m, thickness of window frame 50 mm. Wall thickness is 300 mm. Door D2 is centrally located in the thickness of wall. Window sill from inside is 150 mm. External plaster is 25 mm thick sand faced in C.M (1:3) whereas internal plaster is 19 mm thick in C.M (1:5) sunla finish. Slab thickness is 200 mm. Brickwork is in C.M (1:8) using I.S bricks. Assuming suitable additional data and applying rules of I.S 1200, work out i) ii) Item quantity for brickwork. Item quantity for external plaster. [4] [4] iii) Item quantity for internal plaster. [4] iv) Cost of bricks, cement and sand required to execute the above items of work. [6] P.T.O. OR Q2) An isolated trapezoidal column footing has the following dimensions:D = 500 mm, d = 200 mm, A1 = 2m 2m A2 = 800 mm 800 mm. Mix used is (1:1 1 : 3). 2 Reinforcement steel is 10mm , TOR at 160mm C-C bothways. Column size is (600mm 600mm). Determine. a) Item quantity for concrete using Prismoidal formula [3] b) % of steel reinforcement used. [3] c) Item quantity for formwork required for footing. [3] d) Bar bending schedule for steel reinforcement. [3] e) Cost of cement, sand, coarse aggregates and steel required to execute the above works. [6] Q3) a) Explain advantages of preparing an approximate estimate. [4] b) With examples, explain any 3 methods of preparing an approximate estimate. [12] OR Q4) a) b) c) d) Explain advantages of preparing a detailed estimate. [4] Differentiate between revised estimate and supplementary estimate with examples each. [4] Explain why and how contingencies and W.C. establishment costs are added at the end, while preparing a detailed estimate. [4] Explain correctly any 4 painting factors as per IS 1200, used for painting of doors and windows. [4] Q5) 10m3 of CCTW door frames are to be prepared and fixed in position, in brick masonary. Prepare a) b) c) Brief specification for BOQ. [2] [8] Detailed specification for execution and measurement. Item Rate per unit for door frames Assume correct, suitable data as required. [6] OR Q6) 10m3 of M (1:1:2) R.C.C without steel reinforcement is to be provided and laid for construction of slab. Prepare a) Brief specification for BOQ. [2] b) Detailed specification for execution and measurement. [8] c) Item rate per unit of R.C.C work. [6] [3864]-103 -2- SECTION - II Q7) a) b) c) d) Differentiate between cost, price and value with an example. Explain any 4 types of values with examples. Explain any one method of valuation in detail. Work out the present value of property based on following data:i) Monthly rent is Rs. 50,000/ii) Outgoings are at 40% iii) Interest on sinking fund investment is 4% iv) Interest on land investment is 8% v) Interest on capital investment is 10% vi) Total useful life - 75 years. vii) Future life from valuation data - 15 years. viii) Total present land worth = Rs. 30 lakhs. [3] [4] [4] [7] OR Q8) a) b) c) Explain any 2 methods of depreciation in brief. [6] Explain belting method of valuation with an example. [4] Work out value of property based on following data. [8] i) Original construction cost = Rs. 10 lakhs. ii) Depreciation of 90% is to be done using sinking fund method. iii) Total useful life :- 75 years. iv) Life consumed :- 40 years. v) Present land rate :- Rs 10,000/- per m2 vi) Land area :- 50m 40m. vii) Interest rate on sinking fund :- 5.5%. Q9) a) b) c) Explain 4 pre -qualifications in any tender with any example. Explain scrutiny of tender documents with examples. Explain 3 bid system with an example. [6] [6] [4] OR Q10)a) b) c) Differentiate between selective tendering and open tendering with proper examples. [6] Explain in brief any 4 important constituents of a tender document. [6] Explain front end loading with a proper example. [4] [3864]-103 -3- Q11)a) b) Explain any 6 important tender condition provisions made by the MOS & PI. [12] Explain in brief the FIDIC conditions of contract. [4] OR Q12)a) b) c) As an engineer incharge of works, suggest your action w.r.t. [9] i) Steel reinforcement in beam is exposed and corroded. ii) Internal plaster is not in perfect line and level. iii) Flooring is not in proper slope and water is getting stagnated. Explain void contract with an example. [3] Explain the various ways in which contractual disputes can be resolved.[4] kbkb [3864]-103 -4-

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Additional Info : 2003 Course
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