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Click question to answer it! To ask a question, go to the topic of your interest and click Q & A.| Q & A > ICSE Board Exam : Class X Solved Question Papers Class 10 Sample / Model Papers for Download - Previous Years 
Do we also need to remember the diagrams of manufacturing processes like Ostwald's, Contact process, Haber's process, etc?Asked by: skshooda |
| Q & A > ICSE Board Exam : Class X Solved Question Papers Class 10 Sample / Model Papers for Download - Previous Years 
WHO IS THE CONSTITUTIONAL HEAD OF THE STATE (Country)
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| Q & A > ICSE Board Exam : Class X Solved Question Papers Class 10 Sample / Model Papers for Download - Previous Years 
insists on....persists in
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| Q & A > ICSE Board Exam : Class X Solved Question Papers Class 10 Sample / Model Papers for Download - Previous Years 
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| Q & A > ICSE Board Exam : Class X Solved Question Papers Class 10 Sample / Model Papers for Download - Previous Years 
A note to all of the ICSE students:
Refer Children's academy prelims paper:
1. Keep in mind that you should never change the tense in your answer. For example: Engulfed - Devoured; Indicating - PoAsked by: anuakil |
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| Q & A > ICSE Board Exam : Class X Solved Question Papers Class 10 Sample / Model Papers for Download - Previous Years 
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| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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(a) End A is South pole, End B is North pole. (b) The compass needle will deflect with its North pole pointing towards the East. Reason: End B of the coil acts as a North pole, which repels the North pole of the compass needle and attracts its South pole. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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(a) The glass piece is not seen when the refractive index of the liquid becomes exactly equal to the refractive index of the glass piece at that particular temperature. (b) Refractive index depends on the wavelength (color) of light. Using monochromatic light ensures a complete match of refractive index, whereas white light would only match for one specific color. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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The sky would appear black. Reason: In space, there is no atmosphere or particles to scatter sunlight. Without scattering of light, no light reaches the observer's eyes from the empty space, making it appear black. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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No, it does not breach the law of conservation of energy. The mechanical energy that appears to be lost (5 J - 3.2 J = 1.8 J) is converted into other forms of energy, such as heat, due to friction or air resistance. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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Max PE = mgh = 0.1 * 10 * 5 = 5 J. Max KE = 1/2 mv^2 = 1/2 * 0.1 * 10^2 = 5 J. Since Max PE = Max KE, total mechanical energy is conserved, proving the path is devoid of friction. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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Setup for question 9. See next page for sub-questions. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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(i) Heat energy Q = 966 * 15 = 14490 J. (ii) Specific heat capacity c = 966 / 2.0 = 483 J kg^-1 K^-1. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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(a) At the same position as X. (b) Isotopes. (c) 80. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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(a) f_Y > f_X = f_Z = f_W. (b) Pendulums X and W. (c) Pendulums X and W have the same length as pendulum Z, so their natural frequencies are equal to the frequency of Z. This leads to resonance, causing them to vibrate with maximum amplitude. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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(a) The slope (gradient) of the graph (Load / Effort). (b) Class II lever (since MA = 50/25 = 2, which is > 1). (c) Wheelbarrow. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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Total R = 2V / 0.25A = 8 Ω. External R = 8 - 3 = 5 Ω. 6R / (6+R) = 5 => R = 30 Ω. Voltage across parallel combination = 0.25 * 5 = 1.25 V. Current in 6 Ω branch = 1.25 / 6 A. (a) PD across 4 Ω = (1.25/6) * 4 = 0.833 V. (b) PD across internal resistance = 0.25 * 3 = 0.75 V. (c) PD across R = 1.25 V. PD across 2 Ω = (1.25/6) * 2 = 0.417 V. (d) R = 30 Ω. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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[Diagram showing the ray PQ entering normally at BC, hitting AC, undergoing TIR (angle of incidence 60°), hitting AB at an angle of incidence of 30°, and refracting out of AB bending away from the normal.] ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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a) Stretch the thumb, forefinger, and middle finger of the right hand mutually perpendicular to each other. If the forefinger points in the direction of the magnetic field and the thumb points in the direction of motion of the conductor, then the middle finger points in the direction of the induced current. b) A step-up transformer is used to increase the voltage of an alternating current while decreasing the current. c) North polarity. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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Mass of water = 20 * 10^-3 * 10^3 = 20 kg. Work = mgh = 20 * 9.8 * 20 = 3920 J. (a) Ratio of work done = 1:1. (b) Power = Work / Time. Power ratio = (W/3) / (W/2) = 2:3. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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a) [Connect the middle terminal of the first switch to the live wire. Connect the middle terminal of the second switch to the bulb. Connect the other terminal of the bulb to the neutral wire. Connect the top terminals of both switches together, and bottom terminals together.] b) The top supply terminal connected to the switch should be marked L (Live). The bottom supply terminal connected directly to the bulb should be marked N (Neutral). ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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Direct sound distance = y - x. Time = 2s. (y - x) / 320 = 2 => y - x = 640. Echo distance = x + y. Time = 3s. (x + y) / 320 = 3 => x + y = 960. Adding equations: 2y = 1600 => y = 800 m. Subtracting: 2x = 320 => x = 160 m. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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a) A larger diameter provides a larger perpendicular distance from the axis of rotation, requiring less effort to produce the same turning effect. b) It is made thick and heavy to increase its heat capacity so that it retains heat for a longer time, and the weight helps in pressing clothes. c) Nuclear fusion requires extremely high temperatures to overcome the electrostatic repulsion between positively charged nuclei, hence it is called a thermonuclear reaction. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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(a) Gamma rays, (b) Infrared radiation, (c) Gamma rays. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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It is used in slide projectors or cinema projectors to obtain a magnified, real image on a screen. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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[Ray diagram showing one ray parallel to the principal axis passing through F on the other side, and another ray passing through the optical center undeviated. The rays meet beyond 2F.] Characteristics: 1. Real and inverted. 2. Magnified. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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Pitch is the characteristic of sound by which an acute (or shrill) note can be distinguished from a grave (or flat) note of the same loudness. It depends primarily on the frequency of the sound wave. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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(a) Quality or Timbre. (b) Loudness is proportional to the square of the amplitude. L_F / L_P = (A_F / A_P)^2 => 4 = (A_F / A_P)^2 => A_F / A_P = 2/1. Ratio is 2:1. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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(a) [Diagram of a block and tackle system with 5 pulleys: 3 in the fixed block and 2 in the movable block. The string is tied to the movable block, goes around the pulleys, and effort E is applied downwards. Load L is attached to the movable block.] (b) Mass = 100 kg. Potential energy gained = mgh = 100 * 10 * 5 = 5000 J. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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If reversed, it creates a clockwise moment. Total moment = 120 + 120 = 240 gf cm. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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Anticlockwise moment = 20 * 6 = 120 gf cm. Clockwise moment = 12 * 10 = 120 gf cm. Yes, the rod is in equilibrium. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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The 12 gf force. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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Setup for question vii. See next page for sub-questions. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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(a) Class II lever. Fulcrum is at one end, Effort is at the other end, and Load is in the middle (F - L - E). (b) Class III lever. Fulcrum is at one end, Load is at the other end, and Effort is in the middle (F - E - L). ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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Water has a high specific heat capacity. It can release a large amount of heat energy as it cools down without its temperature dropping significantly. This prevents the temperature of the surrounding air and the crops from falling below freezing point, protecting the crops from frost damage. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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(a) R1 and R2 are in parallel: R12 = (10*40)/(10+40) = 8 Ω. R3, R4, R5 are in parallel: 1/R345 = 1/30 + 1/20 + 1/60 = 6/60 => R345 = 10 Ω. Total resistance = 8 + 10 = 18 Ω. (b) Reading of ammeter A = V / R_total = 1.8 / 18 = 0.1 A. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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(a) 24_11 Na -> 24_12 Mg + 0_-1 e + Î½Ì (b) Isobar. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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(a) East. (b) Right-Hand Thumb Rule. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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[Ray diagram showing light from the top of the plant bending towards the normal as it enters the water. When the refracted rays are extended backwards, they meet at a point higher than the actual top of the plant, making it appear taller to the fish.] ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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Taller. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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Heat lost by water = m_w * c_w * ÎT = 85 * 4.2 * (30 - 5) = 8925 J. Heat gained by ice = m_ice * L + m_ice * c_w * (5 - 0) = m_ice * 336 + m_ice * 4.2 * 5 = 357 * m_ice. Equating heat lost and gained: 357 * m_ice = 8925 => m_ice = 25 g. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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Ultrasonic waves can penetrate human tissues and reflect back from the boundaries of different organs without causing harmful ionization. They also have a short wavelength, allowing them to travel in straight lines without much diffraction, providing clear images. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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Ultrasonic waves (Ultrasound). ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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(a) force (b) microwaves (c) remains same (d) one-fourth (e) mirror isobars (f) elastic potential energy ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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c) Quiet sound waves have a large amplitude. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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d) both (a) and (b) ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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d) assertion is true but reason is false. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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d) assertion is true but reason is false. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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b) â i >â r ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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a) 9 cm ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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b) 2 ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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b) one place higher ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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c) current through 2Ω = current through 5Ω ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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b) Current starts flowing through AC wire concealed in the adjacent wall. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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(a) Substance A will experience a smaller temperature change than substance B. ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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a) Move away from the slab ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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c) 2000 J ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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d) 300 ai_model |
| ICSE Class X Prelims 2026 : Physics (GEMS Modern Academy, Dubai) | |
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d) the body will have rotational as well as translational motion. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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PQ is tangent, so â BAC = â CBQ = 40° (alternate segment). x = 40°. AB = AC => â ABC = â ACB = (180°-40°)/2 = 70°. y = 2 * â BAC = 80°. In ÎOBC, OB=OC => â OBC = (180°-80°)/2 = 50°. w = â OBA = â ABC - â OBC = 70° - 50° = 20°. Angles in same segment: z = â BDC = â BAC = 40°. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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(a) P(one girl) = 165/300 = 11/20. (b) P(one or more girl) = (165+95)/300 = 260/300 = 13/15. (c) P(no boy) = P(2 girls) = 95/300 = 19/60. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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(a) x/a = 5b/(a-b). (b) Using componendo and dividendo: (x+a)/(x-a) = (5b + a - b) / (5b - a + b) = (a + 4b) / (6b - a). ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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(a) l = â(7² + 24²) = 25 cm. Assuming full sphere on top: TSA = 4Ïr² + 2Ïrh + Ïrl = Ïr(4r + 2h + l) = (22/7)7(28 + 48 + 25) = 22 * 101 = 2222 cm². (b) Cost = 2222 * 0.50 = â¹ 1111. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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(a) A(4, 8), B(-1, 2), C(6, 2). (b) Midpoint of AC = ((4+6)/2, (8+2)/2) = (5, 5). Slope of AB = (8-2)/(4-(-1)) = 6/5. Equation: y - 5 = (6/5)(x - 5) => 5y - 25 = 6x - 30 => 6x - 5y - 5 = 0. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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-1 < (2x-3)/3 - x/5 ⤠1. Multiply by 15: -15 < 5(2x-3) - 3x ⤠15 => -15 < 10x - 15 - 3x ⤠15 => -15 < 7x - 15 ⤠15. Add 15: 0 < 7x ⤠30 => 0 < x ⤠30/7. Solution set: {x : 0 < x ⤠30/7, x â R}. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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(a) ODEC: O(0,0), D(2,-3), E(5,-3), C(3,0). (b) OIJH: O(0,0), I(-2,-3), J(-5,-3), H(-3,0). (c) OFGH: O(0,0), F(-2,3), G(-5,3), H(-3,0). ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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ar³ = 16; arⶠ= 128. Dividing gives r³ = 8 => r = 2. a(2)³ = 16 => 8a = 16 => a = 2. (a) Common ratio = 2. (b) First term = 2. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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(a) Vinay's interest = 300 * (24*25)/(2*12) * 8/100 = 600. (b) Rohit's interest = 600 + 800 = 1400. Let Rohit's deposit be P. 1400 = P * (24*25)/(2*12) * 8/100 = 2P => P = 700. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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(a) Median (N/2 = 50) â 56 kg. (b) Students ⥠60 kg = 100 - 70 = 30. Percentage = 30%. (c) Top 20% means above 80th percentile. Weight at cf=80 is â 63 kg. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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BC = 100 * tan(31°) = 100 * 0.6009 = 60.09 m. BD = 100 * tan(33°) = 100 * 0.6494 = 64.94 m. Height of flagpole CD = BD - BC = 64.94 - 60.09 = 4.85 m â 5 m. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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x - y = 5 => x = y + 5. 1/x + 1/y = 3/10 => 1/(y+5) + 1/y = 3/10 => (2y+5)/(y²+5y) = 3/10. 3y² + 15y = 20y + 50 => 3y² - 5y - 50 = 0 => (y-5)(3y+10) = 0. y = 5 (natural number). x = 10. Numbers are 10 and 5. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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A = 28, h = 8. ui = (xi - 28)/8. Σfi = 100. Σfiui = 10(-3) + 20(-2) + 14(-1) + 16(0) + 18(1) + 22(2) = -30 - 40 - 14 + 0 + 18 + 44 = -22. Mean = 28 + (-22/100)*8 = 28 - 1.76 = 26.24. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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(a) MV = 100 + 25 = 125. Investment = 120 * 125 = 15000. (b) 1080 = 120 * (R/100) * 100 => 120R = 1080 => R = 9%. (c) Rate of return = (1080 / 15000) * 100 = 7.2%. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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x² - 4x + 4 - 5x - 3 = 0 => x² - 9x + 1 = 0. x = (9 ± â(81 - 4))/2 = (9 ± â77)/2. â77 â 8.775. x = (9 + 8.775)/2 = 8.8875 â 8.89; x = (9 - 8.775)/2 = 0.1125 â 0.113. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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(a) Let ratio be k:1. y-coord of P = (10k - 2)/(k+1) = 0 => k = 1/5. Ratio is 1:5. (b) x-coord of P = (1(2) + 5(-10))/6 = -48/6 = -8. P is (-8, 0). ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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(a) Students 150 cm and above = 9 (150-160) + 4 (160-170) = 13. (b) Modal class is 130-140. Mode = 130 + ((14-9)/(28-9-12)) * 10 = 130 + (5/7)*10 â 137.14 cm. (c) Total students = 6 + 2 + 9 + 14 + 12 + 9 + 4 = 56. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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(a) ÎADE ~ ÎABC (AA similarity). DE/BC = AD/AB = 2/(2+3) = 2/5. (b) ÎDFE ~ ÎCFB (AA similarity: vertically opposite and alternate interior angles). (c) Area(ÎDFE)/Area(ÎCFB) = (DE/BC)² = 4/25. 16/Area(ÎCFB) = 4/25 => Area(ÎCFB) = 100 sq units. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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(a) Discounted price = 24000 - 10% of 24000 = 24000 - 2400 = 21600. (b) Amount paid = 21600 + 12% of 21600 = 21600 + 2592 = 24192. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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LHS = (1/cosθ - cosθ)(1/sinθ - sinθ) = ((1-cos²θ)/cosθ) * ((1-sin²θ)/sinθ) = (sin²θ/cosθ) * (cos²θ/sinθ) = sinθcosθ = RHS. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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(a) Draw BC = 5 cm, arcs of 5 cm from B and C to find A. Join AB, AC. (b) Draw perpendicular bisectors of any two sides to find circumcentre O. Draw circle with centre O and radius OA. (c) Draw angle bisector of â B. Mark intersection with circumcircle as D. (d) ABCD is a kite. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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r = 3.5 cm. h_cyl = 7 cm, h_cone = 7 cm. (a) Minimum height = r_hemi + h_cyl + h_cone = 3.5 + 7 + 7 = 17.5 cm. (b) Volume = (2/3)Ïr³ + Ïr²h_cyl = Ïr²(2r/3 + h_cyl) = (22/7) * 12.25 * (7/3 + 7) = 38.5 * (28/3) = 359.33 cm³. Nearest whole number = 359 cm³. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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(a) P(-1) = 6 => k(-1)³ + 3(-1)² - 11(-1) - 6 = 6 => -k + 3 + 11 - 6 = 6 => k = 2. (b) 2x³ + 3x² - 11x - 6. P(2) = 0, so (x-2) is a factor. Dividing gives (x-2)(2x² + 7x + 3) = (x-2)(x+3)(2x+1). ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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DE is tangent at B, so â OBE = 90°. In right ÎOBD, â BOD = 180° - 90° - 32° = 58°. x = â AOB = 180° - 58° = 122° (linear pair). In ÎOAB, OA = OB, so 2y + 122° = 180° => 2y = 58° => y = 29°. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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AB = [[3(-1)+1(3), 3a-5], [5(-1)+3(3), 5a-15]] = [[0, 3a-5], [4, 5a-15]]. Equating to given AB: b = 0. 3a - 5 = 7 => 3a = 12 => a = 4. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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(a) a + 3d = 60; a + 6d = 114. Subtracting gives 3d = 54 => d = 18. a + 3(18) = 60 => a = 6. (b) S10 = (10/2)[2(6) + 9(18)] = 5[12 + 162] = 5 * 174 = 870. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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a = 6, r = -2. T9 = a*r^8 = 6*(-2)^8 = 6*256, which is positive. Both A and R are true, and R explains A. Answer: (c) Both (A) and (R) are true and (R) is the correct explanation of (A). ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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Matrix A is 2x2 and Matrix B is 1x2. The number of columns in A (2) does not equal the number of rows in B (1), so the product AB is not possible. Answer: (d) product AB is not possible ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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In a right-angled triangle, the midpoint of the hypotenuse is equidistant from all three vertices. Midpoint of AB = ((0+2x)/2, (2y+0)/2) = (x, y). Answer: (a) (x, y) ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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Let P(x) = x³ + 7x² + 3x + 2 + k. For it to be divisible by (x+2), P(-2) = 0. (-2)³ + 7(-2)² + 3(-2) + 2 + k = 0 -8 + 28 - 6 + 2 + k = 0 => 16 + k = 0 => k = -16. Answer: (b) -16 ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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The ratio of corresponding altitudes of similar triangles is the square root of the ratio of their areas. Ratio = â9 : â64 = 3 : 8. Answer: (a) 3 : 8 ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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Assertion (A) is false because the probability of getting a number greater than 6 on a standard die is 0. Reason (R) is true. Answer: (b) (A) is false and (R) is true. ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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Discriminant Π= (-6)² - 4(3)(-3) = 36 + 36 = 72. Since Π> 0 and not a perfect square, the roots are real, distinct and irrational. Answer: (c) real, distinct and irrational ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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Exterior angle of a cyclic quadrilateral is equal to the interior opposite angle. â ABC = â CDE = 65°. Angle at the centre is twice the angle at the circumference: x = 2 * 65° = 130°. Answer: (d) 130° ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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4ÏR² = 3Ïr² R²/r² = 3/4 => R/r = â3/2 Answer: (c) â3 : 2 ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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Dividend on 1 share = 9% of 20 = 1.8 Let market value be x. Return = 12% of x = 0.12x 0.12x = 1.8 => x = 15 Answer: (b) â¹ 15 ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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A line parallel to the x-axis has the equation y = c. Since the y-intercept is 6, the equation is y = 6. Answer: (a) y = 6 ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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Amount invested by A = 1500 * 12 = 18000 Amount invested by B = 1200 * 15 = 18000 Answer: (d) Both A and B are same (â¹ 18,000) ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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The mode is the most frequent value in the dataset. 9 appears three times. Answer: (d) 9 ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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Rate of GST = (2160 / 12000) * 100 = 18% Answer: (c) 18% ai_model |
| ICSE Class X Board Exam 2026 : Mathematics | |
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(x+3)/1 = (3x-7)/-5 -5x - 15 = 3x - 7 -8x = 8 => x = -1 Answer: (a) -1 ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) A spanner with a long handle provides a larger perpendicular distance from the axis of rotation (the nut) to the point of application of force. Since torque (the turning effect) is the product of force and perpendicular distance, a larger distance allows the required torque to be generated with a much smaller applied force, making it easier to loosen the nut. (b) To loosen a standard right-handed thread nut, the spanner must be rotated in the anti-clockwise direction when looking from above. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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Let the distance of person A from the cliff be x, and the distance of person B from the cliff be y. Since B is behind A, y > x. The first sound heard by B travels directly from A to B. The distance is (y - x). Time t1 = 2 s. Distance = speed * time => y - x = 320 * 2 = 640 m. (Equation 1) The second sound travels from A to the cliff and reflects back to B. The total distance is x + y. Time t2 = 3 s. Distance = speed * time => x + y = 320 * 3 = 960 m. (Equation 2) Adding Eq 1 and Eq 2: 2y = 1600 => y = 800 m. Subtracting Eq 1 from Eq 2: 2x = 320 => x = 160 m. Therefore, x = 160 m and y = 800 m. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) The phenomenon responsible for the formation of this image is Total Internal Reflection. (b) Total internal reflection is the phenomenon that occurs when a ray of light traveling from an optically denser medium to an optically rarer medium strikes the boundary at an angle of incidence greater than the critical angle for that pair of media, causing the light to be completely reflected back into the denser medium. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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Both person P and person Q do the exact same amount of work against the gravitational force. Work done against gravity is calculated as W = mgh, where 'm' is mass, 'g' is acceleration due to gravity, and 'h' is the vertical height. Since both persons have the same mass and are displaced by the same vertical height (from ground to first floor), the work done is identical. The fact that Q runs means Q exerts more power (doing the work in less time), but the total energy expended against gravity remains the same. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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The 0 to 50 cm part will weigh more than 25 gf. Since the meter scale balances at the 40 cm mark, its center of gravity (CG) is located there. This indicates that the mass is not uniformly distributed and the scale is heavier towards the 0 cm end. If cut at the 50 cm mark, the 0-50 cm section contains the CG of the entire ruler. To balance at 40 cm, the moment of the heavier 0-50 cm part must equal the moment of the lighter 50-100 cm part. Therefore, the 0-50 cm part must constitute more than half of the total 50 gf weight. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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An MCB (Miniature Circuit Breaker) is a better safety device than a fuse for several reasons: 1. It operates much faster to break the circuit in the event of a short circuit or overload. 2. It is highly convenient; after tripping, it can simply be switched back on to restore power, whereas a blown fuse wire must be physically replaced. 3. It is generally more sensitive to overcurrents than a standard fuse. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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[A neat labelled diagram of an A.C. generator should be drawn. It must include a rectangular armature coil placed between the North and South poles of a strong permanent magnet. The two ends of the coil should be connected to two separate slip rings (R1 and R2). Two stationary carbon brushes (B1 and B2) should be shown pressing against the slip rings, connecting the rotating coil to an external circuit containing a load or galvanometer.] ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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To freeze water at 0 °C into ice, it must release its latent heat of fusion. Heat transfer only occurs when there is a temperature difference between two bodies. Since both the water and the added ice are at the same temperature (0 °C), no heat can flow from the water to the ice. Consequently, the water cannot lose the required latent heat and will not freeze. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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The assertion is true; nuclear fusion produces significantly more energy per unit mass of reactants than nuclear fission. The reason is also true; achieving controlled fusion is technically much more difficult due to the extreme temperatures and pressures required. However, the technical difficulty is not the scientific explanation for why fusion produces more energy (which is due to a larger mass defect). Therefore, both are true, but the reason is not the correct explanation. Option (b) is correct. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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If electrons are moving towards the west, the conventional current is flowing towards the east. Applying the Right Hand Thumb Rule, if you point your thumb east along the wire, your fingers will curl such that above the wire, the magnetic field points towards the north. Therefore, the north pole of the compass needle placed above the wire will point north. Option (c) is correct. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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The direction of induced current in a conductor moving in a magnetic field is determined by Fleming's Right Hand Rule. Option (d) is correct. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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A double pole switch is designed to simultaneously disconnect both the Live wire and the Neutral wire from the main supply, ensuring complete isolation of the circuit for safety. Option (d) is correct. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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The assertion is false because a machine with a high mechanical advantage might also have a very high velocity ratio (due to many moving parts, friction, or weight), which can result in a low efficiency (Efficiency = MA / VR). The reason is true, as efficiency mathematically depends on both mechanical advantage and velocity ratio. Therefore, option (d) is correct. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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In forced vibrations, the body is compelled to vibrate with the frequency of the applied external periodic force, regardless of its own natural frequency. Therefore, the frequency of the vibrating body will be 450 Hz. Option (c) is correct. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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The circuit consists of a 3 Ω resistor in series with a parallel combination of a 2 Ω and an 8 Ω resistor. The equivalent resistance of the parallel part is Rp = (2 * 8) / (2 + 8) = 16 / 10 = 1.6 Ω. The total external resistance is R_ext = 3 + 1.6 = 4.6 Ω. The total resistance of the circuit including internal resistance is R_total = 4.6 + 0.4 = 5.0 Ω. The total current I drawn from the 5V battery is I = V / R_total = 5 / 5.0 = 1 A. Option (a) is correct. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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When light suffers dispersion through a prism, the angle of deviation is inversely proportional to the wavelength of the light. Among the given colors (red, indigo, orange, blue), indigo has the shortest wavelength and will therefore be deviated the most. Option (a) is correct. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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The value â i - â r represents the angle of deviation. The deviation is maximum for the color with the highest refractive index, which corresponds to the shortest wavelength. Among red, blue, green, and yellow, blue has the shortest wavelength and will therefore bend the most towards the normal, resulting in the greatest value for â i - â r. Option (b) is correct. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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Ray A will suffer total internal reflection. It enters the prism normally through the hypotenuse and strikes the vertical face. The angle of the prism at the top is 60° (since the other angles are 90° and 30°). Geometry shows the angle of incidence on the vertical face is 60°. Since 60° is greater than the critical angle of 42°, Ray A undergoes total internal reflection. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) Since the image is formed on a screen, it is a real image. Only a convex lens can form a real image. (b) Focal length f = +20 cm = +0.2 m. Power P = 1/f = 1/0.2 = +5 D. (c) For a real image, magnification m = -4. Since m = v/u, we have v = -4u. Using the lens formula 1/v - 1/u = 1/f: 1/(-4u) - 1/u = 1/20 => -5/(4u) = 1/20 => 4u = -100 => u = -25 cm. The object is placed 25 cm in front of the lens. The image position v = -4(-25) = +100 cm. The image is formed 100 cm behind the lens. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) At the angle of minimum deviation, the angle of incidence (i) is equal to the angle of emergence (e). The formula is δmin = 2i - A. Given δmin = 40° and A = 60°, we have 40° = 2i - 60° => 2i = 100° => i = 50°. Therefore, both the angle of incidence and the angle of emergence are 50°. (b) As the angle of incidence increases, the angle of deviation first decreases, reaches a minimum value, and then increases. An increase in the refractive index of the prism material causes the angle of deviation to increase. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) Work done by the pump = mgh = 500 kg * 10 m/s^2 * 80 m = 400,000 J = 400 kJ. (b) Power supplied by the pump (useful output power) = Work done / time = 400,000 J / 10 s = 40,000 W = 40 kW. (c) Power rating of the pump (input power) = Output power / Efficiency = 40,000 W / 0.40 = 100,000 W = 100 kW. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) For a block and tackle system with 9 pulleys to have maximum mechanical advantage, the lower block should be as light as possible. Therefore, the upper fixed block will have 5 pulleys and the lower movable block will have 4 pulleys. (b) The Velocity Ratio (VR) is equal to the total number of pulleys, so VR = 9. The energy wasted is 10%, so the efficiency η = 90% = 0.9. The Mechanical Advantage (MA) = η * VR = 0.9 * 9 = 8.1. (c) Load (L) = 810 kgf. Effort (E) = L / MA = 810 / 8.1 = 100 kgf. The effort needed is 100 kgf. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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Let the ball of mass m be thrown upwards with initial velocity u. Let the maximum height reached at C be h. At position A (ground): Height = 0, Velocity = u. Potential Energy (PE_A) = 0 Kinetic Energy (KE_A) = 1/2 * m * u^2 Total Energy (E_A) = PE_A + KE_A = 1/2 * m * u^2 At position C (maximum height): Velocity = 0. From v^2 = u^2 - 2gh, 0 = u^2 - 2gh => h = u^2 / 2g. PE_C = mgh = mg(u^2 / 2g) = 1/2 * m * u^2 KE_C = 0 Total Energy (E_C) = PE_C + KE_C = 1/2 * m * u^2 At position B (height x): Let velocity be v. From kinematics, v^2 = u^2 - 2gx. PE_B = mgx KE_B = 1/2 * m * v^2 = 1/2 * m * (u^2 - 2gx) = 1/2 * m * u^2 - mgx Total Energy (E_B) = PE_B + KE_B = mgx + 1/2 * m * u^2 - mgx = 1/2 * m * u^2 Since E_A = E_B = E_C = 1/2 * m * u^2, the total mechanical energy remains constant, proving the law of conservation of energy. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) Applying Fleming's Left Hand Rule (magnetic field outwards, force to the right), the particles must be positively charged moving upwards. Therefore, the radiation deviated towards the right is Alpha (α) particles. The radiation that goes undeviated is Gamma (γ) rays, as they carry no charge. (b) A thick-walled lead container is used because lead is a dense material that effectively absorbs radioactive emissions. The container absorbs radiations emitted in all other directions, allowing only a narrow, collimated beam to escape through the small opening. (c) The radiation deviated towards the right (Alpha particles) has the highest ionizing power among the three types of radioactive emissions. Its ionizing power is roughly 100 times greater than that of Beta particles and about 10,000 times greater than that of Gamma rays. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) During a short circuit, an excessive amount of current flows through the circuit. This causes the fuse wire to heat up rapidly, melt, and break the circuit. (b) No, current is no longer flowing through the kettle because the melting of the fuse has broken the electrical circuit. (c) No, it is not safe to touch the kettle. Because the fuse was incorrectly placed in the neutral wire, breaking it does not disconnect the appliance from the high-voltage live wire. The kettle remains at a high potential, and touching its metallic body could provide a path to the ground, resulting in a severe electric shock. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) A typical nuclear fusion reaction is the fusion of deuterium and tritium: ^2_1H + ^3_1H -> ^4_2He + ^1_0n + 17.6 MeV The energy released is approximately 17.6 MeV. (b) The cause of the energy released is the mass defect. The total mass of the product nuclei is slightly less than the total mass of the reacting nuclei. This 'lost' mass (Îm) is converted into a tremendous amount of energy according to Einstein's mass-energy equivalence principle, E = Îmc^2. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) The Principle of Method of Mixtures states that when a hot body is mixed with a cold body in a perfectly insulated system, the total heat lost by the hot body is equal to the total heat gained by the cold body, until both reach a common equilibrium temperature. (b) Let the final temperature be T °C. Mass of ice, m_i = 40 g = 0.04 kg. Initial temp = -40 °C. Mass of water, m_w = 200 g = 0.2 kg. Initial temp = 50 °C. Heat gained by ice to reach 0 °C: Q1 = m_i * c_i * ÎT = 0.04 * 2100 * 40 = 3360 J. Heat gained by ice to melt at 0 °C: Q2 = m_i * L_f = 0.04 * 336000 = 13440 J. Heat gained by melted ice to reach T °C: Q3 = m_i * c_w * (T - 0) = 0.04 * 4200 * T = 168T J. Total heat gained = 3360 + 13440 + 168T = 16800 + 168T J. Heat lost by water: Q4 = m_w * c_w * (50 - T) = 0.2 * 4200 * (50 - T) = 840(50 - T) = 42000 - 840T J. By the principle of mixtures: Heat gained = Heat lost 16800 + 168T = 42000 - 840T 1008T = 25200 T = 25 °C. The final temperature of the water is 25 °C. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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Based on the standard pin configuration of a three-pin socket (looking at the face): the top thick pin is Earth, the bottom right pin is Live, and the bottom left pin is Neutral. In the given diagram, A is the top pin (Earth), B is the bottom left pin (Neutral), and C is the bottom right pin (Live). According to standard color coding: Earth is Green, Neutral is Light Blue, and Live is Brown. Matching: A (Earth) - (b) Green B (Neutral) - (c) Light Blue C (Live) - (a) Brown ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) Substance B has a high specific heat capacity. Since it experiences a smaller rise in temperature for the same amount of heat supplied, it requires more heat energy per unit mass to raise its temperature. (b) Substance A is more conducting. In typical physics contexts, materials that heat up rapidly (low specific heat capacity, like metals) are also good conductors of heat. (c) Substance A should be used to make a calorimeter. Calorimeters are constructed from materials with low specific heat capacity (like copper) so that they absorb a minimal amount of heat from the substances being mixed inside them. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) A transformer operates on the principle of electromagnetic induction, which requires a continuously changing magnetic flux to induce an electromotive force (EMF) in the secondary coil. A DC source provides a steady, constant current, which creates a constant magnetic field. Since there is no change in magnetic flux, no EMF is induced, and the transformer cannot function. (b) One energy loss in the core is Eddy current loss. To reduce this loss, the core is made of thin laminated sheets of soft iron instead of a solid block. These laminations are insulated from each other, which increases the electrical resistance of the core and significantly minimizes the magnitude of the induced eddy currents. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) The periodic vibration of the pendulum is caused by the restoring force, which is the component of the bob's weight acting tangentially to the circular arc of its motion (mg sin θ). (b) Yes, the frequency of vibration remains constant with time, as it depends only on the length of the pendulum and the acceleration due to gravity. (c) No, the amplitude of vibration does not remain constant. It gradually decreases with time due to the damping effects of air resistance and friction at the point of suspension. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) According to Fleming's Left Hand Rule, the force on arm AB (current upwards, magnetic field right) is directed inwards (into the plane of the paper). The force on arm CD (current downwards, magnetic field right) is directed outwards (out of the plane of the paper). (b) These two equal and opposite parallel forces acting along different lines of action form a couple. This couple exerts a torque on the coil, causing it to rotate in a clockwise direction (when viewed from above). (c) The coil would ultimately come to rest in the vertical position, where the plane of the coil is perpendicular to the magnetic field, as the torque becomes zero in this position. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) Yes, the notes will differ in quality (timbre). Even though the guitars are identical and the notes have the same loudness and pitch, different players will pluck the strings differently. This excites different sets of overtones (harmonics) with varying relative intensities. The resulting waveform of the sound, which determines its quality, will therefore be different. (b) Two ways to increase the pitch of a stringed musical instrument are: 1. By increasing the tension in the string. 2. By decreasing the vibrating length of the string. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) Ultraviolet (UV) radiation. (b) Its wavelength range is approximately 10 nm to 400 nm (or 100 Ã to 4000 Ã ). (c) The presence of ultraviolet radiation can be detected using a photographic plate, as it strongly affects photographic emulsions, or by observing the fluorescence it induces in certain materials like zinc sulfide. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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(a) When nucleus X emits an alpha particle, its mass number decreases by 4 and atomic number decreases by 2. The subsequent emission of two beta particles increases the atomic number by 2 (back to its original value) while the mass number remains unchanged. The gamma emission does not affect either number. Therefore, nucleus Y has the same atomic number as X but a mass number that is 4 less. This means X and Y are isotopes. (b) Beta particles are widely used in industry for thickness gauging of materials such as paper, plastic films, and aluminum foils. They are also used in medical applications, such as radiation therapy for treating certain superficial cancers. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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The human eye lens is adapted to focus light entering from air, which has a refractive index of approximately 1. When submerged in water (refractive index ~1.33), the difference in refractive index between the surrounding medium and the eye lens decreases significantly. This reduces the converging power of the eye lens, causing its focal length to increase. As a result, the images of objects are formed behind the retina, leading to blurred vision. Wearing goggles introduces a layer of air in front of the eyes, restoring the normal refractive index difference and allowing the eye lens to focus light properly onto the retina. ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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decreases ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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second ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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220 V ai_model |
| ICSE Class X Prelims 2026 : Physics (St. Lukes Day School, Naihati, North 24 Parganas) | |
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80 dB ai_model |
| ICSE Class X Prelims 2026 : Physics (Universal High School, Dahisar East, Mumbai) | |
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c 90° The torque on the coil of a DC motor is proportional to the sine of the angle between the magnetic field and the normal to the coil. Maximum torque is experienced when this angle is 90°, which occurs when the coil is parallel to the magnetic field lines. ai_gemini |
| ICSE Class X Prelims 2026 : Physics (The Assembly of God Church School (AGCSS), Sodepur) | |
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(a) 4 The efficiency of a lever is defined as the ratio of its mechanical advantage to its velocity ratio. Mathematically, efficiency = (Mechanical Advantage) / (Velocity Ratio). Given that the mechanical advantage is 4 and the efficiency is 2, we can rearrange the formula to find the velocity ratio: Velocity Ratio = Mechanical Advantage / Efficiency = 4 / 2 = 2. Wait, it seems like the efficiency is greater than 1. Let me recheck the calculation. In fact, Efficiency = (Actual Mechanical Advantage) / (Ideal Mechanical Advantage). The velocity ratio is equal to the ideal mechanical advantage. So, Efficiency = Mechanical Advantage / Velocity Ratio. Therefore, Velocity Ratio = Mechanical Advantage / Efficiency. Given Mechanical Advantage = 4 and Efficiency = 2, Velocity Ratio = 4 / 2 = 2. Let me recheck the question. "If the mechanical advantage of a lever is 4 and the efficiency of the system is 2". An efficiency of 2 means 200%, which is not possible for a simple machine as it would violate the law of conservation of energy. However, if we interpret "efficiency of the system is 2" as a typo and assume it should be a value less than or equal to 1, or if the question implies something else by "efficiency of the system is 2", then the calculation would change. Let's assume there's a misunderstanding in the question statement or the options provided. If we assume the velocity ratio is 4 and efficiency is 2, then mechanical advantage would be 8, which is not given. Let's consider the possibility that the question meant "the velocity ratio is 4 and the efficiency is 2". Then the mechanical advantage would be 8. Let's assume the question meant "the mechanical advantage is 2 and the efficiency is 4". Then the velocity ratio would be 2/4 = 0.5. Let's assume the question meant "the velocity ratio is 2 and the efficiency is 4". Then the mechanical advantage would be 8. Let's reconsider the original formula and the provided options. Efficiency = Mechanical Advantage / Velocity Ratio Given: Mechanical Advantage = 4, Efficiency = 2 Velocity Ratio = Mechanical Advantage / Efficiency = 4 / 2 = 2. This result (2) is present as option (b). However, if the question meant the efficiency is actually a percentage. For example, if efficiency is 20%, then efficiency = 0.2. Velocity Ratio = Mechanical Advantage / Efficiency = 4 / 0.2 = 20. This is not an option. Let's check the options provided in relation to the formula. If Velocity Ratio is 4 (option a), then Efficiency = 4 / 4 = 1 (or 100%). If Velocity Ratio is 2 (option b), then Efficiency = 4 / 2 = 2 (or 200%). If Velocity Ratio is 6 (option c), then Efficiency = 4 / 6 = 2/3 (or 66.7%). If Velocity Ratio is 9 (option d), then Efficiency = 4 / 9 = 0.444 (or 44.4%). Given the problem statement "efficiency of the system is 2", and the options, it is highly likely that the question is flawed, as efficiency cannot be greater than 1. However, if we must choose an answer based on the provided numbers and formula, and assume the question implicitly means something that leads to one of the options, let's re-examine. Let's assume the question meant to ask for something else, or there is a fundamental misunderstanding of the terms. If we reverse the formula: Mechanical Advantage = Efficiency * Velocity Ratio. If Velocity Ratio = 4, then MA = 2 * 4 = 8. If Velocity Ratio = 2, then MA = 2 * 2 = 4. This matches the given Mechanical Advantage. If Velocity Ratio = 6, then MA = 2 * 6 = 12. If Velocity Ratio = 9, then MA = 2 * 9 = 18. So, if we assume the formula is MA = Efficiency * Velocity Ratio, and the given MA is 4 and the given "efficiency" is 2, then Velocity Ratio would be 4 / 2 = 2. This corresponds to option (b). However, the standard formula is Efficiency = MA / VR. Let's consider if the question meant "Ideal Mechanical Advantage is 4" and "Actual Mechanical Advantage is 2". Then, Efficiency = Actual MA / Ideal MA = 2 / 4 = 0.5. And Velocity Ratio = Ideal MA = 4. This is option (a). Let's consider if the question meant "Velocity Ratio is 4" and "Actual Mechanical Advantage is 2". Then, Efficiency = Actual MA / Velocity Ratio = 2 / 4 = 0.5. This gives us the efficiency but not the velocity ratio. Given the way the question is phrased "If the mechanical advantage of a lever is 4 and the efficiency of the system is 2. The velocity ratio of the system is", and the options, the most direct interpretation using the formula Efficiency = Mechanical Advantage / Velocity Ratio is: Velocity Ratio = Mechanical Advantage / Efficiency. If MA = 4 and Efficiency = 2, then VR = 4 / 2 = 2. This is option (b). However, an efficiency of 2 is unphysical. Let's assume the question meant: Mechanical Advantage = 4, and Velocity Ratio = X, Efficiency = 2. Then 2 = 4 / X, so X = 4 / 2 = 2. Option (b). Let's assume the question meant: Velocity Ratio = 4, and Mechanical Advantage = X, Efficiency = 2. Then 2 = X / 4, so X = 8. Not an option. Let's assume the question meant: Velocity Ratio = 4, and Efficiency = X, Mechanical Advantage = 2. Then X = 2 / 4 = 0.5. Given the choices, and the wording, if we are forced to use the provided numbers as they are, and the standard formula, then option (b) is derived. However, the premise of efficiency being 2 is flawed. Let's re-examine the provided options and the possibility of a typo in the question. If MA = 4 and VR = 4 (option a), then Efficiency = 4/4 = 1. If MA = 4 and VR = 2 (option b), then Efficiency = 4/2 = 2. If MA = 4 and VR = 6 (option c), then Efficiency = 4/6 = 2/3. If MA = 4 and VR = 9 (option d), then Efficiency = 4/9. The question states "efficiency of the system is 2". If we take this literally and use the formula Efficiency = Mechanical Advantage / Velocity Ratio, then: 2 = 4 / Velocity Ratio Velocity Ratio = 4 / 2 = 2. This leads to option (b). Despite the unphysical nature of efficiency > 1, this is the only mathematically derivable answer from the given numbers and the standard formula. Final consideration: Sometimes, in specific contexts or certain types of questions, the efficiency might be presented in a way that leads to these calculations, even if it seems non-standard in basic physics. Assuming the question and options are as intended for a test scenario, the direct calculation leads to option (b). ai_gemini |
| ICSE Class X Prelims 2026 : Physics (La Martiniere for Boys (LMB), Kolkata) | |
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(a) The phenomenon that takes place when the bulb glows is electromagnetic induction. This occurs because the rotating magnets in the dynamo induce an electric current in the coil, which then lights up the bulb. (b) When the rider increases the speed of the bicycle, the spindle of the dynamo rotates faster. This results in a greater rate of change of magnetic flux through the coil, leading to a larger induced current and thus an increase in the brightness of the bulb. (c) One advantage of a.c. (alternating current) over d.c. (direct current) is that a.c. can be easily stepped up or stepped down in voltage using transformers, making it efficient for long-distance transmission. ai_gemini |
| ICSE Class X Prelims 2025 : Biology (Lokhandwala Foundation School (LFS), Kandivali East, Mumbai) | |
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a) Both A and R are true and R is the correct explanation for A. Assertion (A) states that blood plasma transports hormones. This is true because hormones are chemical messengers that travel through the bloodstream, and the blood plasma is the liquid component of blood that carries them. Reason (R) states that hormones are water-soluble and can be dissolved in plasma. This is also true for many hormones, particularly peptide and protein hormones. Water-soluble hormones can easily dissolve in the aqueous plasma and be transported to their target cells. For steroid hormones, which are lipid-soluble, they are transported bound to plasma proteins. However, the statement that hormones are water-soluble and can be dissolved in plasma is generally true for a significant number of hormones and is a correct explanation for how they are transported. Thus, R correctly explains A. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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(a) Sewage Treatment Plant (STP) B will be more effective in treating human excreta in the municipal waste. (b) Justification: STP B includes biological treatment before sequential filtration. Biological treatment allows for the microbial breakdown of organic matter and pathogens in the sewage, which is a crucial step in effectively purifying the waste. Sequential filtration alone might remove solid particles but would be less effective in removing dissolved organic pollutants and microorganisms. Therefore, the inclusion of a biological treatment stage makes STP B more efficient. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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(b) Refer to the diagram: A Venn diagram with two overlapping circles, labeled P and R. Circle P includes parts of the human female reproductive system that support conception. Circle R includes parts that support pregnancy. The overlap region represents parts common to both conception and pregnancy. (i) Name one part each that belong to: P: Fallopian tube (oviduct) - Site of fertilization (conception). R: Uterus - Site where the embryo implants and develops during pregnancy. (ii) Name two parts that function as endocrine glands and indicate whether they belong to P or R. 1. Ovary: Functions as an endocrine gland producing hormones like estrogen and progesterone, which are crucial for both conception (regulating ovulation) and pregnancy (maintaining the uterine lining). It belongs to both P and R as it is involved in processes supporting both. 2. Placenta: Forms during pregnancy and functions as an endocrine gland, producing hormones like progesterone, estrogen, and hCG, essential for maintaining pregnancy. It primarily belongs to R (pregnancy). (Note: While ovaries are part of the reproductive system supporting conception, their endocrine function extends to supporting pregnancy. The placenta is primarily associated with pregnancy.) ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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(a) Comparison of oogenesis and spermatogenesis: | Parameter | Oogenesis | Spermatogenesis | Comparison | | :------------------------------------------ | :--------------------------------------------- | :----------------------------------------------- | :--------------------------------------------------------------------------------------------------------- | | Number of gametes produced from one oocyte or spermatocyte | One functional ovum (egg cell) and polar bodies | Four functional spermatozoa (sperm cells) | Spermatogenesis produces a significantly larger number of gametes compared to oogenesis. | | Onset | Begins during fetal development | Begins at puberty | Oogenesis starts much earlier in life than spermatogenesis. | (b) Oogenesis and spermatogenesis share some similarities, such as both being meiotic processes that produce haploid gametes. Both involve DNA replication and two successive meiotic divisions. However, they differ significantly in terms of timing, number of gametes produced, and cytoplasmic division (unequal in oogenesis, equal in spermatogenesis). ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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Draw a neat, labeled diagram of a Replication fork. A replication fork is a Y-shaped structure that forms during DNA replication. It is the site where the DNA double helix unwinds, and new DNA strands are synthesized. The diagram should show: 1. The unwound DNA double helix. 2. Two parental strands, each serving as a template. 3. Two newly synthesized daughter strands (one continuous, one discontinuous). 4. The enzyme DNA polymerase. 5. The enzyme helicase unwinding the DNA. 6. The leading strand being synthesized continuously towards the fork. 7. The lagging strand being synthesized discontinuously in Okazaki fragments away from the fork. 8. Primase synthesizing RNA primers. 9. Ligase joining Okazaki fragments. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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A nucleosome is the basic structural unit of chromatin in eukaryotes. It consists of a core particle made up of eight histone proteins (two each of H2A, H2B, H3, and H4) around which approximately 147 base pairs of DNA are wrapped. A linker DNA segment connects adjacent nucleosomes, and the H1 histone is often associated with the linker DNA, helping to stabilize the structure. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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(a) The first peak represents the primary immune response following the initial exposure to the pathogen. The second, larger peak represents the secondary immune response after a subsequent exposure to the same pathogen. (b) The difference in the size of the two peaks is because the secondary immune response is faster, stronger, and longer-lasting than the primary response. This is due to immunological memory, where memory B cells and T cells are rapidly activated upon re-exposure. (c) The technique that could be artificially applied is vaccination. Vaccination involves introducing a weakened or inactive form of a pathogen (or its antigens) into the body. This triggers a primary immune response, leading to the formation of memory cells. Upon subsequent exposure to the actual pathogen, the body mounts a rapid and effective secondary immune response, providing immunity without causing the disease. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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The given equation is dN/dt = rN. (i) This equation describes the exponential growth model or geometric growth pattern of a population. (ii) 'r' in the equation signifies the intrinsic rate of natural increase. It is the difference between the birth rate and the death rate of a population when resources are unlimited. (iii) If the population density N is plotted against time t, the type of growth curve obtained will be a J-shaped curve. (iv) In this type of growth, the resource availability will be unlimited for a certain period, as the population grows exponentially. However, this unlimited resource availability is unsustainable in the long term for a growing population. Eventually, resources will become limited, leading to a carrying capacity and a change in the growth pattern (e.g., logistic growth). ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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Given: Total rabbits = 1000 Long ears (LL) = 360 Medium ears (Lj) = 150 Short ears (jj) = 490 (a) Frequency of individuals per each genotype: Frequency of LL = Number of LL individuals / Total number of individuals = 360 / 1000 = 0.36 Frequency of Lj = Number of Lj individuals / Total number of individuals = 150 / 1000 = 0.15 Frequency of jj = Number of jj individuals / Total number of individuals = 490 / 1000 = 0.49 (b) Allele frequencies of L and j: Let p be the frequency of allele L, and q be the frequency of allele j. We know that p + q = 1. From genotype frequencies: p = Frequency of LL + (1/2) * Frequency of Lj p = 0.36 + (1/2) * 0.15 p = 0.36 + 0.075 p = 0.435 q = Frequency of jj + (1/2) * Frequency of Lj q = 0.49 + (1/2) * 0.15 q = 0.49 + 0.075 q = 0.565 Check: p + q = 0.435 + 0.565 = 1.00 (c) To determine if the population is in Hardy-Weinberg equilibrium, we compare the observed genotype frequencies with the expected genotype frequencies. Expected genotype frequencies are calculated using p and q: Expected frequency of LL = p^2 = (0.435)^2 = 0.189225 Expected frequency of Lj = 2pq = 2 * 0.435 * 0.565 = 0.49155 Expected frequency of jj = q^2 = (0.565)^2 = 0.319225 Comparing observed and expected frequencies: Observed LL: 0.36, Expected LL: 0.189225 Observed Lj: 0.15, Expected Lj: 0.49155 Observed jj: 0.49, Expected jj: 0.319225 The observed genotype frequencies (0.36, 0.15, 0.49) are significantly different from the expected genotype frequencies (0.189, 0.492, 0.319). Therefore, the population is NOT in Hardy-Weinberg equilibrium. This could be due to factors like non-random mating, selection, mutation, migration, or genetic drift. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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(i) X represents Crustaceans and Y represents Other animal groups. (ii) Crustaceans (X) is the most species-rich taxonomic group among the given options. This is because crustaceans include a vast array of species, from tiny zooplankton to large crabs and lobsters, inhabiting diverse aquatic environments. (iii) Tropics show the greatest level of species diversity due to several factors including a longer evolutionary history with less disturbance, higher solar energy input and rainfall promoting productivity, and greater niche specialization allowing for coexistence of more species. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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(a) This unauthorized act is called Biopiracy. Biopiracy is the appropriation of the knowledge of indigenous peoples relating to the medicines and other biological resources and then claiming it as their own invention. (b) Indian farmers are set to lose in the following two ways: 1. Loss of traditional rights: They may lose their traditional rights to cultivate, sell, and use their own traditional varieties of Basmati rice. 2. Economic exploitation: The American company can monopolize the market, forcing farmers to buy seeds from them at higher prices or limiting their ability to sell their produce in certain markets. (c) Two measures that different countries are taking to prevent such unauthorized exploitation of their bio-resources are: 1. Legislation and Patent Laws: Enacting and enforcing national laws and international agreements that protect traditional knowledge and prevent the unauthorized patenting of biological resources and associated knowledge. 2. Benefit Sharing Agreements: Establishing agreements that ensure fair and equitable sharing of benefits arising from the use of biological resources and traditional knowledge with the indigenous communities and countries of origin. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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(b) (i) The oral contraceptive pills shown in the image prevent pregnancy primarily by inhibiting ovulation. They may also thicken cervical mucus, making it harder for sperm to reach the egg, and alter the uterine lining to prevent implantation. The 7-day gap after the 21st day is a placebo week or a break week, during which a withdrawal bleed (similar to menstruation) occurs, mimicking a natural cycle and helping the user maintain the habit. (ii) No, oral contraceptive pills would not be recommended as the sole contraceptive method in this situation. Hepatitis-B is a sexually transmitted infection, and oral pills do not protect against STIs. Barrier methods like condoms are necessary to prevent the transmission of Hepatitis-B. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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(a) Intra-Uterine Transfer (IUT) involves the transfer of the embryo into the uterus, while Intra-Uterine Insemination (IUI) involves the artificial introduction of sperm into the uterus. (b) (i) The oral contraceptive pills block ovulation and implantation. The gap of 7 days after the 21st day is for the withdrawal of hormones, which leads to menstruation, preparing the body for the next cycle. (ii) No, oral pills would not be recommended as the ONLY contraceptive. Hepatitis-B is a serious viral infection that can be transmitted through sexual contact. While oral pills prevent pregnancy, they do not offer protection against sexually transmitted infections like Hepatitis-B. Therefore, barrier methods like condoms would be necessary. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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The pie chart represents the global biodiversity by proportionate number of species. (i) The category 'X' represents insects. (ii) The category 'Y' represents other animal groups. (iii) Tropics show the greatest level of species diversity due to factors like a longer period of evolutionary stability, a longer growing season with abundant sunlight and rainfall, and a higher rate of speciation. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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(a) X represents lymphatic vessels and Y represents lymph nodes. (b) Lymphatic vessels transport lymph, a fluid containing white blood cells, throughout the body. Lymph nodes are small, bean-shaped organs that filter the lymph and house immune cells, playing a crucial role in the immune response by trapping pathogens and initiating immune reactions. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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(a) Sweet potato and potato are analogous organs. They are both modified plant structures used for storage, but they originate from different parts of the plant (sweet potato from a root, potato from a stem). (b) The eye of an octopus and the eye of a mammal are analogous organs. They serve the same function (vision) but have evolved independently and have different underlying structures. (c) Thorns of Bougainvillea and tendrils of Cucurbita are homologous organs. Thorns are modified stem branches, while tendrils are also modified stem branches. They share a common origin but have different functions. (d) The forelimbs of a bat and a whale are homologous organs. They have the same basic bone structure inherited from a common ancestor, but they have been adapted for different functions (flight in bats, swimming in whales). ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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Forest B has the maximum energy loss by respiration. This is because the net primary productivity (NPP) is the difference between the gross primary productivity (GPP) and the respiration (R). The formula is NPP = GPP - R. Since the GPP of all forests is the same, a lower NPP indicates a higher respiration rate. Forest B has the lowest NPP (2157 J/m²/day) compared to Forest A (1254 J/m²/day) and Forest C (779 J/m²/day). This implies that Forest B loses the most energy through respiration. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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(a) A disease for which gene therapy has been successful is Severe Combined Immunodeficiency (SCID). (b) One limitation of gene therapy is the possibility of an immune response against the vector used to deliver the genes, which can cause inflammation or other adverse effects. Another limitation is that the therapeutic gene may not be inserted into the correct location in the DNA, potentially disrupting other genes. A permanent cure for SCID would involve correcting the genetic defect in the stem cells of the bone marrow, which produce all blood cells. This could be achieved through gene editing techniques like CRISPR-Cas9, which can precisely modify the DNA. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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(a) Offspring numbered 1 in Generation II has blood group O and genotype OO. (b) The possible blood groups and genotypes of the offspring numbered 2 and 3 in Generation III are: Offspring 2: Blood group A, Genotype AA or AO. Blood group B, Genotype BB or BO. Blood group AB, Genotype AB. Blood group O, Genotype OO. Offspring 3: Blood group A, Genotype AA or AO. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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(a) Cell A is the ovum (egg cell), which is the female gamete. Its function is to fuse with the male gamete (sperm) during fertilization to form a zygote. Cell B is the pollen grain, which contains the male gametes. Its function is to deliver the male gametes to the ovule for fertilization. (b) Cell D gets converted to cell E through a process called meiosis. This is a type of cell division that reduces the chromosome number by half, producing gametes. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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The diagram shows a seed. A is the cotyledon, which stores food. B is the plumule, which develops into the shoot. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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(a) Transgenic mice models are preferred over human models to study human diseases because they can be bred and studied in controlled environments, allowing for faster and more ethical research. They also share a significant genetic similarity with humans, making them suitable for modeling complex diseases like Alzheimer's. (b) Egret birds are often seen grazing cattle because they benefit from a symbiotic relationship. The cattle disturb insects and other small creatures as they graze, making them easier for the egrets to catch and eat. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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The tentative date of ovulation would be estimated around February 5th. Ovulation typically occurs about 14 days before the start of the next menstrual period. Assuming a 28-day cycle, counting 14 days from January 22nd leads to February 5th. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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Q refers to the coconut endosperm. The coconut water is likely to have been spilled or absorbed by the flesh, as it is a liquid that would normally fill the cavity. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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Gottfried Haberlandt ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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The scientist who contributed to the discovery of the enzyme Polynucleotide Phosphorylase is Jerard Hurwitz. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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Integrated Pest Management (IPM). One advantage of IPM is that it reduces reliance on chemical pesticides, which can harm the environment and human health. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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Perisperm is the persistent part of the nucellus which is found in some seeds, serving as stored food material for the developing embryo. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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A Both Assertion and Reason are true, and Reason is the correct explanation for Assertion. Agrobacterium tumefaciens is a natural genetic engineer due to its ability to transfer genes to plant cells, and its association with plant roots facilitates this process. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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B Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion. The detritus food chain begins with dead organic matter and energy flows from decomposers to consumers, not directly from solar energy. ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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C. Separation of eye lids 24 weeks ai_gemini |
| ISC Class XII Prelims 2025 : Biology (GEMS Modern Academy, Dubai) | |
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A. Riya ai_gemini |
| ICSE Class X Prelims 2026 : Biology (Bombay Scottish School, Mahim, Mumbai) | |
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The correct answer is b) Student 2 and 3. Oxygen and urea are transferred from mother to fetus. Amino acids and vitamins are also transferred. Carbon dioxide is a waste product and glucose is utilized by the fetus. ai_gemini |
| ICSE Class X Prelims 2026 : Biology (Bombay Scottish School, Mahim, Mumbai) | |
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a) X chromosome of male ai_gemini |
| ICSE Class X Prelims 2026 : Biology (Bombay Scottish School, Mahim, Mumbai) | |
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b) R and S. Lymph is a clear fluid that circulates in the lymphatic system. It is not colorful and does not contain hemoglobin or RBCs. It contains lymphocytes and some platelets, but its primary role is not clotting. Lymph is important for transporting nutrients and hormones, and it plays a crucial role in absorbing fats from the intestines through lacteals in the villi. ai_gemini |
| ICSE Class X Prelims 2026 : Biology (Bombay Scottish School, Mahim, Mumbai) | |
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d) Both the parents are heterozygous dominant. Tongue rolling is a dominant trait. Since Ajay can roll his tongue, he has at least one dominant allele. Since Vijay cannot roll his tongue, he is homozygous recessive. For Vijay to be homozygous recessive, he must have inherited a recessive allele from each parent. Therefore, both parents must have at least one dominant allele and one recessive allele, making them heterozygous dominant. ai_gemini |
| ICSE Class X Prelims 2026 : Biology (Bombay Scottish School, Mahim, Mumbai) | |
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C arsh09 |
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