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JEE Advance Exam 2021 : PCM : Magnetic effects + EMI + AC Dilute Solution, Mole Concept, Chemical Kinetics, Nomenclature & Isomerism. s-block element and Solid State. MATRICES AND DETERMINANT + ITF +COMPLEX NO.

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Nisarg Bhavsar
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Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Test Name : 12th AITS JEE Advanced [17.11.2020] Difficulty Level : Medium Test Type : Paid Q.1 Total Questions : 60 Total Marks : 246.00 Duration : 180.00 mins A long straight wire along the z-axis carries a current I in the negative z direction. The magnetic vector field A. at a point having coordinates (x, y) in the z = 0 plane is- B. C. D. Answer : A,D, Solution : NA Q.2 A charged particle of specific charge moves with velocity in a magnetic field . Then (specific charge = charge per unit mass) A. Path of the particle is a helix B. Path of the particle is circle C. Distance moved by the particle in time t = /B is v/B D. Velocity of the particle after time t = /B is Answer : B,C, Solution : NA Page - 1/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.3 In the figure shown, 'R' is a fixed conducting fixed ring of negligible resistance and radius 'a'. PQ is a uniform rod of resistance r. It is hinged at the centre of the ring and rotated about this point in clockwise direction with a uniform angular velocity . There is a uniform magnetic field of strength 'B' pointing inwards, 'r' is a stationary resistance, then - A. Current through 'r' is zero B. Current through 'r' is C. Direction of current in external 'r' is from centre to circumference D. Direction of current in external 'r' is from circumference to centre Answer : B,D, Solution : Equivalent circuit Induced emf e = (Q Radius = a) By nodal equation, nodal 4 =0 5 x = 4e x = 4e/5 Page - 2/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 and i = Q.4 In the diagram shown, the wires P1Q1 and P2Q2 are made to slide on the rails with same speed of 5 m/s. In this region a magnetic field of 1 T exists. The electric current in 9 resistor is A. B. C. D. zero if both wires slide towards left zero if both wires slide in opposite direction 20 mA if both wires move towards left. 20 mA if both wires move in opposite direction Answer : B,C, Solution : = Blv = 1 0.04 5 = 0.2 volt i= = i = 0.02 A i = 2 10 2A = 20 mA Page - 3/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.5 L, C and R represent the physical quantities inductance, capacitance and resistance respectively. The combinations which have the dimensions of frequency are A. B. C. D. Answer : A,B, Solution : NA Q.6 In the circuit shown, resistance R = 100 , inductance L = H and capacitance C = F are connected in series with an ac source of 200volt and frequency 'f '. If the readings of the hot wire voltmeters V1 and V2 are same then - A. B. C. D. f = 125 Hz f = 250 Hz current through R is 2A V1 = V2 = 1000 volt Answer : A,C,D, Solution : V1 = V2 I= XL = XC = QX=0 f= = 125Hz Z=R Page - 4/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 I = 2A V1 = V2 = I = I L=2 2 125 = 1000 volt Q.7 Essay : 7-8): A charged particle (q, m) is released from origin with velocity in a uniform magnetic field Pitch of the helical path described by the particle is A. B. C. D. Answer : C, Solution : In the figure V|| = v cos 60 = V = v sin 60 = Page - 5/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 p = v|| T = = Q.8 Essay : 7-8): A charged particle (q, m) is released from origin with velocity in a uniform magnetic field z-component of velocity is A. after time t = . . . . . B. C. D. Answer : C, Solution : Vz = V or and vz = v or Q.9 after t = after t = Essay : 9-10): Figure shows a conducting rod of negligible resistance that can slide on smooth U-shaped rail made of wire of resistance 1 /m. position of the conducting rod at t = 0 is shown. A time t dependent magnetic field B = 2t tesla is switched on at t = 0 Page - 6/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 The current in the loop at t = 0 due to induced emf is A. 0.16 A, clockwise B. 0.08 A, clockwise C. 0.08 A, anticlockwise D. zero Answer : A, Solution : = 2T/s E= i= = 800 10 4 m2 2 = 0.16 V = 0.16 A, clockwise Q.10 Essay : 9-10): Figure shows a conducting rod of negligible resistance that can slide on smooth U-shaped rail made of wire of resistance 1 /m. position of the conducting rod at t = 0 is shown. A time t dependent magnetic field B = 2t tesla is switched on at t = 0 At t = 0, when the magnetic field is switched on, the conducting rod is moved to the left at constant speed 5 cm/s by some external means. The rod moves perpendicular to the rails. At t = 2s, induced emf has magnitude. A. 0.12V B. 0.08V C. 0.04V Page - 7/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 D. 0.02V Answer : B, Solution : At t = 2s, B = 4T, 2T/s A = 20 30 cm2 = 600 10 4 m2 ; (5 20) cm2/s = 100 10 4 m2/s = [4 ( 100 10 4) + 600 10 4 2] = [ 0.04 + 0.120] = 0.08 v Q.11 A charged particle is accelerated through a potential difference of 12 kV and acquires a speed of 106 ms 1. It is projected perpendicularly into the magnetic field of strength 0.2 T. The radius of circle described is 10 cm. Answer : 1, Solution : R= q 12 103 = m (106)2 R= Page - 8/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 R = 12 10 2 m R = 12 cm Q.12 A current I = 10A flows in a ring of radius r =15 cm made of a very thin wire. The tensile strength of the wire is equal to T = 1.5 N. The ring is placed in a magnetic field, which is perpendicular to the plane of the ring so that the forces tend to break the ring. Find B at which the ring is broken. Answer : 1, Solution : NA Q.13 Two conducting rails are connected to a source of emf and form an incline as shown in figure. A bar of mass 50g slides without friction down the incline through a vertical magnetic field B. If the length of the bar is 50 cm and a current of 2.5 A is provided by battery. Value of B for which the bar slide at a constant velocity .. 10 1 Tesla.[g = 10 m/s2] Answer : 3, Solution : Fcos = Mgsin BI Lcos = Mgsin B= = 0.3 Tesla Q.14 A plane loop is shaped in the form as shown in figure with radii a = 20 cm and b = 10 cm and is placed in a uniform time varying magnetic field B = B0 sin t, where B = 10 mT and = 100 Page - 9/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 rad/s. Find the amplitude of the current induced in the loop if its resistance per unit length is equal to 50 10 3 /m. The inductance of the loop is negligible. Answer : 1, Solution : Instantaneous flux = a2 B cos 0 + = (a2 b2) B (a2 b2) B0 sin b2 B cos 180 t l= i= i= R= 2 imax = (a + b) = 1 Amp Q.15 In the given circuit, initially switch S1 is closed and S2 and S3 are open. After charging of capacitor, at t = 0, S1 is open and S2 and S3 are closed. If the relation between inductance capacitance and resistance is L = 4CR2 then find the time (in sec) after which current passing through capacitor and inductor will be same.(given R = ln2 m , L = 2 mH) Page - 10/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Answer : 1, Solution : After charging, charge on capacitor = C Now at t = 0 two circuits formed 1.Discharging of capacitor q= C =C i1 = 2.Growth of current in L-R circuit i2 = now i1 = i2 = (1) given L = 4CR2 = 2RC = ln from equation (1) 2 =1 t ln2 = ln2 t = 1sec. Page - 11/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.16 A conductor ABOCD moves along its bisector with a velocity 1 m/s through a perpendicular magnetic field of 1 wb/m2, as shown in figure. If all the four sides are 1 m length each, then the induced emf between A and D in approx is .. volt Answer : 1, Solution : VA VD = V B l =1 1 = 1. 41 volt sine rule l= = = 1.414 Q.17 A uniform disc of radius R having charge Q distributed uniformly all over its surface is placed on a smooth horizontal surface. A magnetic field B = Kxt2, where K = constant, x is the distance (in metre) from the centre of the disc and t is the time (in second) is switched on perpendicular to the plane of the disc. The torque (in N - m) acting on the disc after 15 sec. (Take 2 KQ = 1 S.I. unit and R = 1 metre) in N - m is Answer : 3, Solution : Consider a ring of thickness dx Torque on this ring = QE x E 2 x= x2 Page - 12/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 E= 2Kxt Kx2t charge on ring = 2 xdx x K x2 t xdx = Torque on ring = x4t dx = Total torque = = x4t dx = 3 N- m Q.18 An inductor of 0.1 Henry and a box are connected to AC supply of 25 volts and = 100 rad/sec over all power factor of circuit is 1 and the reading of AC ammeter (Irms) is 5A. Find the power factor of box. Answer : Solution : z=x+y + = x + (y + one y + I= L L) for power factor to be L=0 ,x= = y = 10 =5 Impedance of box = 5 10 Page - 13/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 cos = = = 0.447 Q.19 Current in the inductance is 0.8 A while in the capacitance is 0.6 A. The current drawn from the source is ------ 10 1 Amp. Answer : 2, Solution : INet = IL IC = 0.8 0.6 = 0.2 Amp. Q.20 An inductor coil, capacitor and an A.C. source of rms voltage 24V are connected in series. When the frequency of the source is varied, a maximum rms current of 6.0 A is observed. If this inductor coil is connected to a battery of emf 12V and of internal resistance 4 , the current will be ... 0.3 amp. Answer : 5, Solution : Current at resonance = Current by 12V battery = A Page - 14/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.21 A. B. C. D. A, B, C, D, Answer : B,C,D, Solution : Q.22 A. B. C. D. A, B, C, D, Page - 15/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Answer : A,B,D, Solution : Q.23 A. A, B. B, C. C, Page - 16/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 D. D, Answer : A,B,C, Solution : Q.24 A. B. C. D. A, B, C, D, Answer : B,C,D, Solution : Page - 17/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.25 A. B. C. D. A, B, C, D, Answer : A,C, Solution : Q.26 Page - 18/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 A. B. C. D. A, B, C, D, Answer : A,B,C,D, Solution : Page - 19/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.27 Essay : 27-28): Page - 20/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 A. B. C. D. A, B, C, D, Answer : D, Solution : Q.28 Essay : 27-28): A. B. C. D. A, B, C, D, Answer : B, Solution : Page - 21/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.29 Essay : 29-30): A. B. C. D. A, B, C, D, Answer : B, Solution : Q.30 Essay : 29-30): Page - 22/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 A. B. C. D. A, B, C, D, Answer : A, Solution : Q.31 Answer : 248, Solution : Page - 23/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.32 Answer : 4, Solution : Page - 24/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.33 Answer : 30, Solution : Page - 25/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.34 Answer : 79, Solution : Page - 26/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.35 Answer : 3, Solution : Q.36 Answer : 1, Solution : Page - 27/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.37 Answer : 1, Solution : Q.38 Page - 28/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Answer : 4, Solution : Q.39 Answer : 2112, Solution : Page - 29/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.40 Answer : 6, Solution : Page - 30/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Page - 31/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.41 A. B. C. D. A, B, C, D, Answer : A,D, Page - 32/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Solution : Q.42 Page - 33/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 A. B. C. D. A, B, C, D, Answer : A,B,C, Solution : Page - 34/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.43 A. B. C. D. A, B, C, D, Answer : A,B,D, Solution : Q.44 A. B. C. D. A, B, C, D, Page - 35/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Answer : D, Solution : Q.45 A. B. C. D. A, B, C, D, Answer : A, Solution : Page - 36/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.46 A. B. C. D. A, B, C, D, Answer : A,B,C, Solution : Page - 37/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.47 Essay : 47-48): A. B. C. D. A, B, C, D, Answer : C, Solution : Page - 38/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.48 Essay : 47-48): A. B. C. D. A, B, C, D, Answer : B, Solution : Page - 39/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.49 Essay : 49-50): A. B. C. D. A, B, C, D, Answer : A, Solution : Page - 40/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.50 Essay : 49-50): A. B. C. D. A, B, C, D, Answer : A, Solution : Page - 41/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.51 Answer : 6, Solution : Page - 42/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.52 Answer : 2, Solution : Page - 43/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.53 Answer : 5, Solution : Page - 44/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.54 Answer : 1, Solution : Q.55 Answer : 4, Solution : Page - 45/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.56 Answer : 1, Solution : Q.57 Page - 46/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Answer : 2, Solution : Q.58 Answer : 4, Solution : Page - 47/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.59 Answer : 2, Solution : Page - 48/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Q.60 Answer : 3, Solution : Page - 49/50 Edunova Educational Foundation https://www.edunova.ac.in, edunovadigital@edunova.ac.in 9327101002 Page - 50/50

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