Trending ▼   ResFinder  

ICSE Class X Mid-term 2024 : Chemistry

54 pages, 351 questions, 0 questions with responses, 0 total responses,    0    0
Prajwal Simha
Florence Public School, RT Nagar, Bangalore
+Fave Message
ProfileTimelineUploads
 Home > l_2345 >

Formatting page ...

CHAPTER - 12 ORGANIC CHEMISTRY EXERCISE. 12 A Question 1: Write the IUPAC name of the following: CH 3 | (a) CH 3 C CH 3 | CH 3 CH 3 CH CH 2 CH 3 | (b) CH 3 H H H | | | (c) H C C C H | H CH 3 | (d) H 3C C CH 2CH 2CH 3 | CH 3 (e) CH 3 C C CH 2CH 3 CH 3 | (f) H C C C H | CH 3 Cl | (g) CH 3 CH CH CH 2CH 3 | Cl CH 3 CH 3 | | (h) CH 2 CH CH 2 | CH 2CH 2CH 3 CH 3 | (i) CH 3 CH CH 2CH 3 (j) CH 3 C C CH 2CH 2CH 2CH 3 CH 3 | (k) CH 3 C CH 2CH 2CH 2CHO | CH 3 CH 3 CH CH 2CH 2CH 3 (l) | OH CH 3CH CH 2CH 2COOH (m) | CH 3 CH 3 | (n) CH 3 C CH 2CH 3 | Br CH 3 (o) | CH 3 CH CH 2 CH 2 Br Solution 1: (a) 2,2- dimethylpropane (b) 2-methyl butane (c) Prop-1-ene (d) 2,2- dimethyl pentane (e) Pent-2-yne (f) 3-methyl but-1-yne (g) 2,3-dichloropentane (h) 3-methylheptane (i) 2-methyl butane (j) Hept-2-yne (k) 2,2- dimethyl hexanal (l) Pentan-2-ol (m) 4-methylpentanoic acid (n) 2-bromo2-methyl butane (o) 1- bromo3-methyl butane Question 2: Write the structure of the following compounds: (a) Prop-1-ene, (b) 2, 3 dimethyl butane, (c) 2 methyl propane (d) 3-hexene (e) prop 1 yne (f) 2-methylprop 1- ene, (g) Alcohol with molecular formula C4H10O Solution 2: The structure of the following compounds are: (a) Prop-1-ene CH3 CH = CH2 (b) 2,3-dimethylbutane CH3 CH(CH3) CH(CH3) CH3 (c) 2-methylpropane CH3 CH(CH3) CH3 (d) 3-hexene CH3 CH2 CH = CH CH2 CH3 (e) Prop-1-yne CH3 C?CH (f) 2-methylprop-1-ene CH3 C(CH3) = CH2 (g) Alcohol with molecular formula C4H10O CH3 CH2 CH2 CH2 OH Question 3: Choose the correct answer: (a) C5 H11 is an (i) alkane (ii) alkene (iii) alkyne (iv) alkyl group (b) A hydrocarbon of the general CnH2n is (i) C15H30 (ii) C12H26. (iii) C8H20 (iv) C6H14 (c) A hydrocarbon with molecular mass 72 is (i) an alkane (ii) an alkene (iii) an alkyne (d) The total number of different carbon chains that four carbon atoms form in alkane is (i) 5 (ii) 4 (iii) 3 (iv) 2 (e) CH3 CH2 OH and CH3 O CH3 are (i) position isomers (ii) chain isomers (iii) homologous (iv) functional group isomers (f) The IUPAC name of the compound is CH 3 | CH 3 CH 2 CH 2 CH CH 2 CH 3 (i) 3-trimethylhexane (ii) 3- methyl hexane (iii) 4 methyl hexane Solution 3: (a) Correct answer: (iv) CnH2n + 1 is the formula for alkyl group. Hence it is C5H11. (b) Correct answer: (i) A hydrocarbon of general CnH2n is C15H30. (c) Correct answer: (ii) As the formula of Alkene is CnH2n. Thus n + 2n = 72 3n = 72 n = 24 By filling value we get the molecular mass 72. (d) (iv) The total number of carbon chains that four carbon atoms form in alkane is 2. They are: H H H H | | | | H C C C C H | | | | H H H H (e) Correct answer: (iv) Alcohol and ether are functional isomers as they have same molecular formula but different functional groups. (f) Correct answer: (ii) CH3 CH 2 CH CH 2 CH 2 CH3 | CH3 The IUPAC name of this compound is: 3-methyl hexane. Question 4: Fill in the blanks: (a) Propane and ethane are ____________ (b) A saturated hydrocarbon does not participate in a/an _________ reaction. (c) Succeeding members of a homologous series differ by ______________ (d) As the molecular masses of hydrocarbons increase, their boiling points ________ and melting point ____________ (e) C25H52 and C50H102 belong to _______________ homologous series. (f) CO is an__________ Compound. (g) The chemical properties of an organic compound are largely decided by the ___________ and the physical properties of an organic compound are largely decided by the ___________ (h) CHO is the functional group of an __________. (i) The root in the IUPAC name of an organic compound depends upon the number of carbon atoms in _____________ (j) But-1-ene and but-2-ene are examples of ___________ isomerism. Solution 4: (a) (b) (c) (d) Propane and ethane are homologues. A saturated hydrocarbon does not participate in a/an addition reaction. Succeeding members of a homologous series differ by CH2. As the molecular masses of hydrocarbons increase, their boiling points Increase and melting point increase. (e) C25H52 and C50H102 belong to the same homologous series. (f) CO is an organic Compound. (g) The physical and chemical properties of an organic compound are largely decided by the Functional group. (h) CHO is the functional group of an aldehyde. (i) The root in the IUPAC name of an organic compound depends upon the number of carbon atoms in Principal Chain. (j) But-1-ene and but-2-ene are examples of position isomerism. EXERCISE. 12 B Question 1: State the sources of Alkanes. Solution 1: Sources of alkane: The principal sources of alkanes are Natural gas and petroleum. Question 2: Methane is a greenhouse gas comment. Solution 2: Methane is a primary constituent of natural gas. It absorbs outgoing heat radiation from the earth, and thus contributes to the green house effect and so it is considered as a green house gas. Question 3: Give the general formula of alkanes. Solution 3: The general formula of alkane is : Cn H 2 n 2 Question 4: Draw the structures of isomers of: (a) butane (b) pentane Write the IUPAC and common names of these isomers Solution 4: (a)The structures of isomers of butane are: (i) H H H H | | | | H C C C C H | | | | H H H H Common name:- n-Butane IUPAC name:- Butane (ii) Common name:-iso butane IUPAC name:- 2-methyl propane (b) The structures of isomers of Pentane are: (i) H H H H H | | | | | H C C C C C H | | | | | H H H H H Common name: n-pentane IUPAC name:- Pentane (ii) H H H H | | | | H C C C C H | | | | H CH3 H H Common name:- iso pentane IUPAC name:- 2-methyl butane (iii) CH 3 | H 3C C CH 3 | CH 3 Common name- neo pentane IUPAC name:- 2,2-dimethyl propane Question 5: Write the: (a) molecular formula (b) electron dot formula and (c) structural formula of methane and ethane. Solution 5: For methane: (a) Molecular formula is CH4 (b) Electron dot formula (c) Structural formula H | H C H | H For ethane: (a) Molecular formula is :- C2H6 (b) Electron dot formula: (a) Structural Formula: H H | | H C C H | | H H Question 6: How is: (a) methane and (b) ethane prepared in the laboratory? Solution 6: (a) Laboratory preparation of methane: When the mixture of sodium ethanoate and soda lime is taken in a hard glass test tube and heated, the gas evolved is methane. It is collected by downward displacement of water. CaO,300 C Na2CO3 + CH4 CH3COONa + NaOH (b) Laboratory preparation of ethane: When the mixture of sodium propionate and soda lime is taken in the boiling tube and heated the ethane gas is evolved. It is also collected by downward displacement of water. 0 CaO,300 C Na2CO3 + C2H6 C2H5COONa + NaOH 0 Question 7: How are methane and ethane prepared from methy1 iodide and ethyl bromide? Solution 7: When methyl iodide is reduced by nascent hydrogen at ordinary room temperature then methane is formed. CH3l+2[H] CH4+Hl When bromoethane is reduced by nascent hydrogen at ordinary room temperature then ethane is produced. C2H5Br+2[H] C2H6+HBr Question 8: What is a substitution reaction? Give the reaction of chlorine with ethane and name the product formed. Solution 8: A reaction in which one atom of a molecule is replaced by another atom (or group of atoms) is called a substitution reaction. When ethane reacts with chlorine C2H6 +Cl2 C2H5Cl + HCl Chloroethane C2H5Cl + Cl2 C2H4Cl2+HCl Dichloroethane C2H4Cl2 +Cl2 C2H3Cl3+HCl Trichloroethane C2H3Cl3 + Cl2 C2H2Cl4 + HCl Tetrachloroethane C2H2Cl4 +Cl2 C2HCl5 +HCl Pentachloroethane C2HCl5 +Cl2 C2Cl6 + HCl Hexachloroethane Question 9: Name the compounds formed when methane burns in: (a) sufficient air, (b) insufficient air, Give a balanced equation Solution 9: (a) Sufficient air: When methane burns in sufficient air, then carbon dioxide and water vapors are formed. CH4 + 2O2 CO2+2H2O (b) Insufficient air: When methane burns in insufficient air , then carbon monoxide and water is formed. 2CH4 + 3O2 2CO + 4H2O Question 10: Write the names and the formula of the products formed when: (a) methane (b) ethane Reacts with : (i) chlorine (ii) bromine Write the chemical equations Solution 10: (a) (i) When methane reacts with chlorine in the presence of sunlight or UV light, it undergoes substitution reaction to form Tetrachloromethane. hv CH 4 Cl2 CH 3Cl HCl Chloromethane hv CH3Cl Cl2 CH 2Cl2 HCl Dichloromethane hv CH 2 Cl2 Cl2 CHCl3 HCl Trichloromethane hv CHCl3 Cl2 CCl4 HCl Tetrachloromethane (ii) When it reacts with bromine it forms Tetrabromomethane CH4 + Br2 CH3Br + HCl CH3Br + Br2 CH2Br2 + HCl Dibromomethane CH2Br2 + Br2 CHBr3 + HCl Tribromo methane CHBr3 + Br2 CBr4 + HCl Tetrabromomethane (b) (i) When ethane reacts with chlorine it forms hexachoroethane. C2H6 +Cl2 C2H5Cl + HCl Chloroethane C2H5Cl + Cl2 C2H4Cl2 + HCl Dichloroethane C2H4Cl2 + Cl2 C2H3Cl3 + HCl Trichloroethane C2H3Cl3 + Cl2 C2H2Cl4 + HCl Tetrachloroethane C2H2Cl4 +Cl2 C2HCl5 +HCl Pentachloroethane C2HCl5 +Cl2 C2Cl6 + HCl Hexachloroethane (ii) When ethane reacts with bromine it forms Hexabromoethane C2H6 +Br2 C2H5Br + HBr Bromoethane C2H5Br + Br2 C2H4Br2+HBr Dibromoethane C2H4Br2 +Br2 C2H3Br3+HBr Tribromoethane C2H3Br3 + Br2 C2H2Br4 + HBr Tetrabromoethane C2H2Br4 +Br2 C2HBr5 +HBr Pentabromoethane C2HBr5 +Br2 C2Br6 + HBr HexaBromoethane Question 11: Name the compound prepared from: (a) sodium propionate, (b) methyl iodide and Write a balanced equation for the same (c) ethyl bromide Solution 11: (a) Ethane is prepared from sodium propionate. CaO,300 C Na2CO3 + C2H6 C2H5COONa + NaOH (b) Methane is prepared from methyl iodide. CH3l + 2[H] CH4 + Hl (c) Ethane is prepared from ethyl bromide. C2H5Br + 2[H] C2H6 + HBr 0 Question 12: What is pyrolysis or cracking? Explain with example. Solution 12: The decomposition of a compound by heat in the absence of air is called Pyrolysis. When pyrolysis occurs in alkanes, the process is termed cracking. For example: Alkanes on heating under high temperature or in the presence of a catalyst in absence of air broken down into lower alkanes, alkenes and hydrogen. 1500 C HC?CH + 3H2 2CH4 0 Question 13: Convert: (a) Methane into chloroform (b) sodium acetate into methane (c) Methyl iodide into ethane (d) Aluminum carbide into methane Solution 13: (a) Methane into chloroform CH4 + Cl2 CH3Cl + HCl CH3Cl + Cl2 CH2Cl2 + HCl CH2Cl2 + Cl2 CHCl3 + HCl (b) Sodium acetate into methane CaO,300 C Na2CO3 + CH4 CH3COONa + NaOH (c) Methyl iodide into ethane dryether 2CH3I + 2Na CH3 CH3 + 2NaI (d) Aluminium carbide into methane Al4C3 + 12H2O 3CH4 + 4Al(OH)3 0 Question 14: Give three uses of: (a) methane (b) ethane Solution 14: (a) Methane: Three uses of methane are: (i) Methane is a source of carbon monoxide and hydrogen (ii) It is used in the preparation of ethyne, methanal, chloromethane, carbon tetrachloride. (iii) It is employed as a domestic fuel. (b) Ethane: Three uses of ethane are: (i) It is used in the preparation of ethene, ethanol, and ethanol. (ii) It forms ethyl chloride, which is used to make tetraethyllead. (iii) It is also a good fuel. Question 15: Under what conditions does ethane get converted to: (a) ethyl alcohol (b) acetaldehyde (c) acetic acid Solution 15: (a) When a mixture of ethane and oxygen is compressed to about 120atm pressure and passed over copper tubes at 475K, ethyl alcohol is formed. 120 atm 2C2H6 +O2 2C2H5OH Cutubes, 475k (b) When mixture of ethane and oxygen is passed through heated molybdenum oxide, the mixture is oxidized to Acetaldehyde. MoO C2H6 +O2 CH3CHO+H2O (c) Ethanol formed from ethane gets oxidized to acetic acid. 120 atm 2C2H6 +O2 2C2H5OH Cutubes, 475k Pt C2H5OH + O2 CH3COOH+H2O 3000 C Question 16: Give the inter-relationship of methane, methyl alcohol, formaldehyde and formic acid with conditions. Solution 16: (a) Methane to methyl alcohol: When a mixture of methane and oxygen is compressed to about 120atm pressure and passed over copper tubes at 475K, ethyl alcohol is formed. 120 atm 2CH4 + O2 2CH3OH Cutubes, 475k (b) Methane to formaldehyde: When mixture of methane and oxygen is passed through heated molybdenum oxide, the mixture is oxidized to Formaldehyde. MoO CH4 + O2 HCHO + H2O (c) Methane to Formic acid: When a manganese based catalyst is used methane is oxidized to formic acid. Min compound 2CH4 + 3O2 2HCOOH + 2H2O EXERCISE. 12 C Question 1: Write: (a) molecular formula, (b) electron dot formula and (c) structural formula of ethane (ethylene) Solution 1: (a) The molecular formula of ethene is C2H4 (b) Electron dot formula of ethene is: (c) Structural formula of ethene: Question 2: The molecules of alkene family are represented by a general formula CnH2n. Answer the following: (a) What do n and 2n signify? (b) what is the name of alkene when n = 4? (c) What is the molecular formula of alkene when n = 4? (d) what is the molecular formula of the alkene if there are ten H atoms in it? (e) what is the structural formula of the third member of the alkene family? (f) write the molecular formula of lower and higher homologous of an alkene which contains four carbon atoms. Solution 2: (a) n signifies the number of carbon atoms and 2n signifies the number of hydrogen atoms. (b) The name of alkene when n = 4 is Butene. (c) The molecular formula of alkene when n = 4 is C4H8. (d) The molecular formula of alkene when there are 10 H atom in it C5H10. (e) The structural formula of the third member of alkene is H H H | | | H C C C H | H (f) Lower homologus of alkene which contain four carbons is C3H6. Higher homologus of alkene which contain four carbons is C5H10. Question 3: Discuss isomers in double bond compounds taking example of butane. Draw their structures and write IUPAC names. Solution 3: The isomers of Butene are: (i) CH3 CH2-CH = CH2 ,But-1-ene (ii) CH3 CH = CH CH3 , But-2-ene (iii) CH2 = C(CH3) CH3 , 2-methyl propene Question 4: Give a balanced equation for the lab. Preparation of ethylene. How is the gas collected? Solution 4: Balanced Equation of ethylene: CH3 CH2OH + H2SO4 CH3 CH2HSO4 + H2O excess H2SO4 CH3 CH2HSO4 CH2 = CH2 1600 C The gas is collected by downward displacement of water. Question 5: How is ethane prepared by: (a) dehydrohalogenation reaction (b) dehydration reaction? Give equations and name the products formed. Solution 5: (a) Dehydrohalogenation reaction: C2H5Cl + KOH(alc.and hot) C2H4 + KCl + H2O Ethene (b) Dehydration reaction: Al2O 3 C2H5OH C2H4 + H2O 3000 C Ethene Question 6: Give the conditions and the main products formed by hydrogenation of ethylene. Solution 6: When ethene and hydrogen are passed over finely divided catalyst such as platinum or palladium at ordinary temperature or nickel at 200o C, the two atom of hydrogen molecule are added to the unsaturated molecule, which thus becomes a saturated one. 2000 C C2H4 +H2 C2H6 Ni Question 7: Ethylene when reacts with halogens (chlorine and bromine) form saturated products. Name them and write balanced equations. Solution 7: Chlorine and bromine are added to the double bond of ethene to form saturated ethylene chloride and ethylene bromide respectively. CH2 = CH2 + Cl2 CH2(Cl) CH2(Cl) 1,2-dichloro ethane CH2 = CH2 + Br2 CH2(Br) CH2(Br) 1,2-dibromo ethane Question 8: How is ethanol converted into ethene using (i) solid dehydrating agent (ii) hot conc. H2SO4? Give only balanced equations Solution 8: (i) Solid dehydrating agent:. Al2O 3 C2H5OH C2H4+H2O 3000 C Ethene (ii) Hot conc. H2SO4: Conc. H2SO4 C2H5OH C2H4 + H2SO4 160 1700 C Question 9: Write the following properties of ethene: (a) Physical state (b) Odour (c) Density as compared to air (d) Solubility Solution 9: (a) (b) (c) (d) Physical state: Ethene is a colourless and inflammable gas. Odour: It has faint sweetish odour. Density as compared to air: It has density less than one hence it is lighter than air. Solubility: It is sparingly soluble in water but highly soluble in organic solvents like alcohol, ether and chloroform. Question 10: How would you convert: (a) ethene into 1, 2-dibromoethane? (b) ethene into ethyl brominde? Solution 10: (a) Ethene into 1, 2 -dibromoethane: Ethene reacts with bromine at room temperature to form saturated ethylene chloride. CH2 = CH2 + Br2 CH2(Br) CH2(Br) 1,2-dibromo ethane (b) Ethene into ethyl bromide: When ethene is treated with HBr bromoethane is formed. CH2 = CH2 + HBr CH3 CH2Br Ethyl bromide Question 11: Give balanced equations when: (a) ethene is burnt in excess of oxygen (b) ethene reacts with chlorine (c) ethene combines with hydrogen chloride (d) a mixture of ethene and hydrogen is passed over nickel at 200 C. Solution 11: (a) C2H4 + 3O2 2CO2 + 2H2O + heat (b) CH2 = CH2+Cl2 CH2(Cl) CH2(Cl) (c) CH2 = CH2 + HCl CH3 CH2-Cl 2000 C (d) C2H4 + H2 C2H6 Ni Question 12: Give the formula and name of A, B C and D in the following equations: cl2 cl2 cl2 cl2 (a) CH4 B C D A- HCI HCI HCI HCI Br2 Br2 H2 H2 C D (b) C2H2 B A- HBr HBr (c) C2H4 + Cl2 A 200 C (d) C2H4 + B C2H6 Ni 0 Solution 12: cl2 cl2 cl2 cl2 (a) CH4 CH2Cl2 CH3Cl CHCl3 CCl4 HCI HCI HCI HCI A = monochloromethane B = dichloromethane C = Trichloromethane D = Tetrachloromethane Br2 Br2 H2 H2 C2H4Br (b) C2H2 C2H5Br C2H4 C2H6 HBr HBr A= Ethene B = ethane C = bromoethane D = dibromoethane (c) C2H4 + Cl2 C2H4Cl2 A = 1,2-dichloro ethane 2000 C (d) C2H4 +H2 C2H6 Ni B = hydrogen Question 13: Write the name and formula of the product formed in each case below: (a) C2H4 + Cl2 . (b) C2H5Br + KOH (alc.) . alk.KMnO4 (c) H2C = CH2 (d) H2C = CH2 + HBr . (e) H2C = CH2 + O3 . Solution 13: (a) C2H4 + Cl2 CH2(Cl) CH2(Cl) 1,2- dichloro ethane (b) C2H5Br + KOH (alc.) C2H4 + KBr + H2O Ethane alk.KMnO4 (c) CH2 = CH2 CH2(OH) CH2(OH) 1,2- Ethanediol (d) CH2 = CH2 + HBr CH3-CH2Cl Chloroethane (e) CH2 = CH2 + O3 Question 14: What do you observe when ethylene is passed through alkaline KMnO4 solution? Solution 14: When ethylene is passed through alkaline KMnO4 solution 1, 2-Ethanediol is formed. The Purple color of KMnO4 decolorizes. CH2 = CH2 + H O H + [O] CH2(OH) CH2(OH) Cold alkaline KMnO4 solution Question 15: Name three compounds formed by ethylene and give the use of these compounds. Solution 15: Three compounds formed by ethylene are: Polythene Ethanol Epoxyethane Uses of above compounds: Polythene is used as carry bags. Ethanol is used as a starting material for other products, mainly cosmetics and toiletry preparation. Epoxyethane is used in the manufacture of detergents. EXERCISE. 12 D Question 1: What are the sources for alkynes? Give the general formula of alkynes. Solution 1: Natural gas and Petroleum are sources for alkynes. The general formula of alkynes are: CnH2n-2 Question 2: Give an example of isomers shown by triple bond hydrocarbon (alkynes) and write its IUPAC name. Solution 2: Butyne is an example, its isomers are: H H H | | | H C C C C H | H | H C C C C H | | | H H H H IUPAC name: But-2-yne But-1-yne Question 3: How is acetylene prepared in the laboratory? (a) draw a diagram (b) Give an equation (c) How is pure dry gas collected? Solution 3: (a) Diagram of acetylene preparation: (b) CaC2 + 2H2O Ca(OH)2 + C2H2 (c) The pure dry gas is collected by downward displacement of water, since it is insoluble in water. Question 4: Give the method of preparation of ethyne by 1, 2 dibromoethene. Solution 4: When 1,2 -dibromoethane is boiled with alcoholic potassium hydroxide, ethyne is formed. Boiling CH 2 Br CH 2 Br KOH CH CH 2KBr 2H 2 O Question 5: Classify the following compounds as alkanes, alkenes and alkynes. C3H4:C3H8:C5H8:C3H6:- Solution 5: The following compounds can be classified as: C3H4:- Alkynes C3H8:- Alkanes C5H8:- Alkynes C3H6:- Alkenes Question 6: Give a chemical test to distinguish between (a) saturated and unsaturated compounds (b) ethane and ethene (c) ethene (ethylene) and ethyne (acetylene) Solution 6: Chemical test to distinguish : (b) Ethane and ethene: Sl. No. Test On adding a few drops of bromine solution in carbon 1. tetrachloride to the hydrocarbon On adding a few drops of alkaline potassium 2. permanganate (purple colour) to the hydrocarbon (c) Ethene and ethyne: Sl. No. Test On adding a few drops of 1. ammonical cuprous chloride to the hydrocarbon Ethane Ethene No change is observed The reddish brown colour gets decolorized No change is observed The purple colour fades. Ethene No change is observed Ethyne Red precipitate of copper acetylide is formed 2. On adding ammonical silver nitrate No observation White precipitate of silver acetylide is formed. Question 7: Name the products formed and write an equation when ethyne is added to the following in an inert solvent: (a) chlorine (b) bromine (c) iodine (d) hydrogen (e) excess of hydrochloric acid Solution 7: (a) Ethyne in an inert solvent of carbon tetrachloride adds chlorine to change into 1,2-dichloro ethene with carbon-carbon double bond, and then to an 1,1,2,2-tetrachloro ethane with carbon-carbon single bond. Cl2 Cl2 C2H2 C2H2Cl4 C2H2Cl2 1,2-dichloro ethene 1,1,2,2 -tetrachloro ethane (b) Ethyne in an inert solvent of carbon tetrachloride adds bromine to change into 1,2-dibromo ethene and then to 1,1,2,2 -tetrabromo ethane . Br2 Br2 C2H2 C2H2Br2 C2H2Br4 (c) Iodine reacts slowly in the presence of alcohol to form di-iodo ethene CH CH + I2 ICH = CHI 1,2-di-iodoethene (d) In the presence of nickel, platinum or palladium ethyne change to ethene and then to ethane. H2 H2 CH CH CH2 = CH2 CH3 CH3 Ni Ni Question 8: Name the hydrocarbon which; (a) is a tetrahedral molecule (b) is a planar molecule (c) is a linear molecule (d) forms a red precipitate with ammoniacal solution of copper (I) chloride (e) is known as paraffin (f) is known as olefin Solution 8: (a) The hydrocarbon which is tetrahedral is Methane. (b) The hydrocarbon which is planar molecule is ethene. (c) The hydrocarbon which is a linear molecule is Ethyne. (d) The hydrocarbon which forms a red precipitate with ammoniacal solution of copper chloride is acetylene. (e) Alkanes are also called as paraffin. (f) Alkenes are also called olefin. EXERCISE. 12 E Question 1: (a) what are alcohols? State their sources (b) give general formulae of monohydric alcohol Solution 1: (a) Alcohols are the hydroxyl derivatives of alkanes and are formed by replacing one or more hydrogen atoms of the alkane with OH group. Methanol is obtained from destructive distillation of wood while ethanol is obtained from fermentation of sugar. (b) General formula of monohydric alcohol: CnH2n+ 1OH Question 2: Give the (a) Dot diagram (b) Abbreviated formula (c) Structure of second member of the alcohol group. Solution 2: (a) Dot diagram (b) Abbreviated formula C2H5OH (c) Structure: H H | | H C O H | | H H Question 3: State the method of preparation of ethanol: (a) by hydrolysis of ethane, (b) by hydrolysis of alkyl halide Solution 3: (a) By hydrolysis of ethene: When concentrated sulphuric acid is added to ethene at a temperature of 80oC and pressure of 30 atm. ethyl hydrogen sulphate is produced. Ethyl hydrogen sulphate on hydrolysis with boiling water gives ethanol. 800 C C2H4 +H2SO4 C2H5HSO4 30atm C2H5HSO4 + H2O C2H5OH +H2SO4 (b) By hydrolysis of alkyl halide: Alcohols can be prepared by the hydrolysis of alkyl halide with a hot dilute alkali. boil C2H5Cl + KOH C2H5OH + KCl Question 4: How is ethanol prepared by fermentation? Solution 4: Ethanol is prepared by the fermentation of sugar by the enzymes invertase and zymase. Invertase C12H22O11 + H2O C6H12O6 + C6H12O6 Fermentation Glucose Fructose Zymase(yeast) C6H12O6 2C2H5OH + 2CO2 Ethanol Question 5: Give the lab. Prepared of: (a) ethyl alcohol (b) methyl alcohol Solution 5: (a) Ethyl alcohol: Ethyl chloride reacts with aqueous potassium hydroxide to form ethyl alcohol. boil C2H5Cl + KOH C2H5OH + KCl (b) Methyl alcohol: Methyl bromide reacts with aqueous potassium hydroxide to form methyl alcohol. boil CH3Br + KOH CH3OH Question 6: (a) how do the boiling point and melting point change in the homologous series of alcohols? (b) Name the product formed when ethanol reacts with acetic acid. Give an equation. (c) What is the name given to this type of reaction? Solution 6: (a) The melting and boiling point of the successive members of the homologous series of alcohols increase with the increase in molecular mass. (b) When ethanol reacts with acetic acid ethyl acetate is formed. Conc.H2SO4 C2H5OH + CH3COOH CH3COOC2H5 + H2O (c) This reaction is known as esterification reaction. Question 7: What is the effect ethanol on human body. Solution 7: Ethanol affects that part of the brain which controls our muscular movements and then gives temporary relief from tiredness. But it damages the liver and kidney too. Question 8: How are the following obtained (a) absolute alcohol (b) spurious alcohol (c) methylated spirit? Solution 8: (a) Absolute alcohol: Absolute alcohol may be obtained by distilling moist alcohol with benzene. The mixture of water and benzene distills off and anhydrous alcohol is left behind. (b) Spurious alcohol: It is made by improper distillation. It contains large portions of methanol in a mixture of alcohols. (c) Methylated spirit: Methylated spirit or denatured alcohol is ethyl alcohol with 5%methyl alcohol, a coloured dye and some pyridine. Question 9: Name the products formed and give appropriate chemical equations for the following: (a) sodium reacting with ethyl alcohol (b) Ethanol oxidized by acidified potassium dichromate Solution 9: (a) Sodium reacting with ethyl alcohol: 2C2H5OH + 2Na 2C2H5ONa + H2 When sodium reacts with ethyl alcohol hydrogen is evolved with formation of sodium ethoxide. (b) Ethanol oxidized by K2Cr2O7: [O] [O] C2H5OH CH3CHO + H2O CH3COOH Alcohols gets oxidized and get converted into ethanal and then into acetic acid. Question 10: Give the trivial (common) names and the IUPAC names of the following: (a) C3H6 (b) C2H4 (c) C2H2 (d) CH3OH (e) C2H5OH Solution 10: Sl. No 1 2 3 4 5 Formula C3H6 C2H4 C2H2 CH3OH C2H5OH Common Name Propylene Ethylene Acetylene Methyl alcohol Ethyl alcohol IUPAC Propene Ethene Ethyne Methanol Ethanol Question 11: Ethanol can be oxidized to ethanoic acid. Write the equation and name the oxidizing agent. Solution 11: [O] [O] C2H5OH CH3CHO+H2O CH3COOH The oxidizing agents that can be used are potassium dichromate and potassium permanganate. Question 12: Complete and balanced the following equations. State the conditions wherever necessary. (a) CH ||| + H2 . + H2 CH (b) C2H4 + Cl2 .. (c) C2H4 + HCl . (d) CaC2 + H2O . (e) C2H2 + Br2 [o] (f) C2H5OH . K Cr O 2 2 7 Solution 12: Ni Ni (a) CH CH + H2 CH2 = CH2 + H2 CH3 CH3 2000 C 2000 C (b) C2H4 + Cl2 CH2(Cl)-CH2(Cl) (c) C2H4 + HCl CH3-CH2Cl (d) CaC2 + 2H2O C2H2 + Ca(OH)2 (e) C2H2 + Br2 H(Br)C = C(Br)H [o] (f) C2H5OH CH3CHO K Cr O 2 2 7 Question 13: Name an organic compound which is: (a) used for illuminating country houses (b) Used for making a household plastic material (c) Called 'wood spirit' (d) Poisonous and contains OH group (e) Consumed as a drink (f) Made from water gas Solution 13: (a) Used for illuminating country houses : Ethyne (b) Used for making a household plastic material: ethyne (c) Called 'wood spirit' : Methanol (d) Poisonous: Methanol (e) Consumed as a drink: Ethanol (f) Made from water gas: Methanol EXERCISE. 12 F Question 1: What are carboxylic acids? Give their general formula Solution 1: An organic compound containing the carboxyl group(COOH) is known as carboxylic acid. The general formula: CnH2n+1COOH Question 2: Write the common name, IUPAC name and formula of one monocarboxylic acid and one dicarboxylic acid Solution 2: Monocarboxylic acid: Formula: HCOOH Common name: Formic acid IUPAC name: Methanoic acid Dicarboxylic acid: Formula: COOH-COOH Common name : Oxalic acid IUPAC name: Ethane-di-oic acid Question 3: Write the names of: (a) First three members of carboxylic acids series. (b) Three compounds that can be oxidized directly or in stages to produce acetic acid. Solution 3: (a) First three members of carboxylic acids are: Methanoic acid Ethanoic acid Propanoic acid (b) Three compounds that can be oxidized directly or in stages to produce acetic acid are: Ethanol Acetylene Ethanal Question 4: Vinegar in greyish in colour with a particular taste Explain. Solution 4: Vinegar commonly called Sirka is a dilute solution of acetic acid. The presence of colouring matter gives it a greyish colour while the presence of some other organic acids and organic compounds impart it the usual taste and flavour. Question 5: Give the structural formulae and IUPAC name of acetic acid. What is glacial acetic acid? Solution 5: Structural formula of acetic acid: H | H C C OH | || H O IUPAC name of acetic acid is: Ethanoic acid Glacial acetic acid is the pure form of acetic acid. It does not contain water. Question 6: Complete: (a) Vinegar is prepared by the bacterial oxidation of . (b) The organic acid present in vinegar is .. (c) The next higher homologue of ethanoic acid is Solution 6: (a) Ethanol (b) Acetic acid (c) Propanoic acid Question 7: How is acetic prepared from (a) ethanol (b) acetylene? Solution 7: (a) It is prepared in the lab by the oxidation of ethanol with acidified potassium dichromate. [O] [O] C2H5OH CH3CHO CH3COOH (b) Acetylene is first converted to acetaldehyde by passing through 40% H2SO4 at 60 C in the presence of 1% HgSO4. The acetaldehyde is then oxidised to acetic acid in the presence of catalyst manganous acetate at 70 C. H2SO4(dil) C2H2 + H2O CH3CHO HgSO4 CH3CHO + O 2CH3COOH Catalyst Question 8: What do you notice when acetic acid reacts with (a) litmus (b) metals (c) alkalies (d) alcohol Solution 8: (a) When acetic acid reacts with litmus it turns blue litmus red. (b) When acetic acid reacts with metals hydrogen is evolved. 2CH3COOH + Zn (CH3COO)2Zn + H2 (c) When acetic acid reacts with alkalies it forms salt CH3COOH + NaOH CH3COONa + H2O (d) Acetic acid reacts with alcohols forming esters H2SO4 CH3COOH + C2H5OH CH3COOC2H5 + H2O Question 9: Acetic acid is a typical acid. Write one equation in each case for its reactions with (a) a metal (b) a base / alkali (c) a carbonate (d) a bicarbonate Solution 9: (a) 2CH3COOH + Zn (CH3COO)2Zn + H2 (b) CH3COOH + NaOH CH3COONa + H2O (c) 2CH3COOH + Na2CO3 2CH3COONa +H2O+ CO2 (d) CH3COOH + NaHCO3 CH3COONa + H2O +CO2 Question 10: Name: (a) compound formed when acetic acid and ethanol react together (b) reducing agent used to convert acetic acid into ethanol (c) substance used to change acetic acid to acetic anhydride. Solution 10: (a) When acetic acid and ethanol react it results in the formation of ethyl acetate. (b) Lithum aluminium hydride(LiAlH4) is used to convert acetic acid to ethanol. (c) Phosphorous pentoxide(P2O5) is heated along with acetic acid to form acetic anhydride. Question 11: Give two tests to show that CH3COOH is acidic in nature. Solution 11: Test to show that CH3COOH is acidic are: When litmus test is done, it turns blue litmus red. It react with bases to form salt and water. Question 12: What do you observe when acetic acid is added to: (a) sodium bicarbonate (b) ethyl alcohol in the presence of sulphuric acid (c) neutral FeCl3 solution? Solution 12: (a) When acetic acid is added to sodium bicarbonate, carbondioxide is liberated. CH3COOH + NaHCO3 CH3COONa + H2O + CO2 (b) When acetic acid is added to ethyl alcohol in presence of sulphuric acid ester (ethyl acetate) is formed. H2SO4 CH3COOH + C2H5OH CH3COOC2H5 + H2O (c) When acetic acid is added to neutral FeCl3, wine red color is produced. MISCELLANEOUS: Question 1: Draw structural formula for each of the following compounds: (a) isomer of n-butane (b) vinegar (c) 2-propanol (d) ethanal (e) acetone (f) diethyl ether What is used to describe these compounds taken together? Solution 1: (a) Ethane: H H | | H C C H | | H H (b) Vinegar (c) Marsh gas H | H C H | H (d) (e) These compounds are called organic compounds. Question 2: (a)What is the special feature of the structure of: (i) C2H4 (ii) C2H2 (b) what type of reaction is common to both these compounds? Why methane does not undergo this type of reaction. Solution 2: (a) (i) (ii) H C C H They both are unsaturated compound. The structure (i) contains double bond where as structure (ii) contains triple bond. (b) Both the compounds undergo addition reactions. Question 3: Give the names and structural formula of: (a) saturated hydrocarbon (b) unsaturated hydrocarbon Which type of reaction will they undrgo? Solution 3: (a) Saturated hydrocarbon Name Structural formula Methane Ethane Propane Butane (b) Unsaturated hydrocarbon: Name Structural formula Ethene Propene Ethyne Propyne The Saturated hydrocarbons undergo substitution reactions whereas unsaturated hydrocarbons undergo addition reactions. Question 4: (a) Write an equation for the laboratory preparation of (i) an unsaturated hydrocarbon from calcium carbide. (ii) an alcohol from ethyl bromide. (b) What would you see, when ethyne is bubbled through a solution of bromine in carbon tetrachloride? (c) Name the addition product formed between ethene and water. Solution 4: (a) CaC2 + 2H2O Ca(OH)2 + C2H2 (b) When bromine in carbon tetrachloride is added to ethyne, the orange colour of the bromine disappears due to the formation of the colourless ethylene bromide. (c) Water reacts with ethene to form ethanol. H C2H5OH CH2=CH2 +H2O Question 5: Choosing only words from the following list, write down appropriate words to fill in the blanks from (a) to (e) given below. Addition, carbohydrates, CnH2n-2, CnH2n, CnH2n+2, electrochemical homologous, hydrocarbon, saturated, substitution, unsaturated. The alkanes form an (a) ___________ series with the general formula (b) __________ The alkanes are (c____________ (d)__________ which generally undergo (e) ________ reactions. Solution 5: The alkanes form an (a) Homologous series with the general formula (b) CnH2n+2. The alkanes are (c) saturated (d) hydrocarbon which generally undergo (e) substitution reactions. Question 6: Ethanol can be converted into ethene which can be changed into ethane. Choose the correct word or phrase from the brackets to complete the following sentences. (a) The conversion of ethanol into ethene is an example of ___________ (b) Converting ethanol into ethene requires the use of ___________ (c) The conversion of ethene into ethane is an example of ___________ (d) The catalyst used in the conversion of ethene into ethane is commonly ___________ Solution 6: (a) The conversion of ethanol into ethene is an example of Dehydration. (b) Converting ethanol into ethene requires the use of Conc. H2SO4. (c) The conversion of ethene into ethane is an example of hydrogenation. (d) The catalyst used in the conversion of ethene into ethane is commonly nickel. Question 7: Give reasons: (a) ethyne is more reactive than ethene (b) Ethene is more reactive than ethane (c) Hydrocarbons are excellent fuels Solution 7: (a) Ethyne is a highly reactive compound than ethene because of the presence of a triple bond between its two carbon atoms. (b) Ethene is a highly reactive compound than ethane because of the presence of a double bond between its two carbon atoms. (c) Hydrocarbons such as alkanes undergo combustion reactions with oxygen to produce carbon dioxide and water vapour. Alkanes are flammable which makes them excellent fuels. Methane for example is the principal component of natural gas. CH4 + 2O2 CO2 + 2H2O Question 1(2004): Write balanced equation when ethane is burnt in air. Solution 1(2004): 2C2H6 + 7O2 4CO2 + 6H2O Question 2(2004): (a) Write the equation for the preparation of ethylene from ethyl alcohol (b) Write the general formula for a saturated hydrocarbon and give one example of a saturated hydrocarbon with its structural formula (c) Name a compound which will give acetylene gas when treated with water. Solution 2(2004): Conc.H2SO4 (a) C2H5OH CH2 = CH2 + H2O 170O C (b) General formula of saturated hydrocarbon is: CnH2n+2 Example: CH4 H | H C H | H (c) Calcium carbide reacts with water to give acetylene gas. Question 1(2005): Draw the structural formula of a compound with two carbon atoms in each of the following cases (a) An alkane with a carbon to carbon single bond (b) An alcohol containing two carbon atoms (c) An unsaturated hydrocarbon with a carbon to carbon triple bond. Solution 1(2005): (a) An alkane is ethane H H | | H C C H | | H H Ethane (b) The alcohol is ethanol H H | | H C C O H | | H H (c) An unsaturated hydrocarbon is ethyne H C C H Question 2(2005): Ethane, Ethene, ethanoic acid, Ethyne, Ethanol From the box, name (a) The compound with OH as the part of its structure. (b) The compound with COOH as the part of its structure. (c) Homologue of Homologous series with general formula CnH2n. Solution 2(2005): (a) Ethanol (b) Ethanoic acid (c) Ethene Question 3(2005): Write the equations for the following lab. Preparations: (a) Ethane from sodium propionate, (b) Ethene from Iodoethane (c) ethyne from calcium carbide (d) Methanol from Iodomethane. Solution 3(2005): (a) Ethane from sodium propionate CaO C2H5COONa + NaOH Na2CO3 + C2H6 300 C (b) Ethene from iodoethane C2H5 I +KOH(alcoholic) C2H4 +KI + H2O (c) Ethyne from calcium carbide CaC2 +2H2O Ca(OH)2 + C2H2 (d) Methanol from iodoethane CH3l+ NaOH CH3OH + Nal Question 1(2006): Give the correct IUPAC name and the functional group for each of the compounds whose structural formulae are given below: H H O | | || (a) H C C C H | | H H H H H | | | (b) H C C C O H | | | H H H Solution 1(2006): (a) IUPAC name: Propanal Functional group: -CHO (b) IUPAC name: Propanol Functional group: -OH Question 2(2006): (a) write the equation for the preparation of carbon tetrachloride from methane . (b) draw the structural formula of ethyne (c) How is the structure of alkynes different from that of alkenes? Solution 2(2006): (a) Preparation of carbon tetrachloride from methane: Difused sunlight CH4+Cl2 CH3Cl +HCl Or 600k CH3Cl + Cl2 CH2Cl2 +HCl CH2Cl2 +Cl2 CHCl3 +HCl CHCl3 + Cl2 CCl4 +HCl (b) Structural formula of ethyne: H C C H (c) Alkynes contain triple bond where as alkenes contain double bond. Question 3(2006): Fill in the blanks with the correct words from the brackets: Alkenes are the (a) ___________ series of (b) ___________ hydrocarbons. They differ from alkanes due to presence of (c) ___________ bonds. Alkenes mainly undergo (d) ___________ reactions. Solution 3(2006): Alkenes are the (a) homologous series of (b) unsaturated hydrocarbons. They differ from alkanes due to presence of (c) single bonds. Alkenes mainly undergo (d) addition reactions. Question 4(2006): (a) draw the structural formulae of the two isomers of Butane. Give the correct IUPAC name of each isomer. (b) State one use of acetylene. Solution 4(2006): (a) Structural formulae of isomers of Butane are: H H H H | | | | H C C C C H | | | | H H H H Butane 2-methyl propane (b) Use of acetylene: For Oxy-acetylene welding at very high temperatures. Question 1(2007): Give the IUPAC names of the following compounds numbered (i) to (v). The IUPAC names of the compounds on the left are to guide you for giving the correct IUPAC names of the compounds on the right. H H H H | | | | H C C C | H C C C H | | H H Propene H H H H H | | | | H (i) ______________________ H H H H H | H C C C C C H | | | | | H H H O H | | | | H C C C C C H | | | | | H H O H H H Pentan 2 ol _____________________________ | H (ii) H | H C H H | H | | | H C C C H | | | H | H H C H | H H H | | | H C C C H | | | H | H H C H | H H 2, 2-dimethylpropane (iii) ___________________________ H | H O | || H C C | | H OH H O | || H C C C | | | H H OH Propanoic acid _______________________________ H H | | H C C H | | Br Br 1, 20dibromoethane Solution 1 (2007): H | H C C C H | H (i) Propyne H | H H O H H | | | | | H C C C C C H | | | | | H H H H H (ii) Pentan-3-ol (iv) H H | | H C C H | | CI CI (v) _______________________ (iii) 2- methyl propane (iv) Ethanoic acid (v) 1,2-dichloroethane Question 2(2007): Copy and complete the following table which relates to three homologous series of hydrocarbons: General Formula Cn H 2n Cn H 2n-2 Cn H2n+2 IUPAC name of the homologous series Characteristic bond type Single Bond IUPAC name of the first member of the series Type of reaction with chlorine Addition Solution 2(2007): The homologous series of hydrocarbons are: General Formula CnH2n IUPAC name of the homologous series Alkenes Double Characteristics bond type bond IUPAC name of the first member of the series Ethene Type of reaction with chlorine Addition CnH2n-2 Alkynes CnH2n+2 Alkanes Triple Bond Single Bond Ethyne Addition Methane Substitution Question 1a(2008): (a) Name the organic compound prepared by each of the following reactions: (i) C2H5COONa + NaOH (ii) CH3I + 2[H] (iii) C2H5Br + KOH (alcoholic solution) (iv) CO + 2H2 (zinc oxide catalyst) (v) CaC2 + 2H2O Solution 1a(2008): CaO (i) C2H5COONa + NaOH Na2CO3 + C2H6 3000 C (ii) CH3I + 2[H] CH4 +HI (iii) C2H5Br + KOH C2H4 + KBr + H2O (iv) CO + 2H2 CH3OH (v) CaC2 + 2H2O Ca(OH)2 + C2H2 Question 1b(2008): Write the equations for the following reactions: (i) calcium carbide and water (ii) ethene and water (steam) (iii) Bromoethane and an aqueous solution of sodium hydroxide. Solution 1b(2008): (i) Calcium carbide and water: CaC2 + 2H2O Ca(OH)2 + C2H2 (ii) Ethene and water: H C2H5OH CH2 = CH2 + H2O (iii) Bromoethane and aqueous solution of sodium hydroxide C2H5Br + NaOH C2H5OH + NaBr Question 1c(2008): Distinguish between the saturated hydrocarbon ethane and the unsaturated hydrocarbon ethene by drawing their structural formulae. Solution 1c(2008): Ethane Ethene It has carbon -carbon single bond. It is saturated. Alkanes undergo substitution reaction. It has carbon-carbon double bond It is unsaturated Alkenes undergo addition reaction. Question 1d(2008): Addition reactions and substitution reactions are types of organic reactions. Which type of reaction is shown by: (i) ethane (ii) ethane? Solution 1d(2008): (i) Ethane undergoes substitution reaction. (ii) Ethene undergoes addition reactions. Question 1e(2008): (i) write the equation for the complete combustion of ethane (ii) Using appropriate catalysts, ethane can be oxidized to an alcohol, an aldehyde and an acid. Name the alcohol, aldehyde and acid formed when ethane is oxidized. Solution 1e(2008): (i) 2C2H6 + 7O2 4CO2 + 6H2O (ii) Ethane can be oxidized as follows: When a mixture of ethane and oxygen in the ratio 9:1 by volume is compressed to about 120 atm pressure and passed over copper tubes at 475K, ethyl alcohol is formed. 120 atm 2C2H6 + O2 2C2H5OH Cutubes 475k When a mixture of ethane and oxygen is passed through heated MoO, the mixture is oxidized to ethanal. MoO C2H6 + O2 CH3CHO + H2O When a manganese based catalyst is used 100oC, ethane can be oxidized to ethanoic acid. Mn Compound 2C2H6 + 3O2 2CH3COOH + 2H2O Question 1f(2008): (i) Why is pure acetic acid known as glacial acetic acid? (ii) what type of compound is formed by the reaction between acetic acid and an alcohol? Solution 1f(2008): (i) Pure acetic acid on cooling forms crystalline mass resembling ice and for this reason it is called glacial acetic acid. (ii) When acetic acid reacts with alcohol, ester is formed. Conc.H2SO4 CH3COOH + C2H5OH CH3COOC2H5 + H2O INTEXT 1 Question 1: (a) What do you understand by organic chemistry? (b) What is vital force theory? Why was it discarded? Solution 1: (a) Organic chemistry may be defined as the chemistry of hydrocarbons and its derivatives. (b) Vital Force Theory is a theory made by the Scientist Berzelius in 1809 which assumed that organic compounds are only formed in living cells and it is impossible to prepare them in laboratories. It was discarded because Friedrich Wohler showed that it was possible to obtain an organic compound (urea) in the laboratory. Question 2: (a) Name a few sources of organic chemistry (b) give the various applications of organic chemistry Solution 2: (a) Few sources of organic compounds are: Plants Animals Coal Petroleum Wood (b) The various applications of organic chemistry is: It is used in the production of soaps, shampoos, powders and perfumes. Various fuels like natural gas, petroleum are also organic compounds. The fabrics that we use to make various dresses are also made from organic compounds. Question 3: Organic chemistry plays a key role in all walks of life. Discuss Solution 3: Organic compounds are present everywhere. They are present in: It is present in the production of soaps, shampoos, powders and perfumes. It is present in the food we eat like carbohydrates, proteins, fats, vitamins etc. Fuel like natural gas, petroleum are also organic compounds. Medicines, explosives, dyes, insecticides are all organic compounds. Thus we can say that organic compounds play a key role in all walks of life. Question 4: Carbon shows some unique properties, name them Solution 4: The unique properties shown by carbon are: Tetravalency of carbon Catenation Isomerism Question 5: Explain the following: (a) Tetravalency (b) Catenation Solution 5: (a) Tetravalency: Carbon can neither lose nor gain electrons to attain octet. Thus it shares four electrons with other atoms. This characteristics of carbon by virtue of which it forms four covalent bonds, is called Tetravalency of carbon. In structural form : (b) Catenation: The property of self -linking of atoms of an element through covalent bonds in order to form straight chains, branched chains and cyclic chains of different sizes is known as catenation. Carbon- carbon bond is strong so carbon can combine with other carbon atoms to form chains or rings and can involve single, double and triple bonds. Question 6: Write any four properties of organic compounds that distinguish them from inorganic compounds. Solution 6: Four properties of organic compound that distinguish them from inorganic compounds are: (i) Presence of carbon. (ii) Solubility in the organic solvents. (iii) Forming of covalent bonds. (iv) Having low melting and boiling points. Question 7: Why are organic compounds studies as a separate branch of chemistry? Solution 7: Due to the unique nature of carbon atom, it gives rise to formation of large number of compounds. Thus this demands a separate branch of chemistry. Question 8: What are hydrocarbons? Compare saturated and unsaturated hydrocarbons? Solution 8: Hydrocarbons are compounds that are made up of only carbon and hydrogen. Comparison of saturated and Unsaturated hydrocarbons: Saturated Hydrocarbon Unsaturated Hydrocarbon 1. Carbon atoms are joined only by Carbon atoms are joined by double single bonds. or by triple bonds. 2. They are less reactive due to the They are more reactive due to non-availability of electrons in the presence of electrons in the double single covalent bond. or the triple bond. 3. They undergo substitution reaction. They undergo addition reaction. Question 9: Give reason for the existence of the large number of organic compounds. Solution 9: Due to presence of unique properties of carbon like Tetravalency, catenation and Isomerism large number of organic compounds are formed. Question 10: Give at least one example in each case to show structure of isomers of: (a) single bond compound (b) double bond compound (c) triple bond compound Solution 10: (a) Single Bond compound: For example: In pentane CH 3 CH 2 CH 2 CH 2 CH 3 n pen tan e (b) Double bond compound: For example:- In pentene CH 2 CH CH 2 CH 2 CH 3 1 pentene CH 3 CH CH CH 2 CH 3 2 pentene CH 2 C CH 2 CH3 | CH3 isopentene CH 2 C CH 2 CH 3 | CH 3 isopentene (c) Triple bond compound: In case of Hexyne: Question 11: Name a compound of each type and draw the figure. (a) Cyclic compound with single bond (b) Cyclic compound with triple bond. Solution 11: (a) Cyclic compound with single bond: cyclopentane Structure: (b) Cyclic compound with triple bond: cyclopentyne Structure: Question 12: Give the name of one member of each of the following: (a) saturated hydrocarbons (b) unsaturated hydrocarbons Solution 12: The member of each of the following is: (a) Saturated Hydrocarbon: Hexane (C6H14) (b) Unsaturated Hydrocarbon: Hexene (C6H12) Question 13: Define substitution and addition reaction. Solution 13: Substitution reaction: A reaction in which one atom of a molecule is replaced by another atom (or group of atoms) is called a substitution reaction. Addition reaction: A reaction involving addition of atom(s) or molecules(s) to the double or the triple bond of an unsaturated compound so as to yield a saturated product is known as addition reaction. Question 14: Define or explain chain isomerism and position isomerism with examples in each case. Solution 14: Chain isomerism Chain isomerism arises due to the difference in arrangement of C atoms in the chain. For example, there are two isomers of butane, C4H10. In one of them, the carbon atoms lie in a "straight chain" whereas in the other the chain is branched. CH3 CH3 CH 2 CH 2 CH3 | CH3 CH CH3 Position isomerism It is due to the difference in position of functional groups. For example, there are two structural isomers with the molecular formula C3H7Br. In one of them, the bromine atom is on the end of the chain, whereas in the other it is attached in the middle. CH 3 CH CH 3 CH 3 CH 2 CH 2 Br | 1- bromopropane Br 2 bromopropane Question 15: (a) Define the term isomerism. State two main causes of isomerism. (b) draw the chain isomers of hexane (C6H12) (c) Draw position isomers of butane (C4H8) Solution 15: (a)Isomerism: Compounds having the same molecular formula but different structural formula are known as isomers and the phenomenon as isomerism. Two main causes of isomerism are: Difference in mode of linking of atoms. Difference in the arrangement of atoms or groups in space. (b) (c) CH2=CHCH2CH3 1-butene H3C-CH=CHCH3 2-butene Question 16: Define a functional group and give the structural formula of the following: (a) Ketone, (b) alcohols (c) aldehydes. Solution 16: A functional group is an atom or a group of atoms that defines the structure (or the properties of a particular family) of organic compounds. The structural formula of (a) Halides :- R-X Example: H | H C CI | H (b) Alcohols:- R-OH Example: H | H C OH | H (c) Aldehydes:- R-CH=O Example: Question 17: Identify the functional groups of the following: (a) CH3OH (b) HCHO (c) CH3COOH Solution 17: The functional group present in the following compounds are: (a) CH3OH :- Alcohol (b) HCHO:- Aldehyde (c) CH3COOH:- Carboxyl Question 18: What will be the formula and structure of benzene? Solution 18: Formula of benzene :C6H6 Structure of benzene: Question 19: Which part of an organic compound determines (i) physical properties (ii) chemical properties? Solution 19: (i) Physical properties: The alkyl group determines the physical properties. (ii) Chemical properties: The functional group is responsible for the chemical properties. Question 20: Name the alkyl radical and the functional group of the following organic compounds: (a) CH3OH (b) C2H5OH (c) C3H7CHO (d) C4H9COOH Solution 20: The alkyl radical and the functional group are: Sl. No a b c d Formula CH3OH C2H5OH C3H7CHO C4H9COOH Name of alkyl radical Methyl Ethyl Propyl Butyl Name of Functional group Alcohol Alcohol Aldehyde Carboxyl Question 21: (a) What is an alkyl group? (b) Give the names of any three alkyl radicals. How are they formed? Solution 21: (a) An alkyl group is obtained by removing one atom of hydrogen from an alkane molecule. Alkyl group is named by replacing the suffix 'ane' of the alkane with the suffix -yl. (b) The name of three alkyl radicals are: Methyl Ethyl Propyl They are formed by removing 1 hydrogen from an alkane. CH4 CH3 + H+ Methyl CH3 CH3 CH3 CH2 - + H+ Ethyl CH3 CH2 CH3 CH3 CH2 CH2 - + H+ Propyl Question 22: Give the names and the structural formula of the first three members of the homologous series of alkanes. Solution 22: The names and the structural formula of first three members of the homologous series of alkane are: (i) H | H C H | H methane (CH 4 ) (ii) C2H6 Ethane H H | | H C C H | | H H ethane (C 2 H 6 ) (iii) C3H8 Propane H H H | | | H C C C H | | | H H H propane (C3H8 ) Question 23: (a) What is homologous series? (b) What is the difference in the molecular formula of any two adjacent homologues: (i) in terms of molecular mass, (ii) in terms of number and kind of atoms per molecule? Solution 23: (a) A homologous series is a group of organic compounds having a similar structure and similar chemical properties in which the successive compounds differ by a CH2 group. (b) The difference in molecular formula of any two adjacent homologues is (i) It differs by 14 a.m.u in terms of molecular mass. (ii) It differs by three atoms. The kind of atoms it differs is one carbon and two hydrogen.

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

Formatting page ...

 

  Print intermediate debugging step

Show debugging info


 

 

© 2010 - 2025 ResPaper. Terms of ServiceContact Us Advertise with us

 

l_2345 chat