Formatting page ...
XII PHYSICS THEORY PAPER Solutions (v) Q.1. A. M.C.Q. : (i) (A) q (ii) (D) All of these (iii) (A) Speed remains constant (D) n = 2 to n = 1 (v) (C) Fringe width decreases (ii) Zero When no current is drawn from a cell by the electric circuit OR Open circuit (iii) e=L di dt 2=L (10 0) 0.40 L= (iv) a1 + a2 2 = a1 a2 1 a1 3 = a2 1 0.40 2 = 0.08 H 10 I1 1 a21 9 = = = I2 2 a22 1 High: retentivity coercivity,susceptibility (x) (i) (ii) (iii) (xi) c or 90 perpendicular to each other 2 (vii) 2D (viii) A telescope is said to be in normal adjustment when it forms the final image of a distance object at infinity. 2 Imax (a1 + a2) 4 (ix) = = Imin (a1 a2)2 1 (vi) (iv) B. (i) Interference Due to superposition of light waves from two coherent sources. Fringes may or may not be of same width. All bright fringes are of same intensity. = Pavg = Irms Vrms cos R = 1.5 200 Z 4 = 300 5 = 240 W Diffraction (i) Due to interference of secondary wavelets coming from different points of same wavefront. (ii) Fringes are never of same width. (iii) Intensity of successive bright fringes goes on decreasing. E 42 eV = c 3 108 SECTION A Q.2. 42 1.6 10 19 = 8 3 10 27 = 22.4 10 (a) kg m/s or Js/m (xii) Electromagnetic waves are produced by accelerated charged particles while matter waves are associated with moving particles irrespective of charge on it.OR EM waves do not medium while matter waves need. (xiii) Lyman series (xiv) Emitter base : Forward biased : electric field intensity due to (+q) E2 : electric field intensity due to ( q) Pt. O : centre of dipole AB Pt. P : point where electric field intensity is to be calculated Collector base : Reverse biased (xv) E1 It indicates the stability of the nucleus. 1
|
