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ICSE Class X Board Exam 2017 : Chemistry

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JEE(Advanced) 2019/Paper-2 FINAL JEE(Advanced) EXAMINATION - 2019 (Held On Monday 27th MAY, 2019) PAPER-2 TEST PAPER WITH ANSWER & SOLUTION PART-2 : CHEMISTRY A LL EN SECTION-1 : (Maximum Marks: 32) This section contains EIGHT (08) questions. Each question has FOUR options. ONE OR MORE THAN ONE of these four option(s) is (are) correct answer(s). For each question, choose the option(s) corresponding to (all) the correct answer(s) Answer to each question will be evaluated according to the following marking scheme: Full Marks : +4 If only (all) the correct option(s) is (are) chosen. Partial Marks : +3 If all the four options are correct but ONLY three options are chosen. Partial Marks : +2 If three or more options are correct but ONLY two options are chosen and both of which are correct. Partial Marks : +1 If two or more options are correct but ONLY one option is chosen and it is a correct option. Zero Marks : 0 If none of the options is chosen (i.e. the question is unanswered). Negative Marks : 1 In all other cases. For example, in a question, if (A), (B) and (D) are the ONLY three options corresponding to correct answers, then choosing ONLY (A), (B) and (D) will get +4 marks; choosing ONLY (A) and (B) will get +2 marks; choosing ONLY (A) and (D) will get +2 marks; choosing ONLY (B) and (D) will get +2 marks; choosing ONLY (A) will get +1 marks; choosing ONLY (B) will get +1 marks; choosing ONLY (D) will get +1 marks; choosing no option (i.e. the question is unanswered) will get 0 marks, and choosing any other combination of options will get 1 mark. 1. The cyanide process of gold extraction involves leaching out gold from its ore with CN in the presence of Q in water to form R. Subsequently, R is treated with T to obtain Au and Z. Choose the correct option(s). (1) T is Zn (2) R is [Au(CN)4] (3) Z is [Zn(CN)4]2 (4) Q is O2 Ans. (1,3,4) JEE(Advanced) 2019/Paper-2/Held on Monday 27 th May, 2019 1 JEE(Advanced) 2019/Paper-2 Sol. 4Au(s) + 8CN (aq) + 2H2O(aq) + O2(g) 4[Au(CN)2] (aq) + 4OH (aq) (Q) 2[Au(CN)2] (aq) + Zn(s) [Zn (CN)4]2 (aq) + 2Au(s) (R) 2. (T) (Z) Which of the following reactions produce(s) propane as a major product? (1) H3C COONa + H2O (2) H3C COONa (3) H3C electrolysis NaOH, CaO, D Cl Zn, dil. HCl Br Zn Br (4) H3C A LL EN Ans. (2,3) electrolysis Sol. CH3 CH2 CH2 CO2Na + H2O n-hexane NaOH + CaO CH3 CH2 CH3 CH3 CH2 CH2 CO2Na D dil. HCl CH3 CH2 CH2 Cl + Zn CH3 CH2 CH2 ZnCl CH3CH2CH3 Br 3. dehalogenation Br + Zn The ground state energy of hydrogen atom is 13.6 eV. Consider an electronic state Y of He+ whose energy, azimuthal quantum number and magnetic quantum number are 3.4 eV, 2 and 0 respectively. Which of the following statement(s) is(are) true for the state Y? (1) It has 2 angular nodes (2) It has 3 radial nodes (3) It is a 4d state (4) The nuclear charge experienced by the electron in this state is less than 2e, where e is the magnitude of the electronic charge. Ans. (1,3) -13.6 4 n2 n=4 Sol. # 3.4 = # l=2 # m=0 Angular nodes = l = 2 Radial nodes = (n l 1) = 1 n l = 4d state 2 JEE(Advanced) 2019/Paper-2/Held on Monday 27 th May, 2019 JEE(Advanced) 2019/Paper-2 4. Choose the correct option(s) that give(s) an aromatic compound as the major product. UV, 500K + Cl 2 (excess) (1) H3C (2) i) alc.KOH ii) NaNH 2 Br iii) red hot iron tube,873 K Br Br NaOEt (3) NaOMe (4) A LL EN Ans. (2,4) Cl Sol. (1) + Cl2 (excess) H3C (2) Br Uv 500 K Cl Cl Cl Cl Cl CH3 Re d hot iron tube873K i) alc. KOH Br CH3 C CH ii) NaNH 2 Br (3) (Non aromatic) + NaOEt EtO (Substitution product) H 3C CH3 (Aromatic) Dimerise (Elimination product) (Non aromatic) (Non aromatic) Na (4) NaOMe + + MeOH (Aromatic ion) JEE(Advanced) 2019/Paper-2/Held on Monday 27 th May, 2019 3 JEE(Advanced) 2019/Paper-2 5. Consider the following reactions (unbalanced) Zn + hot conc. H2SO4 G + R + X Zn + conc. NaOH T + Q G + H2S + NH4OH Z (a precipitate) + X + Y Choose the correct option(s). (1) The oxidation state of Zn in T is +1 (2) Bond order of Q is 1 in its ground state (3) Z is dirty white in colour A LL EN (4) R is a V-shaped molecule Ans. (2,3,4) Sol. Zn + 2H2SO4 (Hot and conc.) ZnSO4 + SO2 + 2H2O (G) (R) (X) Zn + 2NaOH (conc.) Na2ZnO2 + H2 (T) (Q) ZnSO4 + H2S + 2NH4OH ZnS + 2H2O + (NH4)2SO4 (Z) 6. (X) (Y) With reference to aqua regia, choose the correct option(s). (1) Reaction of gold with aqua regia produces NO2 in the absence of air (2) Aqua regia is prepared by mixing conc. HCl and conc. HNO3 in 3 : 1 (v/v) ratio (3) Reaction of gold with aqua regia produces an anion having Au in +3 oxidation state (4) The yellow colour of aqua regia is due to the presence of NOCl and Cl2 Ans. (2,3,4) Sol. (1) Au + HNO3 + 4HCl AuCl41 + H3O+ + NO + H2O (2) Aqua regia = 3HCl(conc.) + HNO3(conc.) (3) AuCl41 is produced (4) Yellow colour of aqua regia is due to it's decomposition into NOCl(orange yellow) and Cl2(greenish yellow). 4 JEE(Advanced) 2019/Paper-2/Held on Monday 27 th May, 2019 JEE(Advanced) 2019/Paper-2 7. Choose the correct option(s) from the following (1) Natural rubber is polyisoprene containing trans alkene units (2) Nylon-6 has amide linkages (3) Cellulose has only a-D-glucose units that are joined by glycosidic linkages (4) Teflon prepared by heating tetrafluoroethene in presence of a persulphate catalyst at high pressure Ans. (2,4) Sol. 1. Natural rubber is polyisoprene containing cis alkene units 2. Nylon-6 has amide linkage [ HN (CH2)5 C ]n O A LL EN 3. Cellulose has only b-D glucose units. Per sulphate [ CF2 CF2 ] n 4. F2C = CF2 8. Choose the correct option(s) for the following reaction sequence CHO i)Hg2+ , dil.H2SO4 ii)AgNO3 , NH 4OH iii)Zn -Hg, conc. HCl Zn -Hg i)SOCl2 pyridine conc. HCl Q R S ii) AlCl 3 MeO Consider Q, R and S as major products OH CO2H (1) MeO MeO Q S CO2H (2) MeO MeO Q (3) MeO R (4) MeO R O O R O MeO S MeO S JEE(Advanced) 2019/Paper-2/Held on Monday 27 th May, 2019 5 JEE(Advanced) 2019/Paper-2 Ans. (2,4) C CH2 CH2 CH = O Sol. C C CH2 CH = O 2+ Hg H SO 2 MeO MeO O 4 AgNO3 + NH4OH C CH2CH2 CO2 MeO O Zn(Hg) + conc. HCl CH2CH2CH2 CO2H MeO A LL EN SOCl2 + pyridine AlCl3 (R) MeO O Zn(Hg) + conc. HCl MeO (S) SECTION-2 : (Maximum Marks: 18) This section contains SIX (06) questions. The answer to each question is a NUMERICAL VALUE. For each question, enter the correct numerical value of the answer using the mouse and the on-screen virtual numeric keypad in the place designated to enter the answer. If the numerical value has more than two decimal places, truncate/round-off the value to Two decimal places. Answer to each question will be evaluated according to the following marking scheme: 1. Full Marks : +3 If ONLY the correct numerical value is entered. Zero Marks : 0 In all other cases. D The decomposition reaction 2N2O5(g) 2N2O4(g) + O2(g) is started in a closed cylinder under isothermal isochoric condition at an initial pressure of 1 atm. After Y 103 s, the pressure inside the cylinder is found to be 1.45 atm. If the rate constant of the reaction is 5 10 4 s 1, assuming ideal gas behavior, the value of Y is ___ Ans. (2.30) 6 JEE(Advanced) 2019/Paper-2/Held on Monday 27 th May, 2019 JEE(Advanced) 2019/Paper-2 Sol. D 2N2O5(g) 2N2O4(g) + O2(g) at constant V, T t=0 1 t = y 103 sec (1 2P) 2P P PT = (1 + P) = 1.45 P = 0.45 atm 1 (2K)t = 2.303 log 1 - 2P (2 5 10 4) y 103 = 2.303 log 1 0.1 y = 2.303 = 2.30 2. Total number of isomers, considering both structural and stereoisomers, of cyclic ethers with the molecular A LL EN formula C4H8O is ___ Ans. (10.00) O Sol. * , (1) 3. O , (2) (R + S) O O O, (1) * (2) (R + S) , O * * (3) R,R R,S S,S , (1) The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc.HNO3 to a compound with the highest oxidation state of sulphur is ___ (Given data : Molar mass of water = 18 g mol 1) Ans. (288.00) Sol. S8 + 48 HNO3 8H2SO4 + 48NO2 + 16H2O 1 mole of rhombic sulphur produce 16 mole of H2O i.e. 288 gm of H2O JEE(Advanced) 2019/Paper-2/Held on Monday 27 th May, 2019 7 JEE(Advanced) 2019/Paper-2 4. Total number of cis N Mn Cl bond angles (that is, Mn N and Mn Cl bonds in cis positions) present in a molecule of cis-[Mn(en)2Cl2] complex is ____ (en = NH2CH2CH2NH2) Ans. (6.00) cis[M(en)2Cl2] Sol. N (1) N(2) Cl (a) Mn Cl (b) N(3) N(4) Cl(a) Mn N(1) Cl(a) Mn N(2) Cl(a) Mn N(4) Cl(b) Mn N(1) Cl(b) Mn N(3) Cl(b) Mn N(4) Number of cis (Cl Mn N) = 6 Total number of hydroxyl groups present in a molecule of the major product P is ___ A LL EN 5. i) H2 , Pd - BaSO 4 , quinoline P ii) dil. KMnO (excess), 273 K 4 Ans. (6.00) Sol. H2 / Pd - BaSO4 Quinoline CH2 CH2 C=C H H dil. KMnO4 (excess) 273 K HO HO OH CH2 CH2 C C H OH OH H total 6 OH group present in a molecule of the major product. 8 JEE(Advanced) 2019/Paper-2/Held on Monday 27 th May, 2019 OH JEE(Advanced) 2019/Paper-2 6. The mole fraction of urea in an aqueous urea solution containing 900 g of water is 0.05. If the density of the solution is 1.2 g cm 3, the molarity of urea solution is ___ (Given data : Molar masses of urea and water are 60 g mol 1 and 18 g mol 1, respectively) Ans. (2.98 or 2.99) n n + 50 19n = 50 Sol. Xurea = 0.05 = n = 2.6315 Vsol = (2.6315 60 + 900) = 881.5789 ml 1.2 2.6315 1000 = 2.9849 881.5789 Molarity = 2.98M Molarity = A LL EN SECTION 3 : (Maximum Marks : 12) This section contains TWO (02) List-Match sets. Each List-Match set has Two (02) Multiple Choice Questions. Each List-Match set has two lists : List-I and List-II List-I has Four entries (I), (II), (III) and (IV) and List-II has Six entries (P), (Q), (R), (S), (T) and (U) FOUR options are given in each Multiple Choice Question based on List-I and List-II and ONLY ONE of these four options satisfies the condition asked in the Multiple Choice Question. Answer to each question will be evaluated according to the following marking scheme : Full Marks : +3 If ONLY the option corresponding to the correct combination is chosen. Zero Marks : 0 If none of the options is chosen (i.e., the question is unanswered); Negative Marks : 1 In all other cases 1. Answer the following by appropriately matching the lists based on the information given in the paragraph Consider the Bohr's model of a one-electron atom where the electron moves around the nucleus. In the following List-I contains some quantities for the nth orbit of the atom and List-II contains options showing how they depend on n. List-I List-II th (I) Radius of the n orbit (P) n 2 (II) Angular momentum of the electron in the nth orbit (Q) n 1 (III) Kinetic energy of the electron in the nth orbit (R) n0 (IV) Potential energy of the electron in the nth orbit (S) n1 (T) n2 (U) n1/2 Which of the following options has the correct combination considering List-I and List-II? (1) (II), (R) (2) (I), (P) (3) (I), (T) (4) (II), (Q) Ans. (3) JEE(Advanced) 2019/Paper-2/Held on Monday 27 th May, 2019 9 JEE(Advanced) 2019/Paper-2 n2 Sol. r = 0.529 z r n2 (I) (T) nh 2p (mvr) n (II) (S) z2 KE = +13.6 2 n KE n 2 (III) (P) mvr = PE = 2 13.6 z2 PE n n2 2 (IV) (P) Answer the following by appropriately matching the lists based on the information given in the paragraph Consider the Bohr's model of a one-electron atom where the electron moves around the nucleus. In the following List-I contains some quantities for the nth orbit of the atom and List-II contains options showing how they depend on n. List-I List-II th (I) Radius of the n orbit (P) n 2 (II) Angular momentum of the electron in the nth orbit (Q) n 1 (III) Kinetic energy of the electron in the nth orbit (R) n0 (IV) Potential energy of the electron in the nth orbit (S) n1 (T) n2 (U) n1/2 Which of the following options has the correct combination considering List-I and List-II? (1) (III), (S) (2) (IV), (Q) (3) (IV), (U) (4) (III), (P) Ans. (4) A LL EN 2. Sol. Same as 1 (Section-3) 10 JEE(Advanced) 2019/Paper-2/Held on Monday 27 th May, 2019 JEE(Advanced) 2019/Paper-2 3. Answer the following by appropriately matching the lists based on the information given in the paragraph List-I includess starting materials and reagents of selected chemical reactions. List-II gives structures of compounds that may be formed as intermediate products and/or final products from the reactions of List-I List-I List-II CN O (I) O (II) i) O3 ii) Zn, H2O iii) NaBH4 iv) conc. H2SO4 (P) CHO CO2H OH (Q) OH A LL EN CO2H i) DlBAL-H ii) dil, HCl iii) NaBH4 iv) conc. H2SO4 (III) i) KCN ii) H3O,+ D CO2CH3 iii) LiAlH 4 iv) conc. H2SO4 Cl CO 2Me (IV) CO2Me i) LiAlH4 ii) conc. H2SO4 (R) O OH (S) CO2H (T) CO2H CO2H (U) O O Which of the following options has correct combination considering List-I and List-II? (1) (III), (S), (R) (2) (IV), (Q), (R) (3) (III), (T), (U) (4) (IV), (Q), (U) Ans. (2) JEE(Advanced) 2019/Paper-2/Held on Monday 27 th May, 2019 11 JEE(Advanced) 2019/Paper-2 Cl Sol. CN KCN CO2CH 3 CO2CH 3 CO2H + H3O D CO2H LiAlH4 O Conc. H2SO4 CH2 OH OH III, T, Q, R CO2Me LiAlH4 OH CH2OH CO2Me Conc.H2SO4 A LL EN O IV, Q, R 4. Answer the following by appropriately matching the lists based on the information given in the paragraph List-I includess starting materials and reagents of selected chemical reactions. List-II gives structures of compounds that may be formed as intermediate products and/or final products from the reactions of List-I List-I (I) List-II CN O O (II) CO2H i) DlBAL-H ii) dil, HCl iii) NaBH4 iv) conc. H2 SO4 i) O3 ii) Zn, H2O iii) NaBH4 iv) conc. H2SO4 i) KCN + ii) H3O , D CO2CH3 iii) LiAlH4 iv) conc. H2SO4 (P) CHO CO2H OH (Q) OH Cl (III) 12 (R) O JEE(Advanced) 2019/Paper-2/Held on Monday 27 th May, 2019 JEE(Advanced) 2019/Paper-2 CO 2Me (IV) CO2Me OH i) LiAlH4 (S) ii) conc. H2SO4 CO2H (T) CO2H CO2H (U) O O Which of the following options has correct combination considering List-I and List-II? (1) (I), (Q), (T), (U) (2) (II), (P), (S), (U) (3) (II), (P), (S), (T) (4) (I), (S), (Q), (R) Ans. (2) CN O DiBALH dil HCl CH2 CH = O A LL EN Sol. O CH = O NaBH4 OH CH2OH Conc.H2SO4 O I, Q, R O3 / Zn / H2O CO2H CH2 CH = O CO2H NaBH 4 CH2 OH CO2H Conc.H2SO4 O O II, P, S, U JEE(Advanced) 2019/Paper-2/Held on Monday 27 th May, 2019 13

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