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ICSE Class X Board Exam 2017 : Computer Applications (Solved Paper)

11 pages, 40 questions, 3 questions with responses, 3 total responses,

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ICSE Question Paper 2017 (Solved) Computer Applications Class X SECTION A (40 Marks) Answer all questions from this Section SECTION A (40 MARKS) Attempt all questions Question 1: a) What is Inheritance ? [2] Ans. Inheritance is the process by which one class extends another class to inherit the variables and functions and add any additional variables and methods. b) Name the operators listed below [2] i) < ii) ++ iii) && iv) ?: Ans. i) Less than comparison operator ii) Increment operator iii) And logical operator iv) Ternary operator c) State the number of bytes occupied by char and int data types.[2] Ans. char occupies two bytes and int occupied 4 bytes. d) Write one difference between / and % operator. [2] Ans. / is division operator while % is modulus operator which gives the remainder on dividing two numbers. e) String x[] = { SAMSUNG , NOKIA , SONY , MICROMAX , BLACKBERRY }; Give the output of the following statements:[2] i) System.out.println(x[1]); ii) System.out.println(x[3].length()); Ans. i) NOKIA ii) MICROMAX .length() = 8 Question 2: a) Name of the following: [2] i) A keyword used to call a package in the program. ii) Any one reference data types. Ans. i) import ii) String b) What are the two ways of invoking functions? [2] Ans. Call by value and call by reference c) State the data type and value of res after the following is executed : [2] char ch = t ; res = Character.toUpperCase(ch); Ans. Data type of res is char and value is T d) Give the output of the following program segment and also mention the number of times the loop is executed: [2] int a,b; for(a=6,b=4;a<=24;a=a+6) { if(a%b==0) break; } System.out.println(a); Ans. Loop initialization: a = 6, b = 4 First iteration: Condition check: a <= 24 that means (6 <= 24) , which is true Loop is executed for the first time Loop execution: a % b = 6 % 4 = 2 != 0 Hence, break is not executed Loop increment operator: a = a + 6 that means ( a = 6 + 6 ), then a is updated to 12 Second iteration: Condition check: a <= 24 that means (12 <= 24) , which is true Loop is executed for the second time Loop execution: a % b = 12 % 4 = 0 = 0 Hence, break is executed System.out.println(a); This statement will print 12 Output is 12 and loop is executed two times e) Write the Output: [2] char ch= 'F'; int m=ch; m=m+5; System.out.println(m+ " " +ch); Ans. ch = F int m = ch; From this statement ASCII value of F i.e. 70 will be assigned to m m = m + 5 = 70 + 5 = 75 System.out.println(m+ +ch); & this statement will print 75 F Output is 75 F Question 3: a) Write a Java expression for the following : [2] ax5 + bx3 + c Ans. a * Math.pow(x, 5) + b * Math.pow(x, 3) + c b) What is the value of x1 if x=5 ? [2] x1=++x x++ + x Ans. x1=++x x++ + x x1 = 6 (x is incremented to 6) 6 (x is incremented to 7) + 6 (x is decremented to 6) =6 c) Why is an object called an instance of a class? [2] Ans. An object is called an instance of a class as every object created from a class gets its own instances of the variables defined in the class. Multiple objects can be created from the same class. d) Convert following do-while loop into for loop. [2] int i=1; int d=5; do{ d=d*2 System.out.println(d); i++; }while(i<=5); Ans. for(int i=1, d=5; i<=5; i++) { d = d * 2; System.out.println(d); } e) Differentiate between constructor and function. [2] Ans. The constructor of a class is invoked automatically during object creation while a function is invoked manually after object creation. A constructor is invoked only once while a function can be invoked multiple times. A constructor has the same name as the class in which it is defined while a function can have any name. f) Write the output for the following: [2] String s= "Today is Test"; System.out.println(s.indexOf('T')); System.out.println(s.substring(0,7)+ " "+ "Holiday"); Ans. So the first println method , System.out.println(s.indexOf( T )); will print the index of T, which is 0 (zero) & second println method will take substring stored from 0 to 7th index & concatenate it with a String Holiday Today i + + Holiday Today i Holiday Output is 0 Today i Holiday g) What are the values stored in variables r1 and r2: [2] i) double r1 = Math.abs(Math.min(-2.83,-5.83)); ii) double r2 = Math.sqrt(Math.floor(16.3)); Ans. i) double r1 = Math.abs(Math.min(-2.83,-5.83)); = Math.abs(-5.83) = 5.83 ii) double r2 = Math.sqrt(Math.floor(16.3)); = Math.sqrt(16) = 4.0 h) Give the output of the following code: [2] String A= "26", B= "100" ; String D=A+B+ "200"; int x= Integer.parseInt(A); int y=Integer.parseInt(B); int d=x+y; System.out.println("Result 1=" +D); System.out.println("Result 2="+d); Ans. String A= 26 , B= 100 ; A = 26 , B = 100 String D=A+B+ 200 ; By doing this, value of A will concatenate with value of B & further these are concatenated with String 200 So , D = 26 + 100 + 200 = 26100200 int x= Integer.parseInt(A); x = Integer.parseInt( 26 ) , By doing this String 26 will converted into Integer 26 , and it will be assigned into variable x int y=Integer.parseInt(B); y= Integer.parseInt( 100 ) , Similarly String 26 will be converted into Integer 26 , and it will be assigned into variable y int d=x+y; d = 26 + 100 = 126 System.out.println( Result 1= +D); Result 1=26100200 System.out.println( Result 2= +d); Result 2=126 Output is Result 1=26100200 Result 2=126 i) Analyze the given program segment and answer the following questions [2] for(int i=3;i<=4;i++) { for(int j=2;j<i;j++) { System.out.print(" "); } System.out.println("WIN"); } i) How many times does the inner loop execute ? ii) Write the output of the program segment. Ans. The output loop runs twice, with i = 3 and i = 4 When i = 3, the inner loop runs once with j = 2 When i = 4, the inner loop runs twice with j = 2 and j = 3 i) Inner loop executes 3 times ii) WIN WIN j) What is the difference between the Scanner class functions next() and nextLine()? [2] Ans. next() read a single token i.e. all characters from the current position till a whitespace or tab or new line is encountered. nextLine() reads an entire line i.e. all characters from the current position till a new line is encountered. SECTION B (60 Marks) Attempt any four questions from this Section. Question 4. Define a class Electric Bill with the following specifications: [15] class: ElectricBill Instance Variable/ data member: String n to store the name of the customer int units to store the number of units consumed double bill to store the amount to paid Member methods: Void accept() to accept the name of the customer and number of units consumed Void calculate() to calculate the bill as per the following tariff : Number of units Rate per unit First 100 units Rs.2.00 Next 200 units Rs.3.00 Above 300 units Rs.5.00 A surcharge of 2.5% charged if the number of units consumed is above 300 units. Void print() To print the details as follows : Name of the customer Number of units consumed Bill amount . Write a main method to create an object of the class and call the above member methods. Ans. import java.util.Scanner; public class ElectricBill { private String n; private int units; private double bill; public void accept() { Scanner kb = new Scanner(System.in); System.out.print("Enter name: "); n = kb.next(); System.out.print("Enter units: "); units = kb.nextInt(); } public void calculate() { if (units<= 100) { bill = units * 2; } else if (units>100 && units<=300) { bill = units * 3; } else { bill = units * 5; double surcharge = bill * 2.5 / 100; bill = bill + surcharge; } } public void print() { System.out.println("Name of the customer: " +n); System.out.println("Number of units consumed: " +units); System.out.println("Bill amount: " +bill); } public static void main(String[] args) { ElectricBill EB = new ElectricBill(); EB.accept(); EB.calculate(); EB.print(); } } Sample output Enter name: Atharv Enter units: 50 Name of the customer: Atharv Number of units consumed: 50 Bill amount: 100.0 Question 5. Write a program to accept a number and check and display whether it is a spy number or not. [15] (A number is spy if the sum its digits equals the product of the digits.) Example: consider the number 1124 , sum of the digits = 1 + 1 + 2 + 4 = 8 Product of the digits = 1 x 1 x 2 x 4=8 Ans. import java.util.Scanner; public class SpyNumber { public static void main(String[] args) { Scanner kb = new Scanner(System.in); System.out.print("Enter number: "); int n = kb.nextInt(); int sum = 0; int product = 1; while (n>0) { int r = n % 10; sum = sum + r; product = product * r; n = n / 10; } if (sum == product) { System.out.println("Spy number"); } else { System.out.println("Not a spy number"); } } } Sample output 1 Enter number: 1124 Spy number Sample output 2 Enter number: 1254 Not a spy number Question 6. Using switch statement, write a menu driven program for the following: [15] i) To find and display the sum of the series given below: S = x1 x2 + x3 x4 + x5 x20 (where x=2) ii) To display the following series: 1 11 111 1111 11111 For an incorrect option, an appropriate error message should be displayed. Ans. import java.util.Scanner; public class MenuDriven { public static void main(String[] args) { System.out.println("Press 1 for Sum of series"); System.out.println("Press 2 for Display Series"); System.out.print("Enter your choice: "); Scanner kb = new Scanner(System.in); int choice = kb.nextInt(); switch (choice) { case 1: double sum = 0; for (int i = 1; i <= 20; i++) { if (i % 2 == 1) { sum = sum + Math.pow(2, i); } else { sum = sum - Math.pow(2, i); } } System.out.println("Sum = " + sum); break; case 2: for (int i = 1; i<= 5; i++) { for (int j = 1; j<= i; j++) { System.out.print("1"); } System.out.print(" "); } break; default: System.out.println("Invalid choice"); break; } } } Sample output 1 Press 1 for Sum of series Press 2 for Display Series Enter your choice: 1 Sum = -699050.0 Sample output 2 Press 1 for Sum of series Press 2 for Display Series Enter your choice: 2 1 11 111 1111 11111 Sample output 3 Press 1 for Sum of series Press 2 for Display Series Enter your choice: 3 Invalid choice Question 7. Write a program to input integer elements into an array of size 20 and perform the following operations: [15] i) Display largest number from the array ii) Display smallest number from the array iii) Display sum of all the elements of the array Ans. import java.util.Scanner; public class MyArray { public static void main(String[] args) { Scanner kb = new Scanner(System.in); int[] arr = new int[20]; System.out.print("Enter 20 numbers in an array: "); for (int i = 0; i < 20; i++) { arr[i] = kb.nextInt(); } int smallest = arr[0]; int largest = arr[0]; int sum = 0; for (int i = 0; i < 20; i++) { if (arr[i] < smallest) { smallest = arr[i]; } if (arr[i] > largest) { largest = arr[i]; } sum = sum + arr[i]; } System.out.println("Smallest = " + smallest); System.out.println("Largest = " + largest); System.out.println("Sum = " + sum); } } Sample output Enter 20 numbers: 1 2 3 4 5 6 7 8 9 8 5 4 2 4 5 6 8 4 7 82 Smallest = 1 Largest = 82 Sum = 245 Question 8: Design a class to overload a function check() as follows: i) void check(String str, char ch) to find and print the frequency of a character in a string. Example : Input Output Str = success number of s present is=3 ch = s ii) void check (String s1) to display only the vowels from string s1 , after converting it to lower case. Example : Input: S1= computer output: o u e Ans. public class Overload { public void check(String str, char ch) { int result = 0; for (int i = 0; i < str.length(); i++) { char currentChar = str.charAt(i); if (ch == currentChar) { result++; } } System.out.println("number of s present is = " + result); } public void check(String s1) { s1 = s1.toLowerCase(); for (int i = 0; i < s1.length(); i++) { char currentChar = s1.charAt(i); if (currentChar == 'a' || currentChar == 'e' || currentChar == 'i' || currentChar == 'o' || currentChar == 'u') { System.out.print(currentChar + " " ); } } } } Question 9: Write a program to input forty words in an array. Arrange these words in descending order of alphabets, using selection sort technique. Print the sorted array. Ans. import java.util.Scanner; public class SelectionSort { public static void main(String[] args) { // Accept 40 words Scanner kb = new Scanner(System.in); String[] words = new String[40]; System.out.println("Enter 40 words: "); for (int i = 0; i < 40; i++) { words[i] = kb.nextLine(); } // Sort using selection sort for (int i = 0; i < words.length - 1; i++) { int largestWordIndex = i; for (int j = i + 1; j < words.length; j++) { if (words[j].compareTo(words[largestWordIndex]) > 0) { largestWordIndex = j; } } String temp = words[largestWordIndex]; words[largestWordIndex] = words[i]; words[i] = temp; } // Print sorted array for (int i = 0; i < 40; i++) { System.out.println(words[i]); } } }

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Additional Info : ICSE Class X Board Exam 2017 : Computer Applications (with Solutions)
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