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IIT JEE Exam 2025 : Advanced

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Class : XIth Date : Solutions Subject : CHEMISTRY DPP No. : 10 Topic :- Chemical Bonding and Molecular Structure 1 (b) Molecule Hybridizatio n 2 2 3 SO3 C2H2 C2H4 CH4 CO2 2 3 (b) Mg2+is smaller thanNa+ and thus, smaller is cation more is hydration energy. (b) Number of lone pair in XeOF4 is one (1). The structure of XeOF4 is given as follows : O F F Xe F F sp3d 2- hybrid Xe atom in ground state 5s 5p 5d Xe in excited state In XeOF4 Bond f ormation Lone pair of electron 4 5 6 sp3d 2 One -bond so remaining six electron pairs form an octahedron with one position occupied by a lone pair. (d) These are the factors on which van der Waals forces depend. (b) It has 3 3-hybridization with one lone pair on X . (b) PRERNA EDUCATION https://prernaeducation.co.in 011-41659551 | 9312712114 1 Bond order Bond length 7 8 10 BO of NO<BO of NO+ Bond length of NO is greater than the bond length of NO+. (b) Element with atomic number 20 is metal (Ca); it will combine with non-metal. (a) A decrease in -character increases bond length. (b) Calculated dipole moment, cal = 2.0 10 10 m 1.6 10 19 C = 3.2 10 29 C m. Percentage of ionic character = = 11 12 5.12 10 29 16 17 18 19 cal 100 100 = 16% (c) C2H4 involves 2-hybridization on carbon atoms. (b) According to molecular orbital theory. F2(18) = 1 2, 1 2 , 2 2, 2 2, 2 2 , 2 2 2 2 , 2 2 , 2 2 Bond order in F2= 15 3.2 10 29 exp 2 = 10 8 2 =1 (a) Bond formation is always exothermic. Compounds of sodium are ionic. (d) In case of water, five water molecules are attached together through four hydrogen bonding (b) Removal of electron is easier in the order of shell 4 > 3 > 2 > 1 (c) Bond order of NO+, NO and NO are 3, 2.5 and 2 respectively. Bond energy bond order. (a) FXF angles of two types are present in 3 hybrid orbitals. Since, SF4 shows 3 hybridisation as follows, therefore, it exhibits two different FXF angles. F F S F F 20 (c) -character bond angle For 25% character (as in 3hybrid orbital), bond angle is 109.5 , for 33.3% character (as in 2 hybrid orbital),bond angle is 120 and for 50% character (as in hybrid PRERNA EDUCATION https://prernaeducation.co.in 011-41659551 | 9312712114 orbital ), bond angle is 180 . Similarly, when the bond angle decreases below 1.9.5 ,the character will decrease accordingly Decreasing in angle = 120 109.5 = 10.5 Decrease in -character = 33.3 25 = 8.3 Actual decrease in bond angle = 109.5 105 = 4.5 Expected decrease in -character 8.3 = 4.5 = 3.56% 10.5 Thus, the -character should decrease by about 3.56%, , -character = 25 3.56 = 21.44% PRERNA EDUCATION https://prernaeducation.co.in 011-41659551 | 9312712114 ANSWER-KEY Q. A. 1 B 2 B 3 B 4 D 5 B 6 B 7 B 8 A 9 B 10 B Q. A. 11 C 12 B 13 C 14 A 15 A 16 D 17 B 18 C 19 A 20 C PRERNA EDUCATION https://prernaeducation.co.in 011-41659551 | 9312712114

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