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IIT JEE Class 11 2019 : Mathematics

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Mayank Kumar Singh
 Jamshedpur 
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TRANSFORMATION OF AXES It s easy too but I find myself stuck most of the times in the beginning but now I am pretty comfortable See by my practice and till the dept I understand there are just few types of questions and I have developed my procedure which I want to discuss here. First )))Transformation of origin See in this x=X+h and y=Y +k.here the points x and y represents the points in the original coordinate axes H and K are the distance moved by reference frame (x-y) frame with respect to original frame. Now questions comes like this at which point should origin be shifted so that the first degree terms becomes zero or is removed or it comes like this to which points origin must be shifted so that constant becomes0 or is removed .so for that . Now I want to say that original coordinate of origin was 0,0 and now u want to shift it to others point (H,k) so in new axes view point this should turn out to be 0. There are two steps. )))first analyse the problem not then blindly whatever just replace xby X+H and y by Y+k and solve them then separate all the 1 degree terms and 2 degree or if any more is there and then if its given in question given that 1 degree term S becomes zero then proceed to it by making coefficient of X to be zero of the new equation and similarly make the coefficient of Y to be 0 and them solve these 2 equation simultaneously to get H,k ))) if u want to find x,y original coordinated just differentiate the original equation means the equation given in the question , (partial differentiation) .u need to differentiate 2 times as once by differentiating the equation by keeping x to be constant ,differentiating the given equation with respect to y and then differentiating with respect to y and keeping x constant (note u need to different than equation given in the question as u need to find the original coordinates x,y) u will get simultaneous equation solve them get x,y.

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