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BEE Energy Sample / Model Paper 2023 : Energy : energy auditor

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Kakoli
Bureau of Energy Efficiency (BEE), New Delhi

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E Paper-4 Code: Gr e en Marks: Section - II: SHORT NUMERICAL QUESTIONS () Answver all the Two questions 2 x5 = ( ) Each question carries Five marks The operating data of Vapor Absorption L-1 Chilled water flow Specific heat of chilled water Density of water Chilled water inlet temperature Chilled water outlet Enthalpy of steam temperature Chiller is given below: 0.18 mn'/sec 4.18 kJ | kg/ K 1000 kg/m' 9 c 7 C Steam flow rate 2700 kJ / kg Condensate temperature 1 kg/sec 100 c Calculate the following: a) b) c) L-2 Refrigeration effect in TR Thermal input energy in kJ|s Coefficient of performance (COP) The fuel gas analysis of an industrial boiler The Gross Calorific Value of the fuel is 4200 revealed CO : 5O00 PPM and 100 kg of fuel. The fuel has 36 kg of CO,: 14%. Estimate the percentage loss duekCal/kg. to carbon incomplete of C to Co. per End of Section Section (i) (ii) N-1 10 combustion - II - III: LONG NUMERICAL QUESTIONS Answer all the Four questions Each question carries Twenty mnarks Marks: 4 x 20 = 80 In an engineering company, the and other To meet the compressed air is required for processes. To assess the installed. pneumatic equipment's one requirement, of The test and other reciprocating of 500 cfm is performance compressor data are given below: compressor, free air delivery test was carried out. Receiver capacity Interconnecting pipe Initial pressure in receiver Atmospheric pressure Final pressure Time taken to fill receiver Inlet air (T) Air temnperature in the temperature Motor RPM receiver (T) Motor efficiency Motor pulley diameter Compressor RPM Compressor pulley diameter Average loading time : 10 m3 : 1m3 1.0 kg/ cm a 1.0 kg/ cm a 8.5 kg/cm a : : 6 mninute : 30 C 40 C 1400 RPM 93% 300 mm 700 RPM : 600 mm 65% BUREAUOF ENERGY EFFICIENCY 2 Paper-4 Code : Green 35% Average unloading time :82 kW Power consumption during loading unloading : 21 kW Power consumption during 10.00 Rs. /kWh Cost of energy Calculate the following: (5 Marks) compressor? (2 Marks) i) Free air delivery of hours of operation) 24 (for day per cost (5 Marks) 11) Operating energy efficiency of the compressor. isothermal and power has decided to iii) Isothermal unloading, the main tenance team loss due to size. Evaluate iv) To reduce the energy the compressor by reducing the motor pulley 50 min of of and speed reduce the 10 min unloading time for required the motor. compressor of pulley the speed of the diameter of the evaluate accordingly (5 Marks) loading time and replacerment of the pulley consumption, energy saving after hours of energy hourly the V) Estimate Rs. 1.2 Lakhs. The operatingloading is is belt and pulley of cost consumption during andpayback period. The in a year. Consider power hours 8000 pulley change. is compressor the unloading is 18 kW after motor during consumption (3 Marks) 64 kW and power N-2 draw water from 1000 liter/sec is planning to of requirement water options are evaluated: i) A factory having a the plant. The following two fromn away km located 3 river basin discharge line of connected to separate dedicated Option A: Two separate pumps and each pump delivering 500 liter/ sec. The efficiency 500mm diameter with 3 kmn length efficiency is 93%. motor of the pump is80% and with 3 km discharge line of 750 mm diameter a to connected pump motor Option B: Single efficiency of the pump is 80% and The liter/sec. 1000 delivering length and efficiency is 95%. Option:A 3 km Pump 500 mm diameter, 500 Ips Reservoir Pump 500 mm dianeter, 500 lps Option:B 3 km Punp The other data's are as follows: System static head Pipe friction factor Cost of energy 750 mm diameter, 1000 Ips Reservoir 12 m 0.006 :Rs. 10/kWh 7680 hrs. Annual operating hours annual As an energy auditor which option you will recommnend considering the (15 Marks) energy cost. 11) A cooling tower connected to the condenser of a refrigeration system is operating with a heat load of 280 x 10 kCal/hr. The hot water inlet temperature to the cooling tower and approach are 33 C and 3 C respectively. The wet bulb temperature is 25 C. The condenser Pump iS operating at a total head of 25 mThe combined efficiency of pump and motor l (5 Marks) 52%. Calculate the power drawn by the condenser pump. BUREAU oF ENERGY EFFICIENCY 3 Paper-4 Code : Green dot N-3 An oil refinery has captive power plant with pet coke fired boiler. The following are the collected to assess the boiler performance : Pet coke elementary analysis Carbon 88.8% Hydrogen 3.6% Nitrogen Oxygen 1.2% Sulphur 3.6% Moisture 1.4% 1.4% GCV of Petcoke : 8340 kCal/kg Stack O, : 6.0 mol% Stack Temperature : 250 C Heat loss due to radiation & convection Loss due to unburnt in fAy ash & bottom ash : 1.0% :0.5% Specific heat of fiue gas Specific heat of water vapour Ambient temperature : 0.29 kCal/ kg C : 0.45 kCal/ kg C : 30 C : 0.0204 Humidity in ambient air Steam generation at 110 bar g (&) 520 C Steam enthalpy at generation Feed water temperature pressure and temperature: 816 kCal/kg Steam drum pressure i) Calculate Boiler efficiency using indirect ii) Calculate evaporation ratio. kg/kg dry air : 200 C : method. 115 bar (g) (12 Marks) i i) Calculate the quantity (kg) of (3 Marks) flash steam generated per kg of blow down if: (s Marks) Saturated liquid enthalpy at steam drum pressure: 352 kCal/kg Total enthalpy of flash steam at 2 bar (g) pressure : 646 kCal/kg Latent heat of evaporation at 2 bar (g) pressure N-4 i) (A) : 526 kCal/kg Answer any ONE of the following among four questions given below: Determine the cooling load of a commercial data building in Watts, based on the following Outdoor Conditions DBT WBT 36 C Humidity 19 gm of 26 C Desired Indoor Conditions DBT RH water/ kg of dry air 25 C 50% Humidity Total area of wall Total area of window U- Factor (Wal1) U- Factor (Roof) U - Factor (Windows) 11 gm of 45 m water/kg of dry air 15 m 0.35 W/m K 0.363 W/ m K 3.00 W/ m K BUREAUOF ENERGY EFFICIENCY 4 Paper-4 Code : Green Other Data 20 m x 20 m Roof Area CLTD 12 C o Wall 42 C o Roof 8 C o Window 500 W/m' 0.84 Shading co-efficient (Window) SCL Window 30 people Space occupancy Heat Gain/ person 80 W o Sensible 50 W o Latent CLF for people Fluorescent light in space CLF for lighting 0.9 21 W/m? 0.9 1.2 Ballast factor 6.3 W/m of sensible heat Computers and office equipment heat production infiltration 0.25 Air changes/hr of 3.9 m Height of building 1210 J/m3 K Product of density and specific heat of air water 3010 J kg dry air/m'grams of (14 Marks) Latent heat factor at the cost of additional insulation to the roof give to decided has value 0.300 W/m? K. ii) The management modifies the Ufactor of the roof to Rs.40,000/-. This treatment The other data is : system The COPof the vapour compression compressor The efficiency of the motor coupled with year for the building The number of hours of operation in a :3.75 :90% : 6000hours : Rs. 10/kWh Power cost additional insulation. Find out the simple payback period for this (6 Marks) Or energy auditor. N-4 The following is the data collected from a 500 MW turbine unit by an (B Main steam flow (TPH) 1561 Hot reheat flow (TPH) 1413 Main steam pressure (kg/cm)/Temperature ( C) Cold reheat (CRH) pressure (kg/cmn)/Temperature ( C) Hot reheat pressure (HRH) (kg/cm)/Temperature ( C) 166/529 Feed water temperature ( C) 44.3/341 42.4/540 246 Main steam enthalpy (kCal/ kg'C) 806.47 Feed water enthalpy (kCal/kgC) CRH enthalpy (kCal/ kg C) 246 730.71 HRH en thalpy (kCal/kg C) 844.27 Generator output (MW) 501.7 Boiler eficiency (%) 87 5 BUREAU OF ENERGY EFF1CIL NCY Paper-4 Code : Green Heater Reference Temp Saturation Temp ( C) (C) Drain Temp Temp (c) (kg/em ) 47.2 13.7 Values Pressure TTD DCA ( C) (kg/em?) ( C) ( C) 63.6 12.6 2.88 4.8 Temp Pressure ( C) Design Feed water out Feed water in Steam LP Heater 73 70 64.2 LP Heater 2 140 111.23 70.4 105 11.5 2.95 4.95 LP Heater 3 209 132.9 110 130 10.4 2.95 4.95 HP Heater 5 416 207.33 171 210 199 HP Heater 335 254.94 212 255 197 170 202 5 0.1 5 Calculate the following: a) Turbine cycle heat rate and unit gross heat rate. (6 Marks) b) Net heat rate and efficiency of the power plant if the auxiliary power consumption is 6%. (2 Marks) c) Loss/ gain in the turbine heat rate because of the deviation of the Terminal Temperature Difference (TTD) and Drain Cooler Approach (DCA) of the LP/HP Heater systems from the design values. (12 Marks) Consider, " For every 0.56 C increase or decrease of TTD from the design value, Heat Rate will increase or decrease by 0.014%. For every 0.56 C increase or decrease of DCA from the design value, Heat Rate will increase or decrease by 0.005%. Or N-4 A cement company manufactures ordinary clinker and low heat clinker. The chemical of the cement clinkers (l0ss free basis) are given in the following (C)composition table: Constituent Sio, Percentage of constituent Ordinary Clinker Low Heat Clinker 20 44 Fe,0 7 15 Al,0, 7 1 CaO 65 39 MgO 1 1 Following heat data is given for both types of manufacturing process. Item Heat output excluding heat of formation Total Heat Input Calculate the following: kCal/ kg of kCal/ kg of Ordinary Clinker Low Heat Clinker 360t6.7ucl 400+7.1m,uc 27+6000mu 27+6000m, i) Heat of formation of clinker for both the types. ii) Total heat output in terms of mcl ii) Amount of fuel needed per kg of clinker for each type of clinker from heat iv) Which type of clinker v) If cost of coal is Rs. (8 Marks) (2 Marks) balance principle . (4 Marks) consumes more energy? (1 Mark) 6,200/- per ton, what is the difference cost per ton of clinker, between in Ordinary Clinker and Low Heat Clinker? energy consumption (5 Marks) BUREAU OF ENERGY EFFICIENCY 6 Paper-4 Code : Green Or mill, 150 kg of fabric is dyed per batch in ajigger. The dye In a textile liquor is kCal/from i) 4 25 Cto 90 C. The specific steam consumption is 0.65 kg/kg (with enthalpy 660heated kg) D) Calculate the liquor ratio allowing 15% margin for the losses. (5 Marks) textile mill a thermic fluid heater of 20 lakh kCal/hour is meeting process heat a In ii)requirement. Outlet : 280 C temperature of fluid :260 C temperature of fluid Return fuid Specificheatof Densityoffiluid Current coal consumption GCVofcoal of :0.55 k Cal/ kg C :840kg/m : 400 kg/ hour : 4100 kCal/ kg heater: 45% the thermic fluid loading Percentagethe Calculate following: (3Marks) (2Marks) circulation rate? fluid thermic efficiencv? fluid heater thermic Whatis the thermal operation? a) efficiency ofthe existing annual (5 Marks) 6000hrs of pre-heater the is the What for b) coalsavings providing an air the Calculate l By conditionsof improved to 62%. outlet textile stenterin a details of a figure below. the unit and ii) operating the shown in The are thecloth Inlet 30 c 60% Moisture inlet and (5 Marks) Outlet Stenter 80 C 5% Moisture ter sten to the Value inputCalorific The heat efficiency Gross kg/hour. The kg/hr.The fuel. 1000 as is is320 thestenter. sten ter byfirewood consumption the of cloth to heaterfired frewood dryingefficiency wet rate of thermicfuid kCal/kgand Calculatethe e Ieed bya 3500 I o efirewood d isheateris65%. C)of III Section tnermicfluid e Endof

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