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if (n == 0) 
           { 
               n = sum; 
               sum = 0; 
           } 
I cannot find any use of these lines in magic number progrma
Can anyone pllease explain.
asked by Bitthal Maheshwari (bitthal04) 5 years ago
5
String res = str.replace(" " , "");  this works
 but this String res = str.replace(' ' , ''); do not work
Why? if they should be character then ther should be ' '
asked by Ansh Anand (teleansh) 5 years ago
1

+ 2 more questions by teleansh  

Anyone from Mumbai
asked by Tubhyam Mehta (tirth7683) 5 years ago
3
I'm so glad I found ResPaper! Nice to have mates from over the country(well mainly Bangalore and Mumbai but yeah :P)

Well, I should be saying all this on the last board exam but well passion, mistress of desires and it sways it to the mood of what it likes or loathes.
asked by Aquaman- King of the Seven Seas (shauns) 5 years ago
3
any one here commercial applications....
asked by jesusavari 5 years ago
0
If there is difference between two things asked for 2 marks and we have only one point are examples accepted?
asked by Anvaya Juvekar (anvaya) 5 years ago
1
What is the scope of local,instance & class variable?
asked by Jeevan Kumar (jeevanms) 5 years ago
2
Hi
asked by ... (sam307) 5 years ago
2
Accept a no. from the user and find if it is a fascinating number.( FASCINATING NUMBER : When a number( 3 digit or more) is multiplied by 2 and 3 ,and when both these products are concatenated with the original number all digits from 1 to 9 are present exactly once, regardless of the number of zeroes)
asked by Deeksha (deeksha9) 5 years ago
3
hi guys these are two answers to the disarmium question everyone has been bothered about- without using string functions
import java.util.Scanner;
public class disarmy1
{
    void hello()
    {  Scanner in = new Scanner(System.in);
        System.out.println("enter the number ahole");
        int s = in.nextInt();
        int a = s;
        int b=s;
        int d=0;//to find the digits
        int c=0;//to count the number of digits
        int i,e=0,sum=0;
        while(s>0)
        {  d= s%10;
            c++;
            s=s/10;
        }
        for(i=c;i>=1;i--)
        { 
            
            
          e= a%10;
           sum = sum+ (int)(Math.pow(e,i));//since i is equal to number of digits
            a=a/10;
        
       }
       if(sum==b)
       System.out.println("disarmium number");
       else
       System.out.println("not");
    }
}
//THIS IS THE SECOND ANSWER TO THE QUESTION WHICH IS A LITTLE HARDER TO COPREHEND 
import java.util.Scanner;
public class disarmy2
{
    void hello()
    {
        //this is using arrays
         Scanner in = new Scanner(System.in);
        System.out.println("enter the number ahole");
        int s = in.nextInt();
        int n =s;
        int q=s;
        int d=0;
        int i;
        int c=0;
        int x=0;
        int sum=0;
        while(s>0)//to find the number of digits the number has
        {d = s%10;
            c++;
            s=s/10;
        }
        int a[]= new int[c];
        for(i=0;i<c;i++)//to put all these digits into an array
        {
            x=n%10;
            a[i]= x;
            n=n/10;
        }
        for(i=c-1;i>=1;i--)//taking array from the last element and adding the power of index+1 of that number to sum
        {
            sum = sum+ (int)Math.pow(a[i],i+1);
        }
        if(sum==q)
        System.out.println("disarmium");
        else
        System.out.println(" not");
    }
    
}
asked by Sankhya Gowda (taankkkkk) 5 years ago
2

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