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asked by ... (sam307) 5 years ago
2
Accept a no. from the user and find if it is a fascinating number.( FASCINATING NUMBER : When a number( 3 digit or more) is multiplied by 2 and 3 ,and when both these products are concatenated with the original number all digits from 1 to 9 are present exactly once, regardless of the number of zeroes)
asked by Deeksha (deeksha9) 5 years ago
3
hi guys these are two answers to the disarmium question everyone has been bothered about- without using string functions
import java.util.Scanner;
public class disarmy1
{
    void hello()
    {  Scanner in = new Scanner(System.in);
        System.out.println("enter the number ahole");
        int s = in.nextInt();
        int a = s;
        int b=s;
        int d=0;//to find the digits
        int c=0;//to count the number of digits
        int i,e=0,sum=0;
        while(s>0)
        {  d= s%10;
            c++;
            s=s/10;
        }
        for(i=c;i>=1;i--)
        { 
            
            
          e= a%10;
           sum = sum+ (int)(Math.pow(e,i));//since i is equal to number of digits
            a=a/10;
        
       }
       if(sum==b)
       System.out.println("disarmium number");
       else
       System.out.println("not");
    }
}
//THIS IS THE SECOND ANSWER TO THE QUESTION WHICH IS A LITTLE HARDER TO COPREHEND 
import java.util.Scanner;
public class disarmy2
{
    void hello()
    {
        //this is using arrays
         Scanner in = new Scanner(System.in);
        System.out.println("enter the number ahole");
        int s = in.nextInt();
        int n =s;
        int q=s;
        int d=0;
        int i;
        int c=0;
        int x=0;
        int sum=0;
        while(s>0)//to find the number of digits the number has
        {d = s%10;
            c++;
            s=s/10;
        }
        int a[]= new int[c];
        for(i=0;i<c;i++)//to put all these digits into an array
        {
            x=n%10;
            a[i]= x;
            n=n/10;
        }
        for(i=c-1;i>=1;i--)//taking array from the last element and adding the power of index+1 of that number to sum
        {
            sum = sum+ (int)Math.pow(a[i],i+1);
        }
        if(sum==q)
        System.out.println("disarmium");
        else
        System.out.println(" not");
    }
    
}
asked by Sankhya Gowda (taankkkkk) 5 years ago
2
what is use of     if (num == 0) 
            { 
                num = sum; 
                sum = 0; 

in magic number code
asked by Ansh Anand (teleansh) 5 years ago
0

+ 3 more questions by teleansh  

Guys cant we use string functions and stuff for Disarium number, Other types of numbers?
asked by Aquaman- King of the Seven Seas (shauns) 5 years ago
2
This is for all.

Can everyone please decribe how you he/she divide his/her time for completing the paper.

and what would you do additional in your copy to fetch good marks from the examiner.
asked by Bitthal Maheshwari (bitthal04) 5 years ago
1

+ 1 more questions by bitthal04  

Do we have to do operators associavity coz it's not there in APC
asked by Tubhyam Mehta (tirth7683) 5 years ago
1
Good quality computer question paper solve to increase your knowledge

Paper 1. https://drive.google.com/file/d/19kSSQ1n-EVh9SV6YBnM_tvhKBjyFp9Hz/view?usp=drivesdk



Paper 2 https://drive.google.com/file/d/1xGWq2bKcsrrAisyE3zWMxbjY22tpUbB7/view?usp=drivesdk

I hope u can 100
asked by Annhaliator (laxyone) 5 years ago
3
Design a class to Overload ......

Do we need to write main( ) ? If yes, do we have to get values from the user, or can we put in our own values? Getting from the user will be prettty loong..
asked by Prateek Pradhan (prateek235) 5 years ago
2
why is (index of )answer -1 if character is not found in string ?
asked by Not productions (pranav55) 5 years ago
3

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