ICSE − Q & A

I'm so glad I found ResPaper! Nice to have mates from over the country(well mainly Bangalore and Mumbai but yeah :P)

Well, I should be saying all this on the last board exam but well passion, mistress of desires and it sways it to the mood of what it likes or loathes.

+ 1 more questions by shauns  

Guys cant we use string functions and stuff for Disarium number, Other types of numbers?
asked by Aquaman- King of the Seven Seas (shauns) 5 years ago
2

Why it is not working. It is a program for Duck Number

import java.util.Scanner;
public class magic
{
    public static void main (String args[])
    {
        Scanner sc = new Scanner(System.in);
        System.out.println("ENTER NO TO CHECK");
        int num = sc.nextInt();
        String str = Integer.toString(num);
        int len = str.length();
        int count = 0;
        int i;
        for(i=0 ; i <len ; i++)
        {
            if ( str.charAt(i) == '0')
            count ++;
        }
        
        
        if(count > 0 && str.charAt(0) != '0')
        System.out.println("It is a Duck Number");
        else
        System.out.println("It is not a Duck Number");
            
    }
}

+ 2 more questions by teleansh  

what is use of if (num == 0) { num = sum; sum = 0; in magic number code
asked by Ansh Anand (teleansh) 5 years ago
0

Why it is not working. This code is for Disarium Number public class sum { public static void main (int num) { int i = 0; int sum = 0; String str = Integer.toString(num); int len = str.length(); while (num > 0) { i = num%10; sum = sum + (int)Math.pow( i , len); len -- ; // or len = len -1; num = num / 10; } if ( sum == num) System.out.println("It is a Disarium Number"); else System.out.println("It is not a Disarium Number"); } }
asked by Ansh Anand (teleansh) 5 years ago
2

any one here commercial applications....

If there is difference between two things asked for 2 marks and we have only one point are examples accepted?

What is the scope of local,instance & class variable?

Hi

Accept a no. from the user and find if it is a fascinating number.( FASCINATING NUMBER : When a number( 3 digit or more) is multiplied by 2 and 3 ,and when both these products are concatenated with the original number all digits from 1 to 9 are present exactly once, regardless of the number of zeroes)

hi guys these are two answers to the disarmium question everyone has been bothered about- without using string functions
import java.util.Scanner;
public class disarmy1
{
    void hello()
    {  Scanner in = new Scanner(System.in);
        System.out.println("enter the number ahole");
        int s = in.nextInt();
        int a = s;
        int b=s;
        int d=0;//to find the digits
        int c=0;//to count the number of digits
        int i,e=0,sum=0;
        while(s>0)
        {  d= s%10;
            c++;
            s=s/10;
        }
        for(i=c;i>=1;i--)
        { 
            
            
          e= a%10;
           sum = sum+ (int)(Math.pow(e,i));//since i is equal to number of digits
            a=a/10;
        
       }
       if(sum==b)
       System.out.println("disarmium number");
       else
       System.out.println("not");
    }
}
//THIS IS THE SECOND ANSWER TO THE QUESTION WHICH IS A LITTLE HARDER TO COPREHEND 
import java.util.Scanner;
public class disarmy2
{
    void hello()
    {
        //this is using arrays
         Scanner in = new Scanner(System.in);
        System.out.println("enter the number ahole");
        int s = in.nextInt();
        int n =s;
        int q=s;
        int d=0;
        int i;
        int c=0;
        int x=0;
        int sum=0;
        while(s>0)//to find the number of digits the number has
        {d = s%10;
            c++;
            s=s/10;
        }
        int a[]= new int[c];
        for(i=0;i<c;i++)//to put all these digits into an array
        {
            x=n%10;
            a[i]= x;
            n=n/10;
        }
        for(i=c-1;i>=1;i--)//taking array from the last element and adding the power of index+1 of that number to sum
        {
            sum = sum+ (int)Math.pow(a[i],i+1);
        }
        if(sum==q)
        System.out.println("disarmium");
        else
        System.out.println(" not");
    }
    
}

This is for all.

Can everyone please decribe how you he/she divide his/her time for completing the paper.

and what would you do additional in your copy to fetch good marks from the examiner.

Do we have to do operators associavity coz it's not there in APC