ICSE − Q & A

hi guys these are two answers to the disarmium question everyone has been bothered about- without using string functions
import java.util.Scanner;
public class disarmy1
{
    void hello()
    {  Scanner in = new Scanner(System.in);
        System.out.println("enter the number ahole");
        int s = in.nextInt();
        int a = s;
        int b=s;
        int d=0;//to find the digits
        int c=0;//to count the number of digits
        int i,e=0,sum=0;
        while(s>0)
        {  d= s%10;
            c++;
            s=s/10;
        }
        for(i=c;i>=1;i--)
        { 
            
            
          e= a%10;
           sum = sum+ (int)(Math.pow(e,i));//since i is equal to number of digits
            a=a/10;
        
       }
       if(sum==b)
       System.out.println("disarmium number");
       else
       System.out.println("not");
    }
}
//THIS IS THE SECOND ANSWER TO THE QUESTION WHICH IS A LITTLE HARDER TO COPREHEND 
import java.util.Scanner;
public class disarmy2
{
    void hello()
    {
        //this is using arrays
         Scanner in = new Scanner(System.in);
        System.out.println("enter the number ahole");
        int s = in.nextInt();
        int n =s;
        int q=s;
        int d=0;
        int i;
        int c=0;
        int x=0;
        int sum=0;
        while(s>0)//to find the number of digits the number has
        {d = s%10;
            c++;
            s=s/10;
        }
        int a[]= new int[c];
        for(i=0;i<c;i++)//to put all these digits into an array
        {
            x=n%10;
            a[i]= x;
            n=n/10;
        }
        for(i=c-1;i>=1;i--)//taking array from the last element and adding the power of index+1 of that number to sum
        {
            sum = sum+ (int)Math.pow(a[i],i+1);
        }
        if(sum==q)
        System.out.println("disarmium");
        else
        System.out.println(" not");
    }
    
}

what is use of     if (num == 0) 
            { 
                num = sum; 
                sum = 0; 

in magic number code

+ 3 more questions by teleansh  

Why it is not working. This code is for Disarium Number public class sum { public static void main (int num) { int i = 0; int sum = 0; String str = Integer.toString(num); int len = str.length(); while (num > 0) { i = num%10; sum = sum + (int)Math.pow( i , len); len -- ; // or len = len -1; num = num / 10; } if ( sum == num) System.out.println("It is a Disarium Number"); else System.out.println("It is not a Disarium Number"); } }
asked by Ansh Anand (teleansh) 5 years ago
2

1) Scope of Instance Variable is - non static methods . Right ?? 2) What is the difference between application class and class as user defined data type. plz explain clearly.
asked by Ansh Anand (teleansh) 5 years ago
1

https://www.respaper.com/sujit28/4435-pdf.html Plz. refer to Q3 d)
asked by Ansh Anand (teleansh) 5 years ago
2

Guys cant we use string functions and stuff for Disarium number, Other types of numbers?

This is for all.

Can everyone please decribe how you he/she divide his/her time for completing the paper.

and what would you do additional in your copy to fetch good marks from the examiner.

+ 1 more questions by bitthal04  

Can anyone please provide any worksheets or notes for nomenclature.
asked by Bitthal Maheshwari (bitthal04) 5 years ago
1

Do we have to do operators associavity coz it's not there in APC

Good quality computer question paper solve to increase your knowledge

Paper 1. https://drive.google.com/file/d/19kSSQ1n-EVh9SV6YBnM_tvhKBjyFp9Hz/view?usp=drivesdk



Paper 2 https://drive.google.com/file/d/1xGWq2bKcsrrAisyE3zWMxbjY22tpUbB7/view?usp=drivesdk

I hope u can 100

Design a class to Overload ......

Do we need to write main( ) ? If yes, do we have to get values from the user, or can we put in our own values? Getting from the user will be prettty loong..

why is (index of )answer -1 if character is not found in string ?

Can anyone help me with the code of my previous question.... I'll tell the logic for that as well..... 
The logic is: If you take the numerical value of the letters, you find that they are in fibonacci sequence. And the second half is reverse fibonacci. Remember to take the numeric value instead of ASCII value. Good luck coding!

import java.util.*;
class isogram
{
    public static void main()
    {
        Scanner ayush=new Scanner (System.in);
        System.out.println("Enter a string");
        String s=ayush.nextLine();
        s=s.toUpperCase();String w="";String s1="";char ch1,ch2;int f=0;
        
        s=s+' ' ;
        int l=s.length();
        for(int i=0;i<l;i++)
        {
            char ch=s.charAt(i);
            if(ch==' ')
            {
                for(int j=0;j<w.length();j++)
                {ch1=w.charAt(j);
                    for(int k=j+1;k<w.length();k++)
                    {ch2=w.charAt(k);
                       if(ch1==ch2)
                       f++;}
                       if(f>0)
                       continue;
                       else
                       s1=s1+w+" ";
                    }}
                  else
                  w=w+ch;
                  w="";}
                  System.out.println("the stirng after manipulationm"+s1);}}

can u guys helps me with his program it is the answer to rikhil question 
i m not getting any syntax error but still no output