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GCE JAN 2008 : AS 1 Forces and Electricity

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Centre Number 71 Candidate Number ADVANCED SUBSIDIARY (AS) General Certificate of Education January 2008 Physics assessing Module 1: Forces and Electricity ASY11 Assessment Unit AS 1 [ASY11] WEDNESDAY 16 JANUARY, AFTERNOON TIME 1 hour. INSTRUCTIONS TO CANDIDATES Write your Centre Number and Candidate Number in the spaces provided at the top of this page. Answer all seven questions. Write your answers in the spaces provided in this question paper. INFORMATION FOR CANDIDATES The total mark for this paper is 60. Quality of written communication will be assessed in question 5(c). Figures in brackets printed down the right-hand side of pages indicate the marks awarded to each question or part question. Your attention is drawn to the Data and Formula Sheet which is inside this question paper. You may use an electronic calculator. For Examiner s use only Question Number 1 2 3 4 5 6 7 Total Marks ASY1W8R 3960.07 Marks If you need the values of physical constants to answer any questions in this paper, they may be found on the Data and Formulae Sheet. Examiner Only Marks Remark Answer all seven questions 1 (a) Physical quantities may be classified as vectors or scalars. (i) Explain what is meant by a vector quantity. ____________________________________________________ [1] (ii) There are four physical quantities listed below. Indicate which of the physical quantities are scalars by placing a tick ( ) in the box corresponding to the quantity. Acceleration Frequency Potential energy Volume [2] (b) Name five of the base units in the SI system of units. __________________________________________________________ _______________________________________________________ [2] ASY1W8R 3960.07 2 [Turn over (c) A runner completes one lap of a circular track of circumference 6000 m in 1500 seconds, running in a clockwise direction starting from point A. Calculate his change in velocity (if any), when he is half way round the track (at B). Assume that he runs at constant speed. A 3960.07 Remark B Change in velocity = _____________ m s 1 ASY1W8R Examiner Only Marks 3 [2] [Turn over 2 Two parallel coplanar forces can sometimes form a couple. Examiner Only Marks Remark (a) State three conditions which must apply to these forces to make a couple. 1. ________________________________________________________ 2. ________________________________________________________ 3. _____________________________________________________ [3] (b) The steering wheel on a bus has a radius of 28.0 cm. Under certain road conditions the torque needed to turn the wheel is 15.6 N m. (i) Assuming the use of a couple, mark on Fig. 2.1 the positions and directions of the minimum forces needed to turn the wheel anticlockwise. Fig. 2.1 [2] (ii) Find the magnitude of these forces. Magnitude = ___________ N ASY1W8R 3960.07 [2] 4 [Turn over BLANK PAGE (Questions continue overleaf) ASY1W8R 3960.07 5 [Turn over 3 (a) A hotel lift, initially at rest, moves vertically in a straight line. From time t = 0 it accelerates uniformly until t = t1, when its acceleration suddenly decreases to zero. It continues moving until t = t2 with zero acceleration. It then decelerates uniformly coming to rest at t = t3. The top graph in Fig. 3.1 shows how its acceleration depends on time t. acceleration a t1 0 t2 t3 t 0 velocity v 0 0 t 0 t displacement s 0 Fig. 3.1 ASY1W8R 3960.07 6 [Turn over On the middle and lower axes in Fig. 3.1 sketch graphs to show the variation with time t of Examiner Only Marks Remark (1) the velocity v of the lift, (2) the displacement s of the lift. [5] (b) A typical jet aircraft accelerates from rest for 28.0 seconds, leaving the ground with a take-off speed of 270 kilometres per hour. (i) Show that a speed of 270 kilometres per hour corresponds to a speed of 75 m s 1. [1] (ii) Assume that the acceleration of the aircraft is constant. (1) Calculate the acceleration of the aircraft as it travels along the runway. Acceleration = _________ m s 2 [2] (2) Calculate the minimum distance the aircraft travels along the runway before it takes off. Distance = _________ m ASY1W8R 3960.07 [2] 7 [Turn over 4 (a) State Newton s second law of motion. Examiner Only Marks Remark __________________________________________________________ __________________________________________________________ _______________________________________________________ [2] (b) A toy car of mass 400 g is placed on a slope inclined at 25.0 to the horizontal. Fig. 4.1 shows a simplified diagram of the situation. Frictio n 25.0 Fig. 4.1 In the calculations that follow, take g = 9.81 m s 2. (i) Calculate the weight of the car. Weight = _________ N [1] (ii) Calculate the component of the weight of the car acting down the slope. Component = _________ N ASY1W8R 3960.07 [2] 8 [Turn over (iii) The car is released and starts to move down the slope. The force of friction opposing the motion is 1.20 N. Calculate the initial acceleration of the car down the slope. Acceleration = _____________ m s 2 Examiner Only Marks Remark [3] (iv) The force of friction increases as the car speeds up. At one stage in the motion the frictional force is increased by 0.46 N. Describe how this affects the acceleration. ______________________________________________________ ____________________________________________________ [1] ASY1W8R 3960.07 9 [Turn over 5 In part (c) of this question you should answer in continuous prose. You will be assessed on the quality of your written communication. Examiner Only Marks Remark (a) The battery in a mobile phone takes exactly 3 hours to charge when the charging current is 400 mA. (i) Calculate the charge which is transferred to the battery in this time. Charge = ___________ C [1] (ii) Calculate the number of electrons transferred to the battery in this time. Number of electrons = _____________ [2] (b) A copper conductor with a cross-sectional area of 2.5 mm2 carries a current of 12 A. The number density of free electrons in copper is 8.4 1028 m 3. (i) Calculate the drift speed of the free electrons in this conductor. Drift speed = _________ m s 1 [3] (ii) Six such conductors are placed in parallel to form a cable. How is the drift speed affected with the same current of 12 A in the composite cable? ______________________________________________________ ____________________________________________________ [1] ASY1W8R 3960.07 10 [Turn over (c) Early transmissions of information across the Atlantic Ocean through a submarine cable involved the use of direct current signals. Calculations show that the drift speed of the electrons is such that it would take about 200 years for an electron to cross the Atlantic! Clearly, information was transmitted much faster. Explain why there is no such delay in sending information across the Atlantic in this way. Examiner Only Marks Remark __________________________________________________________ __________________________________________________________ __________________________________________________________ __________________________________________________________ __________________________________________________________ _______________________________________________________ [2] Quality of written communication ASY1W8R 3960.07 [1] 11 [Turn over 6 (a) Making reference to energy transfer, state the meaning of the term electromotive force of a battery. Examiner Only Marks Remark __________________________________________________________ _______________________________________________________ [2] (b) A source of electrical power with an e.m.f. of 4.16 V and internal resistance r supplies a current of 0.800 A to an external resistor of resistance 4.00 , as shown in Fig. 6.1. 0.800 A 4.16 V 4.00 r Fig. 6.1 (i) Calculate the internal resistance r of the source. r = _________ [3] (ii) Calculate the power dissipated in the 4.00 resistor. Power _________ W ASY1W8R 3960.07 [2] 12 [Turn over 7 (a) Fig. 7.1 shows a network of five resistors connected between X and Y. Examiner Only Marks Remark X 0.60A 4 6 6 12 3 Y Fig. 7.1 (i) Calculate the total resistance between X and Y. Resistance = _____________ [2] (ii) The current entering the network at X is 0.60 A. Calculate the current through the 12 resistor. Current = _________ A ASY1W8R 3960.07 [2] 13 [Turn over (b) A milliammeter reads from 0 to 2.5 mA and has internal resistance 40 . It is to be converted into a 0 to 5 A ammeter. To make the conversion an additional resistor is needed. Fig. 7.2 shows the milliammeter and a partially completed circuit. 5.00 A Examiner Only Marks Remark 2.5 mA 40 Fig. 7.2 There are two possible positions to insert the additional resistor. (i) Complete the circuit diagram to show clearly the correct position in which to insert this resistor. [1] (ii) What name is given to a resistor used in this way? ________________________________________ [1] (iii) Calculate the resistance of this resistor. Resistance = _________ [3] (iv) Calculate the effective resistance of this 5A ammeter with the additional resistor in place. Effective resistance = _________ ASY1W8R 3960.07 14 [1] [Turn over THIS IS THE END OF THE QUESTION PAPER ASY1W8R 3960.07 15 [Turn over S 11/07 302-088-1 16 GCE Physics (Advanced Subsidiary and Advanced) Data and Formulae Sheet Values of constants speed of light in a vacuum c = 3.00 108 m s 1 permeability of a vacuum 0 = 4 10 7 H m 1 permittivity of a vacuum 0 = 8.85 10 12 F m 1 1 = 8.99 109 F 1 m 4 0 ( ) elementary charge e = 1.60 10 19 C the Planck constant h = 6.63 10 34 J s unified atomic mass unit 1 u = 1.66 10 27 kg mass of electron me = 9.11 10 31 kg mass of proton mp = 1.67 10 27 kg molar gas constant R = 8.31 J K 1 mol 1 the Avogadro constant NA = 6.02 1023 mol 1 the Boltzmann constant k = 1.38 10 23 J K 1 gravitational constant G = 6.67 10 11 N m2 kg 2 acceleration of free fall on the Earth s surface g = 9.81 m s 2 electron volt 1 eV = 1.60 10 19 J ASY11INS ASY1W8 USEFUL FORMULAE The following equations may be useful in answering some of the questions in the examination: Thermal physics Mechanics Momentum-impulse relation mv mu = Ft for a constant force Average kinetic energy of a molecule 1 m<c2> 2 Power P = Fv Kinetic theory pV = 1 Nm <c2> 3 Conservation of energy 1 mv 2 2 1 mu 2 = Fs 2 for a constant force Simple harmonic motion Displacement x = x0 cos t or x = x0 sin t Velocity v = x 0 2 x 2 Simple pendulum T = 2 l / g Loaded helical spring T = 2 m / k Medical physics Sound intensity level/dB = 10 lg10(I/I0) Sound intensity difference/dB = 10 lg10(I2/I1) Resolving power sin = / D Waves Capacitors Capacitors in parallel 11 1 1 = + + C C1 C 2 C 3 C = C1 + C2 + C3 Time constant = RC Capacitors in series Electromagnetism Magnetic flux density due to current in (i)i long straight (i)i solenoid B= (ii) long straight (i)i conductor B= = ay/d Diffraction grating 0I 2 a A.c. generator E = E0 sin t = BAN sin t Stress and Strain Hooke s law F = kx Strain energy E = <F > x (= 1 Fx = 1 kx 2 2 2 if Hooke s law is obeyed) Electricity Vout = R1Vin/(R1 + R2) A = N A = A0e t t1 = 0.693/ 2 Photoelectric effect 1 mv2 = max 2 de Broglie equation 1/u + 1/v = 1/ f Radioactive decay Half life Light ASY1W8 l Alternating currents d sin = n Potential divider 0NI Particles and photons Two-slit interference Lens formula = 3 kT 2 = h /p Particle Physics Nuclear radius 1 r = r0 A3 hf hf0

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Additional Info : Gce Physics January 2008 Assessment Unit AS 1, Module 1: Forces and Electricity
Tags : General Certificate of Education, A Level and AS Level, uk, council for the curriculum examinations and assessment, gce exam papers, gce a level and as level exam papers , gce past questions and answer, gce past question papers, ccea gce past papers, gce ccea past papers  

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