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CSIR UGC NET 2008 : LIFE SCIENCES - PAPER I

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LIFE SCIENCES PAPER I(PART B ) 41. During protein synthesis, L-amino acid binds to t-RNA through 1. 2. 3. 4. 42. The peptide bond is planar 1. 2. 3. 4. 43. independent of the nature of donor and acceptor atoms. dependent on donor and acceptor atoms. dependent on the solvent in which the molecule is dissolved. dependent on the other atoms bonded with the donor and acceptor atom. Why a DNA duplex melts at a specific temperature (Tm) on heating? 1. 2. 3. 4. 45. due to restriction caused by rotation around c N bond due to restriction around c c bond due to delocalization of the lone pair of electrons of the nitrogen onto carbonyl oxygen because amide protons and carbonyl oxygen are involved in hydrogen bonding. Hydrogen bond length will NOT be 1. 2. 3. 4. 44. -amino group. hydrophobic side chain. carboxyl group. carboxyl group of the side chain. Loss of base stacking energy The double helix is intrinsically unstable The single helix is more stable as compared to the double helix The DNA double helix is a co-operative structure stabilized by hydrogen bonds and base pairing Lipid bilayers can be formed by phospholipids which have variable head groups and fatty acyl chains. The fluidity of the membrane will depend on 1. 2. 3. 4. only the nature of head groups. only the length of the fatty acid chains irrespective of the extent of unsaturation. only unsaturation irrespective of the length of the fatty acid chains. length and degree of unsaturation of fatty acid chains. 46. Which one of the following RNA molecules is involved in regulation of gene expression? 1. 2. 3. 4. 47. In which organelle is NADP+ the final electron acceptor? 1. 2. 3. 4. 48. Trypanosoma Plasmodium Paramecium Entamoeba Which of the following mammalian cells usually does NOT divide in adult life? 1. 2. 3. 4. 51. 1. 0. +1. 10. Which one of the following human pathogen is a flagellated protozoan? 1. 2. 3. 4. 50. Only chloroplast Only mitochondrion Both chloroplast and mitochondrion Lysosome When the K'q = 1, G is equal to 1. 2. 3. 4. 49. miRNA rRNA 5S RNA tRNA Epithelial cells in lung Nerve cells in brain Liver cells Osteoblast cells What happens to the Cdk-cyclin A complex at metaphase? 1. 2. 3. 4. Both cyclin A and Cdk remain undegraded Only Cdk is degraded Only cyclin A is degraded Both cyclin A and Cdk are degraded 52. The average human genome has approximately 3 109 base pairs coding for various proteins. If an average protein contains 400 amino acids, what is the maximum number of proteins that can be encoded by the human genome? 1. 2. 3. 4. 53. In eukaryotes, the interaction of enhancer and promoter elements is brought closer by 1. 2. 3. 4. 54. Myosin Actin Kinesin Dynein Ionophores are small hydrophobic molecules that can partition into the lipid bilayer and increase their permeability to specific inorganic ions. Which of the following is a channel forming ionophore? 1. 2. 3. 4. 56. zinc finger. DNA looping. helix turn helix. palindrome. Which of the following cytoskeleton elements guides the movement of vesicles containing cell wall precursors from their site of formation in Golgi to the site of new wall formation in a growing pollen tube? 1. 2. 3. 4. 55. 2.5 106. 2.5 107 . 3.0 106 . 3.5 107 . Valinomycin. Actinomycin. Gramicidin A. Nicin. Which GTPases regulate intracellular transport in mammalian cells through vesicle fusion? 1. 2. 3. 4. Rab Ran Ras Rho 57. The region where RNA polymerase binds to promoter in prokaryotes is called 1. 2. 3. 4. 58. Which of the following features highlights the difference between Z-DNA and BDNA? 1. 2. 3. 4. 59. affects elongation only. blocks initiation only. affects both initiation and elongation. does not affect transcription. Which of the following features is not required in the initiation step of protein synthesis? 1. 2. 3. 4. 62. cytoplasm. nucleolus. nucleus. endoplasmic reticulum. The absence of sigma factor in RNA polymerase 1. 2. 3. 4. 61. Double helical nature Orientation of phosphate backbone Pairing of G C Antiparallel nature of two polynucleotide strands of double helix Ribosomal subunits are assembled in 1. 2. 3. 4. 60. Pribnow box. Hogness box. Homeo box. Shine-Dalgarno box. Amino acid activation Binding of mRNA to the ribosomes Transfer of activated amino acid to tRNA Joining together of two amino acids by peptide bond formation By which of the following mechanisms does cycloheximide inhibit protein synthesis? 1. 2. 3. 4. Blocking the peptidyl transferase of 80S euokaryotic ribosomes Blocking the peptidyl transferase of 70S prokaryotic ribosomes By binding to DNA dependent RNA polymerase By binding to sigma factor 63. Which of the following is a natural inducer of the lac operon in E. coli? 1. 2. 3. 4. 64. Antitermination of RNA synthesis is a major mechanism of regulation in 1. 2. 3. 4. 65. lytic phase of phage. lysogenic phase of phage. lac operon. trp operon. Influenza virus binds to its host cells through which one of the following carbohydrate moiety. 1. 2. 3. 4. 66. Lactose Galactose Allolactose IPTG N-acetyl glucosamine N-acetyl neuraminic acid Fucose Mellibiose In mammals, G protein coupled receptors (GPCR) play a major role in mediating effects of various hormones NOT through 1. 2. 3. 4. activation of protein kinase A. activation of adenylate cyclase. inactivation of adenylate cyclase. activation of tyrosine kinase activity. 67. Receptors for neurotransmitters are located on the 68. 1. cell surface. 2. nucleus. 3. endosome. 4. Golgi apparatus. One of the major transmembrane proteins in a tight junction is 1. 2. 3. 4. lectin. claudin. adherin. integrin. 69. Retroviruses are well known as cancer causing agents because it 1. 2. 3. 4. 70. Select the correct statement: 1. 2. 3. 4. 71. equals its prospective fate. is greater than prospective fate. is less than prospective fate. and fate are unrelated. Experiments with sea urchin demonstrated species specific sperm-egg recognition through the protein 1. 2. 3. 4. 74. uses complement mediated cell lysis. uses a radiolabeled second antibody. involves addition of substrate which is converted to coloured end product. requires specialized red blood cells. In mosaic development, the prospective potency of cells 1. 2. 3. 4. 73. In vertebrate development, immune and nervous systems are the prevalent sites for apoptosis. Apoptosis is triggered by growth stimulus. The tumor suppressor factor p53 inhibits apoptosis. The soluble form of tumor necrosis factor cannot induce apoptosis. ELISA assay 1. 2. 3. 4. 72. causes mutations in host genes involved in growth. integrates their proviral DNA next to protooncogenes. generates defective viruses lacking some of the viral genes. integrates their T antigens into the host genome. bindin. avidin. activin. hyalin. Exposing a regenerating limb to which of the following chemicals results in the blastema proximalization? 1. 2. 3. 4. Ascorbic acid Thyroxine Retinoic acid Glutamic acid 75. Temperature-dependent sex determination is observed in 1. 2. 3. 4. 76. Some plants require vernalization (prolonged cold treatment) for transition to flowering. For floral induction, vernalization signal is perceived primarily by 1. 2. 3. 4. 77. young leaves subtending the apical meristem. mature leaves near the root-shoot junction. all vegetative parts. shoot apical meristem. Which phase of embryogenesis in plants is characterized by the initiation of deposition of storage reserves? 1. 2. 3. 4. 78. Drosophila. amphibians. reptiles. sea urchins. Globular stage Heart stage Torpedo stage Cell enlargement stage Which of the following statements is NOT true in relation to growth of animals? 1. 2. 79. When all body parts grow at the same rate, it is called isometric growth. When different body parts grow at different rates, it is called allometric growth. 3. Two-fold change in weight will cause a 1.26-fold expansion in length if growth is allometric. 4. Isometric growth cannot create dramatic changes in the structure of organisms. Abnormalities during development caused by exogenous agents are called disruptions and the agents are specifically called 1. 2. 3. 4. morphogen. teratogen. allergen. mutagen. 80. At which of the following steps does application of dichlorophenyl-dimethyl urea (DCMU) inhibit electron flow during photosynthesis? 1. 2. 3. 4. 81. A major functional difference between the succinyl CoA-synthetase of plant and animal cell mitochondria is that it 1. 2. 3. 4. 82. 84. reduced nitrite reductase activity. reduced nitrate reductase activity. reduced transport of nitrate into the vacuoles. reduced transport of nitrate into the chloroplasts. The Rht mutations in wheat that were pivotal for 'Green Revolution' cause reduction in plant height due to impairment in 1. gibberellic acid biosynthesis pathway. 2. gibberellic acid signaling pathway. 3. auxin biosynthetic pathway. 4. auxin response pathway. Which of the following phytochrome controlled responses displays red/far-red reversibility? 1. 2. 3. 4. 85. does not produce ATP in plant cell. does not produce GTP in plant cell. produces ATP in plants and GTP in animals. produces GTP in plants and ATP in animals. A common symptom of molybdenum deficiency in plants is the accumulation of nitrate in the cytosol, which results from 1. 2. 3. 4. 83. P680* Pheophytin QA QB QB Cytb6f complex Cytb6f complex plastocyanin Very low-fluence responses Low-fluence responses High-irradiance responses Very high-irradiance responses At permanent wilting point, plants cannot regain turgor pressure even if transpiration stops because 1. water potential of soil ( w) is less than or equal to osmotic potential ( S) of the plant. 2. w is higher than S . 3. w and S are unaltered. 4. S remains unaltered. 86. Alkaloid production in plants is regulated by a change in the endogenous pool of 1. 2. 3. 4. 87. Flooding and submergence of plants leads to anoxic conditions. Usually, floodtolerant species alter their developmental programme, resulting in 1. 2. 3. 4. 88. 1/4 1/16 1/64 1/256 Two fruitflies with mutant eye color were crossed. All progenies obtained from this cross had wild type eye colour as 1. 2. 3. 4. 90. increased activity at the apical meristem. growth retardation of foliage. elongation growth of their stems. increased proliferation of root system. An organism with the genotype AABbCcDD is selfed. The four genes are independently assorting. What proportion of the progeny will show the genotype AAbbccDD? 1. 2. 3. 4. 89. gibberellins. jasmonates. brassinosteroids. abscisic acid. the mutations are allelic. one mutation is dominant over the other. the mutations are co-dominant. the mutations are in two different genes. The following pedigree represents the inheritance of a rare disorder. Based on the above pedigree, what is the most likely mode of inheritance? 1. 2. 3. 4. Autosomal dominant X-linked recessive X-linked dominant Y-linked dominant 91. Which of the following pair of relatives will have the highest genetic correlation? 1. First double cousins 2. Half siblings 3. Brothers 4. Brother-sister 92. a1, a2, a3 are three alleles of a gene in Neurospora. Crosses between different a mutants gave the following results a1 a 2 a1 a3 a2 a 3 a1 + a1 + a2 + ++ a1 + a2 + + a2 ++ ++ +a3 + a3 + a2 The process which best explains this result is 1. 2. 3. 4. gene conversion. forward mutation. non-homologous recombination. incomplete dominance. 93. You are provided with an E. coli strain auxotrophic for the amino acids Trp, Leu and Val. To select for double revertants in Trp and Leu, which amino acid(s) would you include in the growth medium? 1. Trp 2. Leu 3. Val 4. Trp, Leu, Val 94. UAG and UAA are both nonsense codons. What kind of single point mutation would cause reversion of UAG to a meaningful codon? 1. Transition 2. Transversion 3. Frameshift 4. Inversion 95. E. coli cells were simultaneously infected by two rII bacteriophage mutants. From the progeny obtained after lysis of the E. coli cells it was observed that some of the bacteriophages showed a wild type phenotype. These were obtained at extremely low frequency. This is due to 1. complementation of the two mutations. 2. recombination between the two mutant chromosomes. 3. transposition of the mutation. 4. incomplete penetrance. 96. Which of the following hormones stimulates the reabsorption of Na+ and the secretion of K+ in the kidney? 1. 2. 3. 4. 97. 98. The correct sequence in vertebrate embryonic development is 1. gastrocoel blastocoel notochord neural crest. 2. blastocoel gastrocoel neural crest notochord. 3. gastrocoel blastocoel neural crest notochord. 4. blastocoel neural crest gastrocoel notochord. A person has a vision problem caused by the image of an object at infinity getting focused in front of retina. The error can be corrected by the use of 1. 2. 3. 4. 99. Na+ channels will close. K+ channels will close. Cl channels will open. Na+ channels will open. The primary function of diaphragm is to 1. 2. 3. 4. 101. biconvex lens. cylindrical lens. plano convex lens. biconcave lens. During electrical stimulation-induced depolarization of neuron, voltage-gated 1. 2. 3. 4. 100. Vasopressin Thyroxine Prolactin Aldosterone control blood pressure. regulate respiration. support the heart. keep the rib cage dilated. In nephron, the main role of deamination is to 1. 2. 3. 4. reduce urine pH. reduce water loss. release urea. release uric acid. 102. During inspiration, the air that we breathe moves through different regions of the associated organs in the sequence of 1. 2. 3. 4. 103. 104. Knee jerk reaction is an example of what type of reflex? 1. Monosynaptic 2. Multisynaptic 3. Conditioned 4. Conscious Which of the following processes is a major problem in interpreting molecular phylogeny? 1. 2. 3. 4. 105. intermediary cell. isotropic cell. idioblast cell. myrosin cell. Among the extant reptiles which group is phylogenetically closely related to Aves? 1. 2. 3. 4. 107. Horizontal transfer of genes Gene duplication Synonymous mutations Non-synonymous mutations In a tissue, a cell that markedly differs in form, size and content from other cells of the same tissue is called 1. 2. 3. 4. 106. larynx > nasopharynx > trachea > glottis. nasopharynx > glottis > larynx > trachea. glottis > nasopharynx > larynx > trachea. larynx > glottis > nasopharynx > trachea. Turtles Lizards Snakes Crocodiles The group of organisms that is now separated from the other groups of fungi based on their motile spores and cellulose-rich cell wall is 1. 2. 3. 4. Myxomycetes. Zygomycetes. Deuteromycetes. Oomycetes. 108. 109. Some floristic elements common to both India and China are in the genus 1. Ginkgo. 2. Rhododendron. 3. Poeciloneuron. 4. Erinocarpus. The difference between Indian and African wild herbivore fauna is that there are no 1. 2. 3. 4. 110. Which of the following bird species is endangered? 1. 2. 3. 4. 111. Hill myna Great Indian bustard Crow-pheasant Grey hornbill In spite of the prevalence of herbivory, the earth continues to be largely green because 1. 2. 3. 4. 112. antelopes in India. deer in Africa. odd-toed animals in India. even-toed hoofed animals in Africa. the number of herbivore species is low. herbivores are very inefficient feeders. herbivore numbers are kept low by their predators. herbivory promotes plant growth. Which of the following curves represents the general relationship between body size (S) and intrinsic rate of population growth (r) ? 113. 114. Which of the following reproductive strategies is characteristic of marine invertebrates? 1. Long generation time, small clutch size 2. Short generation time, small clutch size 3. Long generation time, large clutch size 4. Short generation time, large clutch size Bergmann s Rule refers to a general tendency of mammals to be 1. 2. 3. 4. 115. larger in size in colder areas of their distribution. smaller in size in areas of their distribution. darker-pigmented in warmer areas of their distribution. lighter-pigmented in warmer areas of their distribution. When removal of a species from an ecosystem affects persistence of many other species and the impact of that species removal is disproportionate to its abundance, the species is known as 1 2. 3. 4. indicator species. keystone species. flagship species. umbrella species. 116. Biomass turnover time is the ratio between biomass and productivity of an ecosystem. Which of the following forests should have highest biomass turnover time? 1. Tropical dry forests 2. Tropical wet forests 3. Temperate deciduous forests 4. Boreal forests 117. Conversion of nitrite to nitrate in soil is done by the bacteria of genus 1. 2. 3. 4. 118. Azotobacter. Nitrosomonas. Nitrobacter. Pseudomonas. In a population with two alleles a and b of a genotype in a ratio of 0.2 and 0.8 in Hardy-Weinberg equilibrium, how many individuals in a sample of 300 can be expected to be homozygous for allele a ? 1. 2. 3. 4. 192 12 64 96 119. Defective alleles are eliminated rapidly from a population if they are 1. 2. 3. 4. 120. The correct expression of Hamilton rule for the evaluation of altruism is [C = the cost of a behavioral act to the actor, b = the benefit of that act to a beneficiary, and r = the genetic relatedness between the actor and the beneficiary] 1. 2. 3. 4. 121. after the extinction of dinosaurs and before the appearance of birds. before the extinction of dinosaurs and after the appearance of birds. before the extinction of dinosaurs and before the appearance of birds. after the extinction of dinosaurs and after the appearance of birds. Both the Luria-Delbruck experiment and the Lederberg and Lederberg experiment demonstrate 1. 2. 3. 4. 124. differential investment in offspring. difference in aggression. difference in sex chromosomes. difference in autosomes. The evolutionary appearance of the first mammals was 1. 2. 3. 4. 123. c < b r c<b c r < b r < b c The evolutionary basis of sexual dimorphism is 1. 2. 3. 4. 122. recessive. dominant. codominant. in multiple copies. pre-selection mutations. post-selection mutations. directed mutations. adaptive mutations. Vampire bats regurgitate food in order to feed a starving member of their group. This is an example of 1. 2. 3. 4. group selection. reciprocal altruism. selfish behavior. K-selection. 125. The first appearance of amphibians on earth was during the period 1. Silurian. 2. Carboniferous. 3. Triassic. 4. Jurassic. 126. In a transgenic mouse experiment a founder male produces 100 pups and only 20 of these are transgenic. This result leads to the conclusion that the 1. 2. 3. 4. 127. An inbred mouse is cloned using another mouse strain as an egg donor. The genetic relationship between the original inbred mouse and its clone will be 1. 2. 3. 4/ 128. Calcium Potassium Gold Sodium D-amino acids 1. 2. 3. 4. 130. 100%. 99 100%. 95 99%. 90 95%. Which of the following elements can be used to immobilize a reduced protein? 1. 2. 3. 4. 129. founder transgenic animal is chimaeric. founder animal is mosaic. transgene is integrated on Y chromosome. transgene is integrated on X chromosome. cannot be produced by fermentation. can be produced by E. coli. can be produced by yeast. can be produced by microbes provided with chiral precursors of D-amino acids. Which of the following viruses is used for biocontrol of insect pests of plants? 1. 2. 3. 4. Cauliflower mosaic virus Cucumber mosaic virus Rice tungro virus Nuclear polyhedrosis virus 131. What ratio do you expect for codominant loci in F2 populations? 1. 2. 3. 4. 1:1 3:1 1:2:1 9:3:3:1 132. The copy number of a transgene in plants can be deciphered by 1. 2. 3. 4. 133. It is hypothesized that the mean ( ) longevity of a Drosophila strain is 18 days, with a variance ( ) of 3 days. What values of longevity in a sampled population will lead to rejection of the null hypothesis at 95% confidence level? 1. 2. 3. 4. 134. Near IR Red Red / Near Red (Near IR Red) / (Near IR + Red) (Near IR Red) / Red Function of a monochromator in a spectrophotometer is 1. 2. 3. 4. 136. Only values less than 15. Values less than 15 and more than 18 Only values more than 21 Values less than 12 and more than 24 Normalized Differential Vegetation Index (NDVI) in remote sensing refers to the following spectral band derivation: 1. 2. 3. 4. 135. Southern blotting. northern blotting. south western blotting. far western blotting. focusing a straight beam of light. dividing a light beam into its component wavelengths. selecting a desired wavelength. creating a light source. Which of the following methods is the most appropriate for estimating the population density of burrowing animals? 1. 2. 3. 4. Quadrat sampling Line transect sampling Tag-recapture method Nearest neighbour distance method 137. A radioactive sample was counted in a scintillation counter and a value of 194930 cpm was obtained. The counting efficiency was found to be 95.7%. What is the actual amount of radioactivity present in the sample? 1. 2. 3. 4. 138. Which one of the following treatments does NOT enhance the response of a film to radioisotopes in autoradiography? 1. 2. 3. 4. 139. Staining the gel with Coomassie blue before drying Use of intensifying screens Exposure at low temperature Preflashing the film with a light flash What is the length of oligonucleotide required to give consistent specific hybridization signal in a microarray? 1. 2. 3. 4. 140. 181171 dpm 190411 dpm 203600 dpm 211326 dpm 5 7 9 20 A protein is poorly expressed in a diseased tissue. To determine whether the defect is at the level of transcription or translation, which of the following blotting methods would you use? 1. 2. 3. 4. Southern Southern and northern Northern and western Western

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Additional Info : CSIR UGC (National Eligibility Test) NET New Exam Scheme December 2008 Model Question Paper - Life Sciences Paper I Joint CSIR UGC NET Exam Question Papers
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