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17th National Certification Exam Energy Managers & Auditors SEPTEMBER 2016 Paper 2

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Paper 2 Set A REGULAR Regn No: __________________ Name : __________________ (To be written by the candidate) 17th NATIONAL CERTIFICATION EXAMINATION FOR ENERGY MANAGERS & ENERGY AUDITORS September, 2016 PAPER 2: Energy Efficiency in Thermal Utilities Date: 24.09.2016 Timings: 1400-1700 HRS Duration: 3 HRS General instructions: o o o o o Please check that this question paper contains 8 printed pages Please check that this question paper contains 64 questions The question paper is divided into three sections All questions in all three sections are compulsory All parts of a question should be answered at one place Section I: 1. OBJECTIVE TYPE The large difference between GCV and NCV of gaseous fuels is due to their a) large moisture content c) low hydrogen content 2. Which of the following contributes to spluttering of flame at burner tip during combustion of fuel oil? a) ash content 3. b) water content For coal a) moisture 5. c) sulphur content d) humidity of air When pure hydrogen is burned, with theoretical air, the volume percentage of nitrogen in flue gas on dry basis will be a) 100% 4. b) negligible moisture content d) large hydrogen content b) 79% fired system c) 21% the b) volatile matter. flame d) 0% length c) ash content. is dictated by d) fixed carbon Dissolved CO2 in boiler feed water when left untreated would result in occurrence of in boiler tubes a) creep b) water side corrosion _________________________ Bureau of Energy Efficiency c) scale d) water hammer 1 Paper 2 Set A REGULAR 6. At saturation temp, there can be a) Hot water 7. c) Saturated steam d) all of them are possible Water flows at a rate of 30 m3/hr. at 15oC in a 150 mm bore pipe horizontally. What is the velocity of water flow in the pipe? a) 0.47 m/s 8. b) Wet steam b) 0.94 m/s c) 1.88 m/s Which of the following is not true of condensate recovery? a) reduces water charges c) increases boiler output 9. b) reduces fuel costs d) increases boiler blow down Chemical used for dozing in boiler drum to reduce dissolved gases is a) hydrazine 10. b) chlorine c) alum b) light weight d) thermal shock resistant In a reheating furnace, soaking time of a cycle depends typically on; a) excess air level c) thickness of the charged material 12. b) increase in CO2 presence in flue gas d) increased flame length In a pressure reduction valve, which of these does not change? a) Temperature c) Enthalpy 14. b) Pressure d) None of above In a counter-flow heat exchanger, cold fluid enters at 30 C and leaves at 50 C, whereas the hot fluid enters at 150 C and leaves at 130 C. The LMTD is a) 100 C 15. b) 280 C c) 0 C d) 20 Deaerator is a ___________________ Heat exchanger. a) Shell and tube type c) Direct contact type 16. b) preheat temperature of charge d) furnace atmosphere Higher excess air in an oil fired furnace would result in a) increased furnace temperature c) reduced flame temperature 13. d) all of the above Which of the following is not a property of ceramic fibre ? a) low thermal conductivity c) high heat capacity 11. d) none of the above b) Plate type d) Run Around Coil type Pinch analysis uses the _____ law of thermodynamics a) First b) Second _________________________ Bureau of Energy Efficiency c)Third d) Both (a) & (b) 2 Paper 2 Set A REGULAR 17. What is the most effective way to avoid ambient air infiltration into a continuous reheating furnace? a)maintain negative pressure in furnace c) operate at about 90%capacity 18. b) increase the chimney height d) maintain slightly positive pressure in the furnace Select the wrong statement with respect to furnace operations a) the burner flame should not touch the stock b) air infiltration leads to oxidation of billets c) ceramic fibre linings are used in the exterior of the furnace d) heat loss through openings is proportional to T4 19. The heat recovery device in which high conductivity bricks are used for storing heat is a) heat pipe 20. b) hot air dryer b) 7-9 d) furnace c) 9-11 d) None of the above b) Carbon c) Sulphur d) Nitrogen Which of the following is used for controlling pressure in a natural draft furnace? a) Forced draft fan 24. c) diesel engine Which of the following has the lowest stoichiometric oxygen demand (kg/kg of fuel)? a) Hydrogen 23. d) regenerator Desirable boiler water pH should be? a) 5-7 22. c) thermo compressor The exhaust from which of the following is not suitable for waste heat boiler application? a) gas turbine 21. b) heat pump b)Induced draft fan c) Dampers d)Both (a) & (b) The head loss due to friction in a pipe is a) directly proportional to the diameter b) directly proportional to the gravitational constant c) inversely proportional to the velocity d) directly proportional to the square of velocity 25. 26. Which trap is preferred in discharge of condensate recovery from process equipment? a) Float trap b) Thermodynamic trap c) Thermostatic trap d) All of the above Enthalpy of Evaporation of any vapour at its Critical Point will be _________________________ Bureau of Energy Efficiency 3 Paper 2 Set A REGULAR a) Maximum 27. 28. b) Zero a)Sulphur content in fuel b) Ash content in fuel c) Moisture content in fuel d) All of the above Which of the following fuels has the least viscosity? 31. 32. 33. b) Diesel c) Kerosene b) Distillation tower d) Economiser a) Overall heat transfer coefficient b) Fouling coefficient c) LMTD (Log Mean Temperature Difference d) Effectiveness In a boiler Air preheater is installed a) Before the economizer b) after economizer c) after ESP d) Before superheater Sulphur percentage in furnace oi a) sets lower flue gas temperature limit b) improves viscosity c) does not add to heat value d) forms soot Controlled wetting of coal (during the coal preparation) would result in c) improper combustion b) decrease in the percentage of unburnt carbon d) increase in the fines of coal Which of the following is considered in the calculation of Evaporation ratio ? a) calorific value of fuel c) fuel quantity 35. c) Evaporator Which of the following depends on physical properties of fluids as well as geometry of the heat exchanger? a) reduction in flue gas exit temperature 34. d) Crude Oil Select the odd one among the following a) Condenser 30. d) Unpredictable Corrosion in stack, Air Pre-Heater, Economizer is mainly influenced by _____ a) Furnace Oil 29. c) Less than zero b) latent heat of steam d) all of the above Which causes alkaline hardness a) bicarbonates of Ca and Mg c) Chlorides of Mg and Ca c) Silicates d) nitrates of Ca and Mg _________________________ Bureau of Energy Efficiency 4 Paper 2 Set A REGULAR 36. 1% of the fuel is saved in boiler fuel consumption, if the feed water temperature is increased by 40C 37. 38. b) 9oC a) number of bends in pipe b) specific volume of steam c) length of pipe d) diameter of the pipe The working media in a thermo-compressor is b) compressed air c) high temperature oil d) steam The turbine heat rate is expressed as a) kWh/kCal 40. d) 10oC Velocity of steam in steam pipe is directly proportional to; a) electricity 39. c) 6oC b) kg/kCal c) kCal/kWh d) none of the above A rise in conductivity of boiler feed water indicates a) drop in the total dissolved solids in boiler water b) more steam generation c) rise in the total dissolved solids in boiler water d) greater purity of feed water 41. 42. The insulation used for temperatures more than 350oC a) Polyurethane b) polystyrene c) Calcium silicate d) magnesia Which of these is not true of critical point of steam/water mixture? a) the temperature at critical point is 374.15oC b) the pressure at critical point is 221.2 bar c) saturated liquid and saturated vapour lines meet at critical point d) enthalpy of evaporation is maximum at critical point 43. 44. The effectiveness of insulation with ingress of moisture would a) increase b) decrease c) may increase or decrease depending on temperature and thickness of insulation d) remain unaffected The major limitation of metallic recuperator is ------a) limitation of handling COx, NOx etc. b) limitation of reduced life for handling temperature more than 1000oC c) manufacturing difficulty of the required design d) none of the above 45. In a turbine, the thermodynamic process taking place is a) contraction b) expansion _________________________ Bureau of Energy Efficiency c) condensation d) all the above 5 Paper 2 Set A REGULAR 46. 47. In an FBC boiler with low ash fusion coal, if the bed temperature exceeds 950 C, the result is: a) Low steam temperature b) clinker formation c) Melting of lime stones d) Ash carry over Electrical energy consumption for coal sizing will be maximum for a) stoker fired boiler c) CFBC boiler 48. 49. Ideal furnace for melting & alloying of special steels is a) induction furnace b) Cupola furnace c) rotary hearth d) recirculating bogie furnace Arrange the following fuels by their GCV in decreasing order(p) Rice husk, (q) Diesel, a) s-q-r-p 50. b) AFBC boiler d) pulverised coal boiler b) p-q-r-s (r) Grade-C Coal, (s) Hydrogen c) r-s-q-p d) q-r-s-p Water logging of 2 m lift of condensate at trap discharge will result in back pressure of ____ a) 0.02 kg/cm2 b) 0.2 kg/cm2 c )2 kg/cm2 d) 20 kg/cm2 -------- End of Section - I --------- _________________________ Bureau of Energy Efficiency 6 Paper 2 Set A REGULAR Section - II: S-1 SHORT DESCRIPTIVE QUESTIONS In a plant, a boiler is generating saturated steam of 10 TPH at a pressure of 7 kg/cm 2(g) with furnace oil as a fuel. Feed water temperature = 60 C Evaporation ratio = 14. Calorific value of FO = 10000 kcal/kg Specific gravity of FO = 0.95. Enthalpy of steam at 7 kg/cm2(g) = 660 kcal/kg Find out the efficiency of the boiler by direct method and volume of furnace oil tank (in m 3) required for 120 hrs of operation Ans E. R x (hg hf) Effy = --------------------------GCV 14 x (660-60) = ----------------------10000 = 84% (Note: Deduct 1 mark if 60 is not subtracted from 660) Furnace oil requirement = 10 / 14 = 0.714 TPH = 714 kg/hr For 120 hrs of operation, Furnace Oil requirement = 714 x 120 = 85680 kg Oil tank volume = 85680 / (0.950/(1/1000)) = 90.189 m3 OR Effy E. R x (hg hf) = --------------------------GCV 14 x (660-60) = ----------------------10000 = 84% Furnace oil requirement = 10 / 14 = 0.714 TPH = 714 kg/hr = 714 / 0.95 = 751.57 ltr/hr For 120 hrs of operation, oil requirement = 751.57 x 120 = 90189 ltr Oil tank volume = 90189 / 1000 = 90.189 m3 S-2 In a process plant, 30 TPH of steam after pressure reduction with pressure reducing valve to 20 kg/cm2 gets superheated. The temperature of steam is 280oC. The management wants to install a de-superheater to convert superheated steam into saturated steam at 20 kg/cm2 for process use, and its saturation temperature is 210oC. Calculate quantity of water at 30oC to be injected in de-super-heater to get the desired _________________________ Bureau of Energy Efficiency 7 Paper 2 Set A REGULAR saturated steam using the following data. Specific heat of superheated steam = 0.45 kcal/KgoC, Latent heat of steam at 20kg/cm2 Ans = 450 kcal/kg Quantity of heat available above saturation = 30,000 x 0.45 x (280-210) = 9,45,000 kCal/hr Quantity of water required in de-superheater S-3 = Q x{1x (210-30) + 450}= 945000 = 1500 Kg/hr A steam pipe of 100mm diameter is insulated with mineral wool. As a part of energy saving measure, the insulation is upgraded with efficient Calcium silicate insulation. Calculate the percentage reduction in heat loss due to above measure with the following data, Boiler efficiency : 80% Surface temperature with mineral wool : 95 C Surface temperature with calcium silicate : 55 C Ambient temperature : 25 C Ans Heat loss thru non-insulated pipe = [10 + (95 25) / 20] * (95 25) ] = 945 kcal/hr-m2 Heat loss thru insulated pipe = [10 + (55 25) / 20] * (55 25) ] = 345 kcal/hr-m2 % Reduction in heat loss = (945 345)*100 / 945 = 63.5 % S-4 a) List any six losses in a Boiler b) Name two sources of wet flue gas loss in a coal fired boiler _________________________ Bureau of Energy Efficiency 8 Paper 2 Set A REGULAR Ans a) (b) Moisture in air, Moisture in fuel and H2 in fuel. S-5 Ans (a) Calculate the blow down rate for a boiler with an evaporation rate of 5 tons/hr, if the maximum permissible TDS in boiler water is 3000 ppm and with 18 % make up water addition. The feed water TDS is around 400 ppm. (b) Briefly explain temporary hardness and permanent hardness in boiler water Feed water TDS x % Make up Permissible TDS in Boiler FeedwaterT DS a) Blow down (%) = Percentage blow down = 400 x 18/(3000 400) = 2.77 % If boiler evaporation rate is 5000 kg/hr then required blow down rate is: = 5000 x 2.77/100 = 138.5 kg /hr (b) Ref Book-2 :; Page Nos. 45 & 46 Temporary hardness ; It is the hardness that can be removed by boiling. Calcium and magnesium bi carbonate dissolve in water to form an alkaline solution and these salts are called alkaline hardness. They decompose upon heating releasing carbon dioxide and forming a soft sludge which settles out. Permanent hardness: calcium and magnesium sulphates and chlorides, nitrates etc when dissolved in water are chemically neutral and are known as non alkaline hardness. These are called permanent hardness and form hard scale on the boiler surface which are difficult to remove. S-6 List down any five good practices in Furnaces for energy efficiency _________________________ Bureau of Energy Efficiency 9 Paper 2 Set A REGULAR Ans a) Improve capacity Utilisation b) Minimise Excess air c) Minimise heat loss due to radiation, walls and openings d) Adopt Waste heat recovery e) Ensure Complete combustion f) Maintain Furnace in slightly positive pressure g) Adopt Variable frequency drives for fans h) Optimise cycle time. i) Emissivity Coatings Any five of the above can be awarded marks, 1 mark each. S-7 Ans S-8 A cogeneration plant has an electrical output of 5 MW with a back pressure turbine which has a input steam conditions to the turbine as 32 TPH with Enthalpy of 3418 KJ/kg @ 64 ata and 500oC and the exit conditions of steam at the end of the back pressure turbine is 186oC, with enthalpy of 2835.8 KJ/kg. After the process heating, all the condensate @ 730C returns to the boiler. Calculate the Heat to power Ratio and Energy Utilization factor of the process. Fuel consumption of the boiler is 8.2 TPH Coal at 4800 GCV. Heat to power Ratio = 32*((2835.8/4.18)-73)/(5*860) = 4.5 Energy Utilization Factor = ( 32* ((2835.8/4.18)-73) + 5*860))/(8.2*4800) =68.7% Two identical oil fired boilers of capacity 100 TPH are operated in a refinery. They have a full load efficiency of 90%. The part load efficiencies at 70% and 40% load are 75% and 65% respectively. For meeting 140 TPH requirement of steam, which one of the case would you prefer to run and estimate the % savings in the preferred case. The enthalpy of steam generated is 550 Kcal/kg and feed water enters the boiler at 50 C in all the cases. Calorific value of the fuel oil is 10,000 Kcal/hr. Case 1: both the boilers operated at 70 TPH capacity each. Case 2: one at full load capacity and other at 40% capacity. Ans Case-1: Amount of Fuel energy required when both the boilers are run at 70% load i.e, at 70 TPH load Enthalpy change = (550 50) = 500 Kcal/kg = (2 * 70 * 1000 * 500)/ (0.75 * 10000) = 9333 Kg/hr (or) 9.33 Tons/hr Case-2: Amount of Fuel required when one boilers is running at full load at 100 TPH and other at part load of 40 TPH _________________________ Bureau of Energy Efficiency 10 Paper 2 Set A REGULAR Enthalpy change = (550 50) = 500 Kcal/kg = (100 * 1000 * 500) / (0.9*10000) + (40 * 1000 * 500) / (0.65*10000) = 5555 + 3076.9 = 8.63 Tons/hr Fuel required for Case 2 is less & hence Case 2 is preferred % Fuel Savings = (9.33 8.63) / 9.33 x 100 = 7.5 % -------- End of Section - II --------- _________________________ Bureau of Energy Efficiency 11 Paper 2 Set A REGULAR Section - III: LONG DESCRIPTIVE QUESTIONS L-1 Ans A gaseous fuel has volumetric composition as CH4 70 % & C2H6 30%. The Gross Calorific Value of CH4 & C2H6 is 45000 kJ/Nm3 & 70000 kJ/Nm3 respectively. Find out the Net Calorific Value of gaseous fuel in kJ/Nm3. (Latent heat of water vapor 2445 kJ/kg) CH4 + 2O2 = CO2 + 2H2O 1 Nm3 of CH4 + 2 Nm3 of O2 = 1 Nm3 of CO2 + 2 Nm3 of H2O Hence, 0.70 Nm3 of CH4 will generate 0.70 x 2 = 1.4 Nm3 of H2O C2H6 + 3.5 O2 = 2CO2 + 3H2O 1 Nm3 of C2H6 + 3.5 Nm3 of O2 = 2 Nm3 of CO2 + 3 Nm3 of H2O Hence, 0.3 Nm3 of C2H6 will generate 0.30 x 3 = 0.9 Nm3 of H2O Volume of water vapor = 1.4 + 0.9 = 2.3 Nm3/Nm3 of fuel (We know that mass of 22.4 Nm3 of H2O = 18 kg i.e. mass of 1 kMol) Mass of Water vapor, Mm = 2.3 x 18 / 22.4 = 1.85 kg/Nm3 of fuel GCV of gaseous Fuel = (70% x 45000) + (30% x 70000) = 52500 kJ/Nm3 NCV L-2 = GCV (Mm x 2245) = 52500 (1.85 x 2245) = 48346 kJ/Nm3 = 4.13 % A Textile plant has an extensive steam distribution network and the steam condensate is not being recovered. The plant management is planning to recover the condensate and generate flash steam for use as low pressure process steam for fuel savings. The following are the parameters about the system. Condensate quantity Condensate Pressure Cost of steam Annual operating hours Low pressure process steam (flash steam) pressure Sensible heat of condensate at 10 bar Sensible heat of condensate at 2 bar Latent heat of steam at 2 bar Boiler Efficiency GCV of fuel oil Specific Gravity of fuel oil _________________________ Bureau of Energy Efficiency = 1000 kg/hr = 10 bar = Rs 1100/ Ton = 8000 = 2 bar = 188 kCal/kg = 135 kCal/kg = 518 kCal/kg = 82 % = 10,200 kCal/kg = 0.92 12 Paper 2 Set A REGULAR = 95 oC = 35 oC Condensate temperature when recovered Make up water temperature Calculate the Quantity of flash steam which can be recovered, and the annual fuel oil savings on account of condensate recovery Ans a) Flash steam available % = S1- S2/(L2) Where: S1 is the sensible heat of higher pressure condensate. S2 is the sensible heat of the lower pressure condensate L2 is the latent heat of flash steam (at lower pressure). % of Flash steam recoverable = (188 135) / 518 = 10.2 % Quantity of flash steam recovered from condensate = 1000 x 0.102 = 102 kg/hr Condensate available for recovery after flash steam = 1000 102 = 898 kg/hr Heat recovered = 898 x (95 35 ) = 53880 kCal/hr Annual fuel oil saving = 53880 x 8000 / (0.82 x 10200) = 51.2 tons/yr L3 Analyse the diagram as given below and calculate: (i) Boiler Efficiency by direct method (ii) Water Temperature in the condensate tank (iii) Estimate fuel loss due to non-recovery of 2 TPH condensate, assuming the boiler efficiency to be the same Given data: Enthalpy of steam at 10kg/cm2 Furnace Oil consumption Specific Gravity of furnace oil G.C.V. of furnace oil _________________________ Bureau of Energy Efficiency = 665 kCal/kg = 600 liters/hr = 0.89 = 10,000 kCal/kg 13 Paper 2 Set A REGULAR CONDENSATE RETURN QUANTITY = 5 TPH o TEMPERATURE = 95 C MAKE UP WATER QUANTITY = 2 TPH 2 o STEAM FLOW AT 10 KG/CM TEMPERATURE = 28 C CONDENSATE TANK BOILER CAPACITY = 7 TPH FEED WATER TEMPERATURE AT o BOILER INLET = 60 C FEED WATER PUMP ANS Oil Consumption = 600 x 0.89 = 534 kg/hr 1) Boiler Efficiency = 7000 (665 - 60) X 100/ 534 X 10000 = 79.3 % 2) Feed water temperature in condensate tank = [5000 x 95 + 2000 x 28]/ 7000 = 75.85oC = 76 oC 3) Fuel Loss L4 Ans = [ 7000 x (76 60)]/ 10000 x 0.793 = 14 kg/hr A heat exchanger is to be designed to condense the hydrocarbon vapor mixture from a distillation column at the rate of 11.0 kg/sec which is available at its saturation temperature of 120 C. The latent heat of condensation of the hydrocarbon vapor mixture is 450 kJ/kg. The cooling water at 32 C is used in counter-current direction at the rate of 58 kg/sec to condense the vapor mixture. The specific heat of cooling water is 4.18 kJ/kg oC. Determine LMTD and area of the heat exchanger surface if the overall heat transfer coefficient is 600 J/m2s C. Heat removal rate from hydrocarbon vapour mixture = heat gain rate in cooling water Qxh = M * cp* (T2-T1) 11.0 x 450 = 58 x 4.18 x (T2 32) T2 = 52.4 C Water leaves the exchanger at 52.4 C LMTD = (120-32)-(120-52.4)/ln(120-32)/(120-52.4) LMTD of counter flow pattern = 77.4 C Q = m*Cp* deltaT = U * A * LMTD 58 * 4.18 * (52.4 32) * 1000 = 600 * A * 77.4 A = 106.5 m2 _________________________ Bureau of Energy Efficiency 14 Paper 2 Set A REGULAR Area of the heat exchanger surface is 106.5 m2 L-5 a) b) Ans Explain the process of Mechanical de-aeration and chemical de-aeration How does an energy auditor assess the performance of steam trap during energy audit? a) Ref page no 47 b) _________________________ Bureau of Energy Efficiency 15 REGULAR Paper 2 Set A The three performance test methods of steam traps are 1. Visual testing, 2. Sound Testing 3. Temperature testing Ref page no 95 L-6 Answer the followings: (a) Ans a) b) Explain why dry saturated steam is preferred over wet or superheated steam for industrial process heating. (b) Why should one use dry saturated steam at the lowest possible pressure for indirect steam heating? (c) What are the two major advantages of direct injection of steam for heating of liquid? (d) Why drain points are required in a steam system? (e) What is flash steam? Dry saturated steam is the preferred choice because: Wet steam has a lower heat content than dry steam. Superheated steam gives up heat at a slower rate than saturated steam. Dry steam alone condenses quickly, thereby providing a higher heat transfer rate. The latent heat of steam increases with reduction of steam pressure and it is only the latent heat that is transferred during indirect heating applications. c) No condensate recovery system is necessary The heating is quick, and the sensible heat in the steam is also used up along with the latent heat, making the system thermally more efficient. d) The drain points help in removing water in pipes due to condensation of steam. e) Flash steam is produced when condensate at a high pressure is released to a lower pressure. . . End of Section III .. . _________________________ Bureau of Energy Efficiency 16

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