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  ICSE Class X Prelims 2025 : Biology (Vibgyor High School, Airoli, Navi Mumbai)
  	14th day respaper202409

  ICSE Class X Prelims 2024 : Chemistry (Hiranandani Foundation School (HFS), Thane)
  	Dehydrohalogenation can also be given. rishitmathur

  + 12 more by rishitmathur  

  ICSE Class X Prelims 2025 : Chemistry (Kohinoor International School (KIS), Mumbai)
  	a) colourless rishitmathur

  ICSE Class X Prelims 2025 : Chemistry (Kohinoor International School (KIS), Mumbai)
  	a) increases rishitmathur

  ICSE Class X Prelims 2025 : Chemistry (Kohinoor International School (KIS), Mumbai)
  	c rishitmathur

  ICSE Class X Prelims 2025 : Chemistry (Kohinoor International School (KIS), Mumbai)
  	X rishitmathur

  ICSE Class X Prelims 2025 : Chemistry (Kohinoor International School (KIS), Mumbai)
  	c)  since atoms can also achieve duplet configuration rishitmathur

  ICSE Class X Prelims 2025 : Computer Applications (St. Augustine's Day School, Kolkata)
  	b rishitmathur

  ICSE Class X Prelims 2025 : Computer Applications (St. Augustine's Day School, Kolkata)
  	b rishitmathur

  ICSE Class X Prelims 2025 : Computer Applications (St. Augustine's Day School, Kolkata)
  	d rishitmathur

  ICSE Class X Prelims 2025 : Computer Applications (St. Augustine's Day School, Kolkata)
  	d rishitmathur

  ICSE Class X Prelims 2025 : Computer Applications (St. Augustine's Day School, Kolkata)
  	b rishitmathur

  ICSE Class X Prelims 2025 : Computer Applications (St. Augustine's Day School, Kolkata)
  	d rishitmathur

  ICSE Class X Prelims 2025 : Computer Applications (St. Augustine's Day School, Kolkata)
  	a rishitmathur

  ICSE Class X Prelims 2025 : Chemistry 2nd prelims (Smt. Sulochanadevi Singhania School, Thane)

  (a) 2,2,3-Trimethylbut-3-ene The compound shown in the image is named according to IUPAC nomenclature as follows: - The longest carbon chain contains 4 carbon atoms, so the root name is "but". - There is a double bond, so we add the suffix "-ene". - The double bond is at the 3rd carbon, so we insert "3-" before "ene". - There are three methyl groups: two at the 2nd carbon and one at the 3rd carbon. - We list the substituents in alphabetical order, so "2,2,3-trimethyl". (b) 2-Methylpropanal For the second compound (CH3-CH(CH3)-CHO): - The longest carbon chain containing the aldehyde group has 3 carbons, so the root name is "propan". - The aldehyde group (-CHO) is indicated by the suffix "-al". - There is a methyl group (-CH3) attached to the 2nd carbon. - Combining these gives us "2-methylpropanal". garviv

  + 5 more by garviv  

  ICSE Class X Prelims 2025 : Chemistry 2nd prelims (Smt. Sulochanadevi Singhania School, Thane)

  (a) Homologous series (b) Lone pair of electrons (c) Ores (d) Electrolysis (e) Electron affinity Reasoning: (a) A homologous series is a group of organic compounds with similar chemical properties and structures, differing by a CH2 group between successive members. (b) Lone pairs are electrons in an atom that are not involved in bonding and remain localized on the atom. (c) Ores are naturally occurring rock formations containing minerals from which metals can be extracted economically. (d) Electrolysis is a process that uses electricity to separate ions in an ionic compound, often used in purification or extraction of elements. (e) Electron affinity is the energy released when a gaseous atom accepts an electron to form a negative ion (anion). It's an important concept in understanding chemical bonding and reactivity. garviv

  ICSE Class X Prelims 2025 : Chemistry 2nd prelims (Smt. Sulochanadevi Singhania School, Thane)

  (a) First, let's calculate the molar masses: CaCO3: 40 + 12 + (16 × 3) = 100 g/mol CaCl2: 40 + (35.5 × 2) = 111 g/mol From the equation, 1 mole of CaCO3 produces 1 mole of CaCl2. 10g of CaCO3 = 10/100 = 0.1 mole 0.1 mole of CaCl2 will be produced Mass of CaCl2 = 0.1 × 111 = 11.1g For CO2: 0.1 mole of CO2 will be produced Volume at STP = 0.1 × 22.4 L = 2.24 L (b) According to Avogadro's law, equal volumes of gases under the same conditions of temperature and pressure contain an equal number of molecules. If 150 cc of gas A contains X molecules, then 150 cc of gas B will also contain X molecules. For 450 cc of gas B: 450/150 = 3 So, 450 cc of gas B will contain 3X molecules. garviv

  ICSE Class X Prelims 2025 : Chemistry 2nd prelims (Smt. Sulochanadevi Singhania School, Thane)

  (a) low Reasoning: Acetic acid is a weak acid, while dilute sulphuric acid is a strong acid. Weak acids dissociate less in water, producing fewer H+ ions compared to strong acids. Therefore, acetic acid has a lower concentration of H+ ions, resulting in a higher pH than dilute sulphuric acid. (b) only H2 Reasoning: - Solution X with pH 1 is strongly acidic. When zinc reacts with an acid, it produces hydrogen gas: Zn + 2H+ → Zn2+ + H2 - Solution Y with pH 14 is strongly basic (alkaline). Zinc can react with strong bases in the presence of water to produce hydrogen gas: Zn + 2OH- + 2H2O → Zn(OH)4^2- + H2 In both cases, only hydrogen gas (H2) is evolved. O2 and Cl2 are not produced in these reactions. garviv

  ICSE Class X Prelims 2025 : Chemistry 2nd prelims (Smt. Sulochanadevi Singhania School, Thane)

  (a) When methyl orange is added to a mixture of ammonium hydroxide and dilute HCl, the solution will turn yellow. This is because the mixture becomes slightly basic due to the presence of excess ammonium hydroxide, and methyl orange is yellow in basic solutions. (b) When sodium hydroxide is added to lead nitrate solution: - In small amount: A white precipitate of lead hydroxide forms. - In excess: The white precipitate dissolves, forming a clear solution of sodium plumbate. (c) When ammonium nitrate is strongly heated, it decomposes, producing nitrous oxide gas and water vapor. The observation would be the formation of bubbles and possibly a slight mist in the test tube. (d) When neutral FeCl3 is added to acetic acid solution, the color of the solution changes from pale yellow to reddish-brown due to the formation of iron(III) acetate complex. (e) When copper sulphide reacts with dilute hydrochloric acid, hydrogen sulphide gas is evolved, which can be recognized by its characteristic rotten egg smell. The solution may also turn slightly greenish due to the formation of copper(II) chloride. garviv

  ICSE Class X Prelims 2025 : Chemistry 2nd prelims (Smt. Sulochanadevi Singhania School, Thane)

  The compound 'Q' formed when magnesium ribbon reacts with dilute HCl is magnesium chloride (MgCl2). The electron dot diagram for MgCl2 is: Mg : :Cl : · : Cl : In this diagram, magnesium (Mg) loses two electrons, which are gained by two chlorine (Cl) atoms. The dots represent the outer shell electrons, with each chlorine having 8 electrons (octet) and magnesium having none in its outer shell after forming the ionic bond. garviv

  ICSE Class X Prelims 2025 : Economic Applications (Vivekananda Mission School (VMS), Joka, Kolkata)

  d) Both (b) and (c) Reasoning: In the long run, under perfect competition and monopolistic competition, firms earn only normal profits. This is because: 1. Perfect competition: In this market structure, there are many small firms selling identical products. Free entry and exit of firms ensures that any economic profits are competed away in the long run, leaving firms with only normal profits. 2. Monopolistic competition: This market form has many firms selling differentiated products. While firms may earn economic profits in the short run, the long-run equilibrium results in firms earning only normal profits due to free entry and exit. Normal profit is the minimum level of profit required to keep a firm in business. It's considered a cost of production rather than an economic profit. Both perfect competition and monopolistic competition converge to this state in the long run, making option (d) the correct answer. vaishalisawant05

  + 1 more by vaishalisawant05  

  ICSE Class X Prelims 2025 : Economic Applications (Vivekananda Mission School (VMS), Joka, Kolkata)

  b) False Reasoning: While traders do often use current accounts, it's not accurate to say that current accounts are mostly used by traders. Current accounts are widely used by individuals, businesses, and organizations of various types. They are designed for frequent transactions and daily financial operations, making them suitable for a broad range of users, including: 1. Individual consumers for everyday banking needs 2. Small and large businesses for managing cash flow 3. Non-profit organizations 4. Government entities 5. Professionals and service providers Traders are just one subset of the diverse group of users who benefit from current accounts. Therefore, the statement that current accounts are mostly used by traders is false, as it oversimplifies and misrepresents the broad user base of these accounts. vaishalisawant05

  ICSE Class X Prelims 2024 : Computer Applications (Bombay Scottish School, Mahim, Mumbai)
  	(c) private sea_

  ICSE Class X Prelims 2024 : Computer Applications (Bombay Scottish School, Mahim, Mumbai)
  	D wamia

  ICSE Class X Prelims 2025 : Computer Applications (St. Xavier's Institution (SXI), Ruiya)
  	(b)- (3)(4)(1)(2) radhikaprabhu

  + 3 more by radhikaprabhu  

  ICSE Class X Prelims 2025 : Computer Applications (St. Xavier's Institution (SXI), Ruiya)
  	(d) - both a and c radhikaprabhu

  ICSE Class X Prelims 2025 : Computer Applications (St. Xavier's Institution (SXI), Ruiya)
  	(d) - Math.round(n) radhikaprabhu

  ICSE Class X Prelims 2025 : Physics (Vasant Vihar High School (VVHS) & Junior College, Thane)
  	(b) +2.5D radhikaprabhu

  ICSE Class X Prelims 2025 : Physics (Smt. Sulochanadevi Singhania School, Thane)
  	Let the e.m.f. of the cell is E and its internal resistance is r. E R+r and From I = 0.6 = E/(2 + r) 0.3 = E/(8 + r) E = 0.6(2 + r) = 1.2 + 0.6r and E = 0.3(8 + r) = 2.4 + 0.3r Thus, 1.2 + 0.6r = 2.4 + 0.3r or 0.6r - 0.3r = 2.4 - 1.2 Or 0.3r = 1.2 or r = 1.2/0.3 = 4Omega and E = 1.2 + 0.6 * 4 = 1.2 + 2.4 = 3.6V anilkumarms

  + 15 more by anilkumarms  

  ICSE Class X Prelims 2025 : Physics (Smt. Sulochanadevi Singhania School, Thane)
  	The nuclear waste obtained from laboratories, hospitals, scientific establishments or power plants must be first kept in thick casks and then they should buried in the specially designed deep underground stores. The stores should be make quite far from the populated area and the casks should also be buried and scaled in useless mines after storing if. anilkumarms

  ICSE Class X Prelims 2025 : Physics (Smt. Sulochanadevi Singhania School, Thane)
  	a anilkumarms

  ICSE Class X Prelims 2025 : Physics (Shishuvan English Medium School, Mumbai)
  	D anilkumarms

  ICSE Class X Prelims 2025 : Physics (Shishuvan English Medium School, Mumbai)
  	C anilkumarms

  ICSE Class X Prelims 2025 : Physics (Smt. Sulochanadevi Singhania School, Thane)
  	answer a I=v/R Here, $5\text{V}$ R =10 ΩR = 10\,\Omega I  =  5 V10 Ω  =  0.5 A.I \;=\; \frac{5\,\text{V}}{10\,\Omega} \;=\; 0.5\,\text{A}. anilkumarms

  ICSE Class X Prelims 2025 : Physics (Smt. Sulochanadevi Singhania School, Thane)
  	b anilkumarms

  ICSE Class X Prelims 2025 : Physics (Smt. Sulochanadevi Singhania School, Thane)
  	a anilkumarms

  ICSE Class X Prelims 2025 : Physics (Smt. Sulochanadevi Singhania School, Thane)
  	c anilkumarms

  ICSE Class X Prelims 2025 : Physics (Smt. Sulochanadevi Singhania School, Thane)
  	c anilkumarms

  ICSE Class X Prelims 2025 : Physics (Smt. Sulochanadevi Singhania School, Thane)
  	b anilkumarms

  ICSE Class X Prelims 2025 : Physics (Smt. Sulochanadevi Singhania School, Thane)
  	a anilkumarms

  ICSE Class X Prelims 2025 : Physics (Smt. Sulochanadevi Singhania School, Thane)
  	b anilkumarms

  ICSE Class X Prelims 2025 : Physics (Smt. Sulochanadevi Singhania School, Thane)
  	c anilkumarms

  ICSE Class X Prelims 2025 : Physics (Smt. Sulochanadevi Singhania School, Thane)
  	b anilkumarms

  ICSE Class X Prelims 2025 : Physics (Smt. Sulochanadevi Singhania School, Thane)
  	b anilkumarms

  ICSE Class X Prelims 2025 : Computer Applications (The Bishops Co - Ed. School, Kalyaninagar, Pune)
  	a. 0.0d b. \n0000 mkmk

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